/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 86 A space vehicle is in a circular... [FREE SOLUTION] | 91Ó°ÊÓ

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A space vehicle is in a circular orbit of \(2200-\mathrm{km}\) radius around the moon. To transfer it to a smaller circular orbit of \(2080-\mathrm{km}\) radius, the vehicle is first placed on an elliptic path \(A B\) by reducing its speed by \(26.3 \mathrm{m} / \mathrm{s}\) as it passes through \(A .\) Knowing that the mass of the moon is \(73.49 \times 10^{21} \mathrm{kg}\), determine (a) the speed of the vehich as it approaches \(B\) on the elliptic path, \((b)\) the amount by which its speed should be reduced as it approaches \(B\) to insert it into the smaller circular orbit.

Short Answer

Expert verified
The speed at B is 1629 m/s, and the speed reduction required is 1.3 m/s.

Step by step solution

01

Determine initial orbital velocity at A

The speed of a space vehicle in a circular orbit is determined using the formula \( v = \sqrt{\frac{GM}{r}} \), where \( G \) is the gravitational constant \( 6.674 \times 10^{-11} \, \mathrm{Nm}^2/\mathrm{kg}^2 \), \( M \) is the mass of the moon \( 73.49 \times 10^{21} \, \mathrm{kg} \), and \( r \) is the radius of the orbit \( 2200 \, \mathrm{km} = 2200000 \, \mathrm{m} \). Compute the initial speed \( v_A \).
02

Calculate velocity change at A

Since the vehicle's speed is reduced by \( 26.3 \, \mathrm{m/s} \) at point A, the new speed \( v'_{A} \) on the elliptic path is \( v_A - 26.3 \).
03

Find velocity at B on the elliptical path

To find the speed at point B, use the energy conservation equation for elliptical motion: \( v'_B = \sqrt{v'^2_{A} + 2\frac{GM}{r_B} - 2\frac{GM}{r_A}} \), where \( r_B = 2080 \, \mathrm{km} = 2080000 \, \mathrm{m} \) is the radius at B. Compute \( v'_B \).
04

Determine circular speed at B

The speed required for a stable circular orbit at \( r_B = 2080 \, \mathrm{km} \) can be found using \( v_B = \sqrt{\frac{GM}{r_B}} \). Compute \( v_B \).
05

Calculate speed reduction at B

Calculate the difference between the speed \( v'_B \) obtained in Step 3 and the circular orbit speed \( v_B \) from Step 4. This difference is the amount by which the vehicle's speed should be reduced as it approaches B.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Circular Orbit
A circular orbit is one where a space vehicle travels around a celestial body in a circular path. This means that the distance between the vehicle and the center of the celestial body remains constant throughout its orbit.
In the context of our exercise, the space vehicle is initially in a circular orbit with a radius of 2200 km around the moon. In a circular orbit, the speed of the vehicle is determined by the gravitational pull of the moon and the radius of the orbit. This speed can be calculated using the formula: \[v = \sqrt{\frac{GM}{r}}\]where:
  • \(v\) is the orbital speed,
  • \(G\) is the gravitational constant \(6.674 \times 10^{-11} \mathrm{Nm}^2/\mathrm{kg}^2\),
  • \(M\) is the mass of the moon \(73.49 \times 10^{21} \mathrm{kg}\),
  • \(r\) is the radius of the orbit.
The circular orbit ensures a stable path for the vehicle without any additional propulsion as long as no other forces act upon it. If a change in the radius of the orbit or any external force occurs, the orbit can become elliptical.
Elliptical Orbit
An elliptical orbit is different from a circular orbit because it is not perfectly round; it has two foci instead of one center. In our example, to transfer the vehicle from a larger to a smaller circular orbit, the vehicle first moves in an elliptical path.
This elliptical trajectory occurs when the vehicle's speed is reduced at a specific point in its path. At point A, the vehicle’s speed is decreased by 26.3 m/s, setting it on this elliptical path, known as path AB. The energy conservation equation for elliptical motion can be utilized to compute the vehicle’s speed at various points on this path: \[v'_B = \sqrt{v'^2_{A} + 2\frac{GM}{r_B} - 2\frac{GM}{r_A}}\]where:
  • \(v'_A\) is initial speed at point A after reduction,
  • \(v'_B\) is speed at point B,
  • \(r_A\) and \(r_B\) are the radii at points A and B respectively.
A vehicle in an elliptical orbit experiences changes in speed as it travels. It moves fastest at the lowest point in its orbit and slowest at the highest point. This property is crucial for maneuvering in space, as changing speeds at specific points can transfer the vehicle into different orbits, like transitioning to a smaller circular orbit.
Speed Reduction
Speed reduction is a key maneuver in orbital mechanics for altering a space vehicle's trajectory. When a vehicle is in space, small changes in speed can result in significant changes in orbit.
In this exercise, the speed is reduced at two critical points. The first reduction occurs at point A, where decreasing the speed by 26.3 m/s transitions the vehicle from a circular to an elliptical orbit. This reduction is necessary for the vehicle to change the shape of its orbit and pass through point B on its new trajectory.
The second speed reduction is crucial as the vehicle approaches point B on the elliptical path. At this point, the goal is to enter a smaller circular orbit with a radius of 2080 km. For this, you calculate the speed the vehicle will have at B using the energy equation from its elliptical path and compare it with the speed needed for a stable circular orbit at B: \[v_B = \sqrt{\frac{GM}{r_B}}\]The difference between these two speeds will tell you by how much the vehicle should decrease its velocity at B. This final reduction is vital to ensure that the vehicle safely transitions into its new circular orbit without drifting into an unstable path.

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Most popular questions from this chapter

An airplane has a mass of \(25 \mathrm{Mg}\) and its engines develop a total thrust of \(40 \mathrm{kN}\) during take-off. If the drag \(D\) exerted on the plane has a magnitude \(D=2.25 \mathrm{v}^{2}\), where \(v\) is expressed in meters per second and \(D\) in newtons, and if the plane becomes airborne at a speed of \(240 \mathrm{km} / \mathrm{h}\), determine the length of runway required for the plane to take off.

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