/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 169 A boy located at point \(A\) hal... [FREE SOLUTION] | 91Ó°ÊÓ

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A boy located at point \(A\) halfway between the center \(\mathrm{O}\) of asemicircular wall and the wall itself throws a ball at the wall in adirection forming an angle of \(45^{\circ}\) with \(O A .\) Knowing that after hitting the wall the ball rebounds in a direction parallel to \(O A,\) determine the coefficient of restitution between the ball and the wall.

Short Answer

Expert verified
The coefficient of restitution is 0.

Step by step solution

01

Understand the Problem

The problem involves a boy throwing a ball at a wall from point \(A\). The ball hits the wall at an angle of \(45^{\circ}\) and rebounds parallel to the line \(OA\). The task is to find the coefficient of restitution, which measures how much kinetic energy is conserved in the collision.
02

Consider the Geometry and Angles

Point \(A\) is halfway between the center of the semicircular wall \(O\) and the wall itself. The ball is thrown such that it hits the wall at an angle of \(45^{\circ}\). Upon rebound, the ball travels parallel to \(OA\), which means the angle between the rebound path and the wall is \(90^{\circ}\).
03

Use the Definition of Coefficient of Restitution

The coefficient of restitution \(e\) is defined as the ratio of the relative speed after the collision to the relative speed before the collision. Since the ball rebounds at \(90^{\circ}\) to the wall, the normal component of the velocity after the collision is zero.
04

Analyze the Velocity Components

Before hitting the wall, the velocity can be split into two components: normal and parallel to the wall. The normal component forms an angle of \(45^{\circ}\) with the wall. Thus, if \(v\) is the initial speed of the ball, the normal component \(v_n = v \sin(45^{\circ}) = \frac{v}{\sqrt{2}}\). After the collision, the normal component is zero.
05

Calculate the Coefficient of Restitution

Since the normal component of the velocity after the collision is zero, the coefficient of restitution \(e = \frac{0}{v_n} = 0\). This suggests that all the normal component of velocity is lost during the collision.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

kinematic analysis
In our problem, kinematic analysis helps us understand the motion of the ball both before and after the collision. By breaking down the velocity of the ball into components, we can visualize how each affects the outcome of the collision.
Before the ball hits the wall, it travels at a certain velocity. This velocity has two components:
  • Normal to the wall (perpendicular).
  • Parallel to the wall.
Since the ball is thrown at a 45-degree angle to the line OA, both components play significant roles. The angle of 45 degrees indicates that these components are equal in magnitude.
The kinematic analysis becomes crucial when observing the sudden stop of the normal velocity component. This change is indicative of energy loss through the collision. Each component can be calculated using trigonometry, which allows us to further unravel the behavior of the ball during its journey.
collision mechanics
Collision mechanics deal with what happens during the impact between two bodies—in this case, a ball and the wall. Here, understanding the nature of the impact is vital for determining the coefficient of restitution.
During the collision, mechanical energy is partially lost, especially in real-world scenarios. The coefficient of restitution (e) quantifies the elasticity of the collision:
  • If \(e = 1\), the collision is perfectly elastic, meaning no kinetic energy is lost.
  • If \(e = 0\), the collision is perfectly inelastic, which means the bodies do not rebound apart.
In our problem, since the ball rebounds such that it travels parallel to OA, it signifies that all energy in the normal direction is lost, representing an inelastic collision with \(e = 0\). Understanding this ratio provides insight into the dynamics occurring during these impactful events.
angle of incidence
The angle of incidence is a key concept to understanding the motion of the ball as it approaches and makes contact with the wall. It directly influences the behavior of the ball upon rebound.
This angle—between the trajectory of the ball and a line perpendicular to the surface—determines how the velocity components are distributed. In the given problem, this angle of 45 degrees (an acute angle) results in equal contributions from the normal and tangential velocity components at the point of contact.
The angle of incidence not only affects how the ball hits the wall but also defines the pathway the ball takes after bouncing off. Since the ball rebounds at 90 degrees to the surface, it implies the absence of a normal component post-collision. Hence, the angle of incidence governs how momentum and energy are handled in such scenarios and is pivotal to predicting post-impact trajectories.

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Most popular questions from this chapter

A test machine that kicks soccer balls has a 5 -lb simulated foot attached to the end of a 6 -ft long pendulum arm of negligible mass. Knowing that the arm is released from the horizontal position and that the coefficient of restitution between the foot and the 1 -lb ball is \(0.8,\) determine the exit velocity of the ball \((a)\) if the ball is stationary, \((b)\) if the ball is struck when it is rolling towards the foot with a velocity of \(10 \mathrm{ft} / \mathrm{s}\).

A 3-kg block rests on top of a 2-kg block supported by, but not attached to, a spring of constant 40 N/m. The upper block is suddenly removed. Determine (a) the maximum speed reached by the 2-kg block, (b) the maximum height reached by the 2-kg block.

A roller coaster starts from rest at \(A,\) rolls down the track to \(B\), describes a circular loop of 40 -ft diameter, and moves up and down past point \(E .\) Knowing that \(h=60 \mathrm{ft}\) and assuming no energy loss due to friction, determine \((a)\) the force exerted by his seat on a 160 -lb rider at \(B\) and \(D,(b)\) the minimum value of the radius of curvature at \(E\) if the roller coaster is not to leave the track at that point.

The coefficient of restitution is 0.9 between the two 60 -mm-diameter billiard balls \(A\) and \(B .\) Ball \(A\) is moving in the direction shown with a velocity of \(1 \mathrm{m} / \mathrm{s}\) when it strikes ball \(B\), which is at rest. Knowing that after impact \(B\) is moving in the \(x\) direction, determine (a) the angle \(\theta,(b)\) the velocity of \(B\) after impact.

A 1 -lb stone is dropped down the "bottomless pit" at Carlsbad Caverns and strikes the ground with a speed of 95 fts. Neglecting air resistance, \((a)\) determine the kinetic energy of the stone as it strikes the ground and the height \(h\) from which it was dropped. (b) Solve part \(a\) assuming that the same stone is dropped down a hole on the moon. (Acceleration of gravity on the moon \(=5.31 \mathrm{ft}( \left\mathrm{s}^{2}\).) \right.

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