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You are a project manager for a manufacturing company. One of the machine parts on the assembly line is a thin, uniform rod that is \(60.0 \mathrm{~cm}\) long and has mass \(0.400 \mathrm{~kg}\). (a) What is the moment of inertia of this rod for an axis at its center, perpendicular to the rod? (b) One of your engineers has proposed to reduce the moment of inertia by bending the rod at its center into a V-shape, with a \(60.0^{\circ}\) angle at its vertex. What would be the moment of inertia of this bent rod about an axis perpendicular to the plane of the \(\mathrm{V}\) at its vertex?

Short Answer

Expert verified
The moment of inertia for a straight rod is \(0.008 \mathrm{~kg} \cdot \mathrm{m}^2\) and for a V-shaped rod is \(0.006 \mathrm{~kg} \cdot \mathrm{m}^2\).

Step by step solution

01

Calculate moment of inertia for a straight rod

Use the formula for the moment of inertia of a straight rod which is \(I=\frac{1}{12}mL^2\) where \(m=0.4 \mathrm{~kg}\) is the mass and \(L=0.6 \mathrm{~m}\) is the length. You get \(I=\frac{1}{12}(0.4 \mathrm{~kg})(0.6 \mathrm{~m})^2=0.008 \mathrm{~kg} \cdot \mathrm{m}^2\).
02

Convert the angle in degrees to radians

In the second scenario, the angle is given in degrees, but we should convert it into radians as the trigonometric functions in the moment of inertia formula for a V-shaped rod use radians. The conversion formula from degrees to radians is \(\theta_{\text{rad}} = \frac{\pi}{180}\theta_{\text{deg}}\). Thus, we get \(\theta_{\text{rad}}=\frac{\pi}{180}(60.0^{\circ})=\frac{\pi}{3} \mathrm{~rad}\).
03

Calculate moment of inertia for a V-shaped rod

Now use the formula for the moment of inertia of a V-shaped rod which is \(I= \frac{mL^2}{4} sin^2(\frac{\theta}{2})\). We already have \( m=0.4 \mathrm{~kg}\), \(L=0.6 \mathrm{~m}\), and \(\theta=\frac{\pi}{3} \mathrm{~rad}\). Substituting these values into the formula, we get \( I= \frac{(0.4 \mathrm{~kg})(0.6 \mathrm{~m})^2}{4} sin^2(\frac{\pi}{6})=0.006 \mathrm{~kg} \cdot \mathrm{m}^2\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rigid Body Dynamics
When we talk about rigid body dynamics, we are exploring how solid objects move. Unlike fluids or gases, rigid bodies do not deform when forces are applied, at least in an ideal scenario. This makes them simpler to analyze. We often look at properties like mass, velocity, and acceleration, but a particularly important one in this context is the moment of inertia.
  • Rigid bodies tend to have fixed shapes and sizes.
  • Their mass does not change regardless of how they move.
  • We analyze such bodies by looking at how forces and torques affect them.
In our problem, the rod is considered a rigid body. The concept of the moment of inertia plays a crucial role in determining how it will react to rotational forces. It's like rotational mass - it measures how hard it is to make something spin around a particular axis. When we change the shape of the rod (like bending it into a V-shape), we change how that mass is distributed, thus changing the moment of inertia.
Simple Harmonic Motion
Simple harmonic motion (SHM) refers to a type of motion where an object moves back and forth through an equilibrium position. This is similar to the motion of a pendulum or a spring. While the moment of inertia isn’t directly about SHM, it's a fundamental element in broader mechanical physics which involves SHM.
  • SHM is characterized by periodic motion such as oscillations.
  • For something to have SHM, the restoring force must be proportional to the displacement.
  • The frequency and period of oscillation depend heavily on mass and how it is distributed.
In the context of our rod, if it were to oscillate back and forth in a motion similar to SHM, its moment of inertia would significantly influence the motion's frequency and amplitude. An altered shape, like bending the rod, might drastically change these oscillatory characteristics.
Mechanical Physics
Mechanical physics is a broad field that deals with the motion and behavior of objects. It encompasses concepts like force, energy, and motion, and is anchored on the laws of motion formulated by Isaac Newton.
  • It examines how bodies move in response to external forces.
  • Newton's laws serve as a foundation, describing how forces affect an object's movement.
  • Mechanical physics covers both linear and rotational movements.
In our exercise, the focus is on rotational dynamics, which falls under mechanical physics. Specifically, moment of inertia is a central theme. Understanding how a rod's shape or mass distribution affects its moment of inertia helps in controlling or predicting its rotational behavior. By bending the rod into a V-shape, the rules of mechanical physics allow us to predict the new moment of inertia and how it might behave under the same conditions of force or motion.

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Most popular questions from this chapter

A bicycle wheel has an initial angular velocity of \(1.50 \mathrm{rad} / \mathrm{s}\) (a) If its angular acceleration is constant and equal to \(0.200 \mathrm{rad} / \mathrm{s}^{2},\) what is its angular velocity at \(t=2.50 \mathrm{~s} ?\) (b) Through what angle has the wheel turned between \(t=0\) and \(t=2.50 \mathrm{~s} ?\)

\(\mathrm{At} t=0\) a grinding wheel has an angular velocity of \(24.0 \mathrm{rad} / \mathrm{s}\) It has a constant angular acceleration of \(30.0 \mathrm{rad} / \mathrm{s}^{2}\) until a circuit breaker trips at \(t=2.00 \mathrm{~s}\). From then on, it turns through 432 rad as it coasts to a stop at constant angular acceleration. (a) Through what total angle did the wheel turn between \(t=0\) and the time it stopped? (b) At what time did it stop? (c) What was its acceleration as it slowed down?

A uniform disk has radius \(R_{0}\) and mass \(M_{0}\). Its moment of inertia for an axis perpendicular to the plane of the disk at the disk's center is \(\frac{1}{2} M_{0} R_{0}^{2}\). You have been asked to halve the disk's moment of inertia by cutting out a circular piece at the center of the disk. In terms of \(R_{0}\), what should be the radius of the circular piece that you remove?

While riding a multispeed bicycle, the rider can select the radius of the rear sprocket that is fixed to the rear axle. The front sprocket of a bicycle has radius \(12.0 \mathrm{~cm} .\) If the angular speed of the front sprocket is 0.600 rev \(/ \mathrm{s},\) what is the radius of the rear sprocket for which the tangential speed of a point on the rim of the rear wheel will be \(5.00 \mathrm{~m} / \mathrm{s} ?\) The rear wheel has radius \(0.330 \mathrm{~m}\).

A uniform wheel in the shape of a solid disk is mounted on a frictionless axle at its center. The wheel has mass \(5.00 \mathrm{~kg}\) and radius \(0.800 \mathrm{~m} .\) A thin rope is wrapped around the wheel, and a block is suspended from the free end of the rope. The system is released from rest and the block moves downward. What is the mass of the block if the wheel turns through 8.00 revolutions in the first \(5.00 \mathrm{~s}\) after the block is released?

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