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A 500-kg communications satellite is in a circular geosynchronous orbit and completes one revolution about the earth in 23 h and 56 min at an altitude of 35 800 km above the surface of the earth. Knowing that the radius of the earth is 6370 km, determine the kinetic energy of the satellite.

Short Answer

Expert verified
The kinetic energy of the satellite is approximately \( 2.36 \times 10^9 \ J \).

Step by step solution

01

Understand the Problem

We need to find the kinetic energy of a satellite in a circular orbit. The satellite's mass is given, and we have its orbital period and altitude. We'll use these values to find the orbital speed and then the kinetic energy.
02

Calculate Orbital Radius

The altitude of the satellite is 35,800 km above the Earth's surface. The radius of the Earth is 6,370 km. Therefore, the orbital radius \( r \) is the sum of the Earth's radius and the altitude, which is \( r = 6370 \ km + 35800 \ km = 42170 \ km \).
03

Convert Orbital Radius to Meters

Convert the orbital radius from kilometers to meters by multiplying by 1,000. Thus, \( r = 42170 \ times 10^3 \ m = 42170000 \ m \).
04

Calculate Orbital Speed

The orbital speed \( v \) can be found using the formula: \( v = \frac{2\pi r}{T} \), where \( T \) is the orbital period in seconds. First, convert the period to seconds: \( T = 23 \ times 3600 + 56 \ times 60 = 86160 \ s \). Then, \( v = \frac{2 \pi \times 42170000}{86160} \approx 3074 \ m/s \).
05

Calculate Kinetic Energy

The kinetic energy \( KE \) of the satellite can be found using the formula: \( KE = \frac{1}{2}mv^2 \), where \( m = 500 \ kg \) and \( v = 3074 \ m/s \). So, \( KE = 0.5 \times 500 \times 3074^2 \approx 2.36 \times 10^{9} \ J \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Energy
Kinetic energy is the energy that an object possesses due to its motion. It is a crucial concept in understanding how satellites move in their orbits. The formula for kinetic energy is given by:
  • \( KE = \frac{1}{2}mv^2 \)
where \( m \) is the mass of the object and \( v \) is its velocity.

In our exercise, we calculated the kinetic energy of a 500-kg satellite. Once the velocity was determined from its orbit’s characteristics, we applied this formula to find that the satellite's kinetic energy is approximately \( 2.36 \times 10^{9} \) Joules.

This energy keeps the satellite moving in its orbit, counteracting gravitational forces pulling it towards Earth. The faster the satellite moves, the higher its kinetic energy, which prevents it from falling due to gravitational attraction.
Satellite Orbits
Satellite orbits refer to the paths that satellites follow as they move around a planet. These orbits can be circular or elliptical, and their shape and duration depend on the satellite's speed and altitude.

In a circular orbit, the satellite maintains a constant distance from the Earth's surface, like our example of a geosynchronous orbit. Factors affecting satellite orbit include:
  • The gravitational pull from the Earth
  • The speed at which the satellite travels
  • The height above Earth's surface
Satellites in circular geosynchronous orbit have an altitude that matches the Earth's rotation, allowing them to remain over the same point. The consistent position makes them ideal for communication purposes since they provide steady coverage of a particular Earth region.
Circular Motion
Circular motion describes the movement of an object along the circumference of a circle. This type of motion is crucial in understanding how satellites like the one in our exercise, maintain their paths around the Earth.

In circular motion, several forces keep the satellite in its orbit:
  • Centripetal force that acts towards the center of the circular path, in this case, Earth's center.
  • Gravitational force acting as the attractive force that provides the required centripetal force.
These forces ensure that the satellite moves at a constant speed and distance from the Earth. For geosynchronous satellites, this means one revolution every day, synchronizing with the Earth's rotation.
Geosynchronous Orbit
A geosynchronous orbit is a specific type of orbit that allows a satellite to move in sync with the Earth’s rotation. As a result, the satellite appears in a fixed position relative to a point on Earth’s surface.

Such orbits are achieved by placing the satellite at a specific altitude where its orbital period matches the Earth’s rotational period. For example, the communications satellite in the exercise achieves this by orbiting at approximately 35,800 km above the Earth's surface.

Geosynchronous orbits are ideal for communications and weather observation satellites. They provide continuous coverage to specific geographic areas, eliminating the need for multiple ground tracking stations. This fixed positioning ensures reliable signals and continuous data transmission.

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