/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 169 A boy located at point \(A\) hal... [FREE SOLUTION] | 91Ó°ÊÓ

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A boy located at point \(A\) halfway between the center \(\mathrm{O}\) of asemicircular wall and the wall itself throws a ball at the wall in adirection forming an angle of \(45^{\circ}\) with \(O A .\) Knowing that after hitting the wall the ball rebounds in a direction parallel to \(O A,\) determine the coefficient of restitution between the ball and the wall.

Short Answer

Expert verified
The coefficient of restitution is 0.

Step by step solution

01

Understand the Problem

The problem involves a boy throwing a ball at a wall from point \(A\). The ball hits the wall at an angle of \(45^{\circ}\) and rebounds parallel to the line \(OA\). The task is to find the coefficient of restitution, which measures how much kinetic energy is conserved in the collision.
02

Consider the Geometry and Angles

Point \(A\) is halfway between the center of the semicircular wall \(O\) and the wall itself. The ball is thrown such that it hits the wall at an angle of \(45^{\circ}\). Upon rebound, the ball travels parallel to \(OA\), which means the angle between the rebound path and the wall is \(90^{\circ}\).
03

Use the Definition of Coefficient of Restitution

The coefficient of restitution \(e\) is defined as the ratio of the relative speed after the collision to the relative speed before the collision. Since the ball rebounds at \(90^{\circ}\) to the wall, the normal component of the velocity after the collision is zero.
04

Analyze the Velocity Components

Before hitting the wall, the velocity can be split into two components: normal and parallel to the wall. The normal component forms an angle of \(45^{\circ}\) with the wall. Thus, if \(v\) is the initial speed of the ball, the normal component \(v_n = v \sin(45^{\circ}) = \frac{v}{\sqrt{2}}\). After the collision, the normal component is zero.
05

Calculate the Coefficient of Restitution

Since the normal component of the velocity after the collision is zero, the coefficient of restitution \(e = \frac{0}{v_n} = 0\). This suggests that all the normal component of velocity is lost during the collision.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

kinematic analysis
In our problem, kinematic analysis helps us understand the motion of the ball both before and after the collision. By breaking down the velocity of the ball into components, we can visualize how each affects the outcome of the collision.
Before the ball hits the wall, it travels at a certain velocity. This velocity has two components:
  • Normal to the wall (perpendicular).
  • Parallel to the wall.
Since the ball is thrown at a 45-degree angle to the line OA, both components play significant roles. The angle of 45 degrees indicates that these components are equal in magnitude.
The kinematic analysis becomes crucial when observing the sudden stop of the normal velocity component. This change is indicative of energy loss through the collision. Each component can be calculated using trigonometry, which allows us to further unravel the behavior of the ball during its journey.
collision mechanics
Collision mechanics deal with what happens during the impact between two bodies—in this case, a ball and the wall. Here, understanding the nature of the impact is vital for determining the coefficient of restitution.
During the collision, mechanical energy is partially lost, especially in real-world scenarios. The coefficient of restitution (e) quantifies the elasticity of the collision:
  • If \(e = 1\), the collision is perfectly elastic, meaning no kinetic energy is lost.
  • If \(e = 0\), the collision is perfectly inelastic, which means the bodies do not rebound apart.
In our problem, since the ball rebounds such that it travels parallel to OA, it signifies that all energy in the normal direction is lost, representing an inelastic collision with \(e = 0\). Understanding this ratio provides insight into the dynamics occurring during these impactful events.
angle of incidence
The angle of incidence is a key concept to understanding the motion of the ball as it approaches and makes contact with the wall. It directly influences the behavior of the ball upon rebound.
This angle—between the trajectory of the ball and a line perpendicular to the surface—determines how the velocity components are distributed. In the given problem, this angle of 45 degrees (an acute angle) results in equal contributions from the normal and tangential velocity components at the point of contact.
The angle of incidence not only affects how the ball hits the wall but also defines the pathway the ball takes after bouncing off. Since the ball rebounds at 90 degrees to the surface, it implies the absence of a normal component post-collision. Hence, the angle of incidence governs how momentum and energy are handled in such scenarios and is pivotal to predicting post-impact trajectories.

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Most popular questions from this chapter

A baseball player hits a 5.1 -oz baseball with an initial velocity of \(140 \mathrm{ft} / \mathrm{s}\) at an angle of \(40^{\circ}\) with the horizontal as shown. Determine \((a)\) the kinetic energy of the ball immediately after it is hit, \((b)\) the kinetic energy of the ball when it reaches its maximum height, maximum height above the ground reached by the ball.

Rockfalls can cause major damage to roads and infrastructure. To design mitigation bridges and barriers, engineers use the coefficient of restitution to model the behavior of the rocks. Rock \(A\) falls a distance of \(20 \mathrm{m}\) before striking an incline with a slope of \(\alpha=40^{\circ}\). Knowing that the coefficient of restitution between rock \(A\) and the incline is \(0.2,\) determine the velocity of the rock after the impact.

A 35 000-Mg ocean liner has an initial velocity of 4 km/h. Neglecting the frictional resistance of the water, determine the time required to bring the liner to rest by using a single tugboat that exerts a constant force of 150 kN.

Steep safety ramps are built beside mountain highways to enable vehicles with defective brakes to stop. A 10 -ton truck enters a \(15^{\circ}\) ramp at a high speed \(v_{0}=108 \mathrm{ft} / \mathrm{s}\) and travels for \(6 \mathrm{s}\) before its speed is reduced to \(36 \mathrm{ft} / \mathrm{s}\). Assuming constant deceleration, determine \((a)\) the magnitude of the braking force, \((b)\) the additional time required for the truck to stop. Neglect air resistance and rolling resistance.

Prove that a force \(F(x, y, z)\) is conservative if, and only if, the following relations are satisfied: $$\frac{\partial F_{x}}{\partial y}=\frac{\partial F_{y}}{\partial x} \quad \frac{\partial F_{y}}{\partial z}=\frac{\partial F_{z}}{\partial y} \quad \frac{\partial F_{z}}{\partial x}=\frac{\partial F_{x}}{\partial z}$$

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