/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 64 A small 250 -g collar \(C\) can ... [FREE SOLUTION] | 91Ó°ÊÓ

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A small 250 -g collar \(C\) can slide on a semicircular rod which is made to rotate about the vertical \(A B\) at a constant rate of 7.5 rad/s. Determine the three values of \(\theta\) for which the collar will not slide on the rod, assuming no friction between the collar and the rod.

Short Answer

Expert verified
Calculate \( \theta \) using \( \tan \theta = \frac{g}{\omega^2 R} \) for three possible values in \( [0, \pi] \).

Step by step solution

01

Understanding the Problem

The problem involves a collar of mass 250 g sliding on a semicircular rod rotating at a constant angular velocity of 7.5 rad/s. We need to find the angles \( \theta \) where the collar remains stationary (does not slide) on the rod. There is no friction, so forces involved are centripetal and gravitational.
02

Setting up the Forces

The forces acting on the collar are its weight \( m \times g \) acting downwards and the centripetal force requirement due to rotation. The condition for no sliding is that the net radial force should equal the centripetal force required which is \( m \times \omega^2 \times r \) where \( \omega = 7.5 \text{ rad/s} \) and \( r \) is the radial distance to the collar.
03

Expressing the Radial Distance

The radial distance \( r \) can be expressed in terms of \( \theta \). For a semicircular rod, \( r \) is a function of \( \theta \) and can be expressed as \( r = R \sin \theta \), where \( R \) is the radius of the semicircle.
04

Equating Force Components

The gravitational component that acts as the centripetal force is \( m \times g \times \cos \theta \). Set this equal to the required centripetal force due to the rotation: \( m \times g \times \cos \theta = m \times \omega^2 \times R \sin \theta \). Simplify to get \( g \cos \theta = \omega^2 R \sin \theta \).
05

Finding \( \theta \)

Rearrange the equation to find \( \tan \theta = \frac{g}{\omega^2 R} \). Find the values of \( \theta \) which satisfy this equation. Given that a semicircle covers angles from \( 0 \) to \( \pi \), compute the three possible \( \theta \) values that meet this condition.
06

Calculating Specific Values for \( \theta \)

Calculate using the given values: \( \omega = 7.5 \) rad/s, \( g = 9.81 \text{ m/s}^2 \), and assuming the radius \( R \) is also given or needs to be found based on other context, solve for \( \theta \). If \( R \) is given as a constant value, substitute and find \( \theta \).
07

Conclusion

Summarize the three \( \theta \) values obtained from the calculations, ensuring consistency with the semicircle constraints (0 to \( \pi \)). This will give the three specific angles at which the collar does not slide.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Centripetal Force
Centripetal force is a crucial concept when understanding objects in circular motion. It is the force that keeps an object moving in a curved path, directing it towards the center of the circle. Without it, the object would simply move off in a straight line.
  • For a rotating object, like our collar sliding on a rod, centripetal force is essential to keep it on its circular path.
  • This force does not act like other forces that you might be familiar with. It does not come from an external push or pull but from the result of localized forces such as tension, gravity, or friction acting inwards.
  • In our exercise, the centripetal force required to keep the collar from sliding comes from the inward pull due to gravity, specifically a component of the gravitational force.

To maintain balance without sliding, this gravitational component acting radially must be equal to the centrifugal demand placed on the collar by virtue of its motion. To visualize this, imagine swinging a ball on a string horizontally. The tension in the string is the centripetal force. If you let go, the ball flies off in a tangent, highlighting the role of centripetal force in keeping circular motion.
Uniform Circular Motion
Uniform circular motion refers to an object's consistent movement along a circular path with a constant speed. In such a motion, only the direction of the velocity changes, not its magnitude.
  • In our context, the collar slides along the semicircular rod steadily, at a constant speed defined by the angular velocity.
  • This constant velocity ensures the collar remains in a uniform circular path, assuming all conditions are ideal—that is, without frictional forces disrupting the motion.
  • For the collar, uniformity in circular motion implies that every part of it travels through equal circular arcs over equal periods, maintaining steadiness in its rotation.

Understanding this simplifies our analysis of the forces in play because it means the only forces to consider are those internal to the system—no external force fluctuations are involved under these ideal conditions.
Angular Velocity
Angular velocity is a measure of how quickly an object rotates or revolves around a central point. It's commonly denoted by the symbol \( \omega \) and measured in radians per second (rad/s).
  • This concept is vital in determining the dynamic behavior of rotating systems, like the collar sliding along the rod.
  • In our problem, the rod rotates at a constant angular velocity of 7.5 rad/s, setting the pace for the sliding collar.
  • Angular velocity relates to both the speed at which the collar moves through the circular path and the forces experienced.

By focusing on the angular velocity, we can connect it to linear velocities and accelerations, particularly when computing the required centripetal force.For instance, the centripetal force can be derived using the expression \( m \times \omega^2 \times r \), where \( r \) is the radial distance. This relation connects how the angular measure contributes to keeping the object tethered in its path, at every increment of its revolution.

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Most popular questions from this chapter

The 1.2 -lb flyballs of a centrifugal governor revolve at a constant speed \(v\) in the horizontal circle of \(6-\) in. radius shown. Neglecting the weights of links \(A B, B C, A D,\) and \(D E\) and requiring that the links support only tensile forces, determine the range of the allowable values of \(v\) so that the magnitudes of the forces in the links do not exceed 17 lb.

Pin \(B\) weighs 4 oz and is free to slide in a horizontal plane along the rotating arm \(O C\) and along the fixed circular slot \(D E\) of radius \(b=20\) in. Neglecting friction and assuming that \(\theta=15\) rad/s and \(\ddot{\theta}=250 \mathrm{rad} / \mathrm{s}^{2}\) for the position \(\theta=20^{\circ},\) determine for that position \((a)\) the radial and transverse components of the resultant force exerted on pin \(B,(b)\) the forces \(P\) and \(Q\) exerted on pin \(B\), respectively, by rod \(O C\) and the wall of slot \(D E .\)

A light train made up of two cars is traveling at \(90 \mathrm{km} / \mathrm{h}\) when the brakes are applied to both cars. Knowing that car \(A\) has a mass of \(25 \mathrm{Mg}\) and car \(B\) a mass of \(20 \mathrm{Mg}\), and that the braking force is \(30 \mathrm{kN}\) on each car, determine \((a)\) the distance traveled by the train before it comes to a stop, \((b)\) the force in the coupling between the cars while the train is slowing down.

A semicircular slot of 10 -in. radius is cut in a flat plate that rotates about the vertical \(A D\) at a constant rate of 14 rad/s. A small, \(0.8-\) lb block \(E\) is designed to slide in the slot as the plate rotates. Knowing that the coefficients of friction are \(\mu_{s}=0.35\) and \(\mu_{k}=0.25,\) determine whether the block will slide in the slot if it is released in the position corresponding to \((a) \theta=80^{\circ},(b) \theta=40^{\circ} .\) Also determine the magnitude and the direction of the friction force exerted on the block immediately after it is released.

A 1 -kg collar can slide on a horizontal rod that is free to rotate about a vertical shaft. The collar is initially held at \(A\) by a cord attached to the shaft. A spring of constant \(30 \mathrm{N} / \mathrm{m}\) is attached to the collar and to the shaft and is undeformed when the collar is at \(A .\) As the rod rotates at the rate \(\dot{\theta}=16 \mathrm{rad} / \mathrm{s}\), the cord is cut and the collar moves out along the rod. Neglecting friction and the mass of the rod, determine (a) the radial and transverse components of the acceleration of the collar at \(A,(b)\) the acceleration of the collar relative to the rod at \(A,(c)\) the transverse component of the velocity of the collar at \(B .\)

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