/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 65 A small 250 -g collar \(C\) can ... [FREE SOLUTION] | 91Ó°ÊÓ

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A small 250 -g collar \(C\) can slide on a semicircular rod which is made to rotate about the vertical \(A B\) at a constant rate of 7.5 rad/s. Knowing that the coefficients of friction are \(\mu_{s}=0.25\) and \(\mu_{k}=0.20\), indicate whether the collar will slide on the rod if it is released in the position corresponding to \((a) \theta=75^{\circ},(b) \theta=40^{\circ} .\) Also, determine the magnitude and direction of the friction force exerted on the collar immediately after release.

Short Answer

Expert verified
(a) The collar will slide at \( \theta=75^{\circ} \). Friction force determined by kinetic friction. (b) The collar will not slide at \( \theta=40^{\circ} \). Friction force is static.

Step by step solution

01

Calculating the Normal Force

First, we need to determine the normal force exerted on the collar. Since the collar is in circular motion, the forces acting on it include the gravitational force, the centripetal force due to rod rotation, and the normal force. Determine the radial direction of motion, where centripetal acceleration a_c is due to the spinning rod:\[a_c = ext{radius of rod} \times ext{angular velocity}^2\]Given the angular velocity \( \omega = 7.5 \text{ rad/s} \) and knowing \( \theta \), compute the effective radius \( r \) corresponding to above angles. Also consider the weight \( W = mg = 0.25 \cdot 9.81 \text{ N} \). Use components of the forces to find the normal force \( N \) in both cases.
02

Analyzing the Forces for Sliding Condition

Next, analyze whether the static friction can prevent the collar from sliding. The static friction force is given by:\[f_s = \mu_s \cdot N\]Calculate the centrifugal force required to maintain the circular motion. If:\[f_s < m \cdot a_c\]the collar will slide. Compare these forces at both angles \( \theta = 75^{\circ} \) and \( \theta = 40^{\circ} \) to determine slipping occurrence.
03

Evaluating the Friction Force on Sliding

If the collar is determined to slide (from Step 2), compute the friction force exerted on it using the kinetic friction coefficient:\[f_k = \mu_k \cdot N\]If there's no sliding, the friction force is equal to the static friction required to balance other forces, but not exceeding \( f_s \). Calculate this friction force at both angles.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Centripetal Force
In the context of a collar sliding on a semicircular rod, understanding the centripetal force is crucial. This force is what keeps an object moving in a circular path. Rather than being a distinct type of force, centripetal force is simply the net force causing this motion.

To visualize this, imagine tying a ball to the end of a string and swinging it around in a circle. The tension in the string provides the centripetal force needed to keep the ball moving in a circular path. Similarly, for the collar on the rod, this force is provided by the radial component of forces acting on the collar.
  • The centripetal acceleration can be calculated using the formula: \( a_c = r \times \omega^2 \), where \( r \) is the radius and \( \omega \) is the angular velocity.
  • In this exercise, the angular velocity \( \omega \) is provided as 7.5 rad/s. By calculating the radius for each angle, the effective centripetal force exerted on the collar can be determined, which is important to understand the forces at play when assessing whether the collar will slide.
Coefficient of Friction
The coefficient of friction is a fundamental concept in understanding how objects interact with the surfaces they are on. It's a measure of how much frictional force exists between two surfaces. In this exercise, we have two coefficients: static friction \( \mu_s \) and kinetic friction \( \mu_k \).
  • Static Friction: This occurs when the collar is about to slide but hasn't started moving yet. The force is calculated as \( f_s = \mu_s \times N \), where \( N \) is the normal force.
  • Kinetic Friction: This comes into play once the collar starts sliding. It generally has a lower coefficient than static friction. The force is given by \( f_k = \mu_k \times N \).
Understanding these coefficients helps determine whether the collar will slide or stay put. By comparing the static frictional force to the necessary centripetal force for circular motion, we can see if the collar remains fixed. If the required centripetal force is greater than what static friction can provide, the collar will start sliding, and kinetic friction will take over.
Angular Velocity
Angular velocity is a key player in the dynamics of rotating mechanical systems. It represents how fast an object rotates around a central point or axis. Here, it's given as \( \omega = 7.5 \text{ rad/s} \).

Angular velocity affects the centripetal acceleration (and thus force) because these accelerations depend directly on this velocity. For an object in rotation, like the collar, the formula \( a_c = r \times \omega^2 \) shows that higher angular velocities lead to larger centripetal accelerations. This means more force is needed to keep the collar from flying off, increasing the role and challenge of static friction.

In practical terms, knowing the angular velocity allows us to compute various forces in such scenarios. It tells us how swiftly the dynamics switch from the state of rest (static friction dominated) to motion (kinetic friction dominated). Calculating these correctly is crucial for accurately predicting whether sliding will occur.
Static and Kinetic Friction
Friction is a force that opposes motion, and understanding static and kinetic friction is essential when examining whether the collar will slide. These forces are determined by their respective coefficients given in the problem.
  • Static Friction: This friction is what keeps the collar from moving initially. It acts when the collar is at rest and needs to be overcome by another force to initiate movement.
  • Once the collar starts moving, kinetic friction takes over, which is usually less than static friction. This is why \( \mu_k \) is typically smaller than \( \mu_s \).
In our exercise, the collar's behavior is influenced by these opposing forces. The proper calculation is necessary to determine the normal and frictional forces and to compare the static frictional force against the required centripetal force to understand if the collar will slide or stay. This insight helps solve the problem at angles \( \theta = 75^\circ \) and \( \theta = 40^\circ \), providing the answer to whether static or kinetic friction will dominate.

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Most popular questions from this chapter

Pin \(B\) weighs 4 oz and is free to slide in a horizontal plane along the rotating arm \(O C\) and along the fixed circular slot \(D E\) of radius \(b=20\) in. Neglecting friction and assuming that \(\theta=15\) rad/s and \(\ddot{\theta}=250 \mathrm{rad} / \mathrm{s}^{2}\) for the position \(\theta=20^{\circ},\) determine for that position \((a)\) the radial and transverse components of the resultant force exerted on pin \(B,(b)\) the forces \(P\) and \(Q\) exerted on pin \(B\), respectively, by rod \(O C\) and the wall of slot \(D E .\)

A baggage conveyor is used to unload luggage from an airplane. The 10 -kg duffel bag \(A\) is sitting on top of the \(20-\) kg suitcase \(B .\) The conveyor is moving the bags down at a constant speed of \(0.5 \mathrm{m} / \mathrm{s}\) when the belt suddenly stops. Knowing that the cofficient of friction between the belt and \(B\) is 0.3 and that bag \(A\) does not slip on suitcase \(B\), determine the smallest allowable coefficient of static friction between the bags.

A small 250 -g collar \(C\) can slide on a semicircular rod which is made to rotate about the vertical \(A B\) at a constant rate of 7.5 rad/s. Determine the three values of \(\theta\) for which the collar will not slide on the rod, assuming no friction between the collar and the rod.

A 0.2 -lb model rocket is launched vertically from rest at time \(t=0\) with a constant thrust of 2 lb for one second and no thrust for \(t>1\) s. Neglecting air resistance and the decrease in mass of the rocket, determine ( \(a\) ) the maximum height \(h\) reached by the rocket, \((b)\) the time required to reach this maximum height.

A space probe is to be placed in a circular orbit of radius \(4000 \mathrm{km}\) about the planet Mars. As the probe reaches \(A\), the point of its original trajectory closest to Mars, it is inserted into a first elliptic transfer orbit by reducing its speed. This orbit brings it to point \(B\) with a much- reduced velocity. There the probe is inserted into a second transfer orbit by further reducing its speed. Knowing that the mass of Mars is 0.1074 times the mass of the earth, that \(r_{A}=9000 \mathrm{km}\) and \(r_{B}=180000 \mathrm{km},\) and that the probe approaches \(A\) on a parabolic trajectory, determine the time needed for the space probe to travel from \(A\) to \(B\) on its first transfer orbit.

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