/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 2 A 1 -lb stone is dropped down th... [FREE SOLUTION] | 91Ó°ÊÓ

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A 1 -lb stone is dropped down the "bottomless pit" at Carlsbad Caverns and strikes the ground with a speed of 95 fts. Neglecting air resistance, \((a)\) determine the kinetic energy of the stone as it strikes the ground and the height \(h\) from which it was dropped. (b) Solve part \(a\) assuming that the same stone is dropped down a hole on the moon. (Acceleration of gravity on the moon \(=5.31 \mathrm{ft}( \left\mathrm{s}^{2}\).) \right.

Short Answer

Expert verified
(a) Earth: KE = 140.072 ft-lbs, height = 140.072 feet. (b) Moon: KE = 140.072 ft-lbs, height = 849.58 feet.

Step by step solution

01

Convert Weight to Mass

The stone weighs 1 lb, but to use the formula for kinetic energy, we need the mass. The relationship between weight (W) and mass (m) is given by the equation: \( W = m \cdot g \), where \( g \) is the acceleration due to gravity (32.2 ft/s² on Earth). Thus, the mass, \( m \), is \( \frac{1}{32.2} \approx 0.0311 \) slugs.
02

Calculate Kinetic Energy on Earth

The kinetic energy (KE) of an object is given by the formula: \( KE = \frac{1}{2} m v^2 \). Substituting the values, \( m = 0.0311 \) slugs and \( v = 95 \) ft/s, we have: \( KE = \frac{1}{2} \times 0.0311 \times (95)^2 = 140.072 \) ft-lbs.
03

Determine the Height on Earth

Using the principle of conservation of energy, the potential energy at height \( h \) must equal the kinetic energy at impact: \( mgh = KE \). Solving for \( h \), we get: \( h = \frac{KE}{mg} = \frac{140.072}{1} \approx 140.072 \) feet (since \( mg = 1 \) lb by definition on Earth).
04

Calculate Kinetic Energy on the Moon

On the moon, the same stone's mass is \( 0.0311 \) slugs, and the velocity upon impact is still 95 ft/s (as velocity is not impacted by gravity alone). Hence, the kinetic energy is the same on the moon as on Earth: \( 140.072 \) ft-lbs.
05

Determine the Height on the Moon

On the moon, the relation of potential energy is \( mg_{moon} h = KE \). Here, \( g_{moon} = 5.31 \) ft/s², thus \( mg_{moon} = 1 \times \frac{5.31}{32.2} = 0.1649 \) lb. Solving for \( h \), we have: \( h = \frac{KE}{mg_{moon}} = \frac{140.072}{0.1649} \approx 849.58 \) feet.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conservation of Energy
Conservation of Energy is a fundamental concept in physics. It tells us that the total energy in a closed system remains constant, meaning energy can neither be created nor destroyed. Instead, energy can only transform from one type to another. In our problem with the stone, we consider the conversion of potential energy into kinetic energy.

This principle is expressed mathematically as:
  • Potential Energy (PE) at height = Kinetic Energy (KE) at impact
  • Mathematically: \[ mgh = \frac{1}{2}mv^2 \]
When a stone is dropped from a height, it loses potential energy while gaining kinetic energy. By the time it hits the ground, all the potential energy has become kinetic energy. This method allows us to calculate the height from which the stone was dropped based solely on its speed at impact and its kinetic energy.

Under these conditions, whether on Earth or the Moon, this conversion of energy explains why the stone will have a consistent speed upon reaching the ground given no initial upward movement or air resistance.
Acceleration due to Gravity
Acceleration due to gravity (\( g \)) is the rate at which an object accelerates when it is in free fall solely under the influence of gravity. It determines how fast something speeds up or slows down due to the gravitational pull of a larger body like Earth or the Moon.

On Earth, this acceleration due to gravity is approximately \( 32.2 \text{ ft/s}^2 \), leading to a constant increase in velocity as an object falls. This gravitational acceleration is part of why the stone gains speed as it falls.

There's a significant difference when we move to the Moon, where \( g \) is only \( 5.31 \text{ ft/s}^2 \). Thus, objects accelerate more slowly when falling on the Moon compared to on Earth. Importantly, though the acceleration due to gravity is different, the kinetic energy of the stone as it strikes the ground remains the same because it depends on velocity and not on the journey of falling.

Understanding gravity's effect is essential in explaining the differences in height calculations when considering locations in different gravitational fields, as was shown when we calculated the height from which the stone was dropped.
Potential Energy
Potential Energy (PE) refers to the stored energy in an object due to its position relative to a specific force, often gravity. This is the energy an object might have stored due to its elevated position above a point where it would have less potential energy if it were nearer to the ground.

The formula for potential energy is: \[ PE = mgh \]
  • \( m \) stands for the mass of the object.
  • \( g \) represents the gravitational pull.
  • \( h \) is the height above the ground.
As demonstrated in the exercise, this stored energy transforms into kinetic energy as the stone falls. By the conservation of energy, the height 'h' from where the stone was dropped can be determined knowing the potential energy and the specific gravitational acceleration at different locations.

For instance, on Earth with a \( g \) of \( 32.2 \text{ ft/s}^2 \), the stone dropped from 140.072 feet equates its potential energy to its kinetic energy at impact. This fundamental understanding of potential energy as an energy form that is converted as objects move through a gravitational field is essential in many areas of physics and engineering.

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