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An electric fan is turned off, and its angular velocity decreases uniformly from 500 rev \(/\) min to 200 rev \(/ \min\) in 4.00 s. (a) Find the angular acceleration in rev/s \(^{2}\) and the number of revolutions made by the motor in the 4.00 s interval. (b) How many more seconds are required for the fan to come to rest if the angular acceleration remains constant at the value calculated in part (a)?

Short Answer

Expert verified
The angular acceleration for the fan is -1.25 rev/sec^2 and it makes 25 revolutions in 4 seconds. It will take an additional 2.66 seconds for the fan to come to rest.

Step by step solution

01

Convert velocities from rev/min to rev/sec

The initial angular velocity becomes \(500/60 = 8.33 \ rev/sec\) while the final angular velocity becomes \(200/60 = 3.33 \ rev/sec\)
02

Calculate angular acceleration

To find the angular acceleration, subtract the initial angular velocity from the final angular velocity and divide by the time interval. Hence, \(\alpha = (3.33 - 8.33)/4 = -1.25 \ rev/sec^{2}\). The negative sign indicates deceleration.
03

Find number of revolutions during the 4s interval

Using equation of motion for uniform deceleration \(θ = Ө0t + 0.5*α*t^{2}\), where \(Ө0\) is the initial angular velocity, \(α\) is angular acceleration, \(t\) is time and \(θ\) is angular displacement. Substituting \(Ө0 = 8.33 rev/sec\), \(α = -1.25 rev/sec^{2}\) and \(t = 4 sec\), we get \(θ = (8.33 * 4) + 0.5*(-1.25)*(4)^{2} = 25 revolutions\).
04

Compute time required for the fan to rest

Given the angular acceleration; the final angular velocity when the fan comes to rest will be zero. Using the equation \(ω = Ө0 + αt\), where \(ω\) is the final angular velocity, \(Ө0\) is the initial angular velocity, \(α\) is the angular acceleration and \(t\) is the time. Since \(ω = 0\) at rest, \(t = (ω - Ө0) / α = (0 - 3.33) / -1.25 = 2.66 sec.\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Velocity
Angular velocity is an important concept when discussing rotating objects like an electric fan. It refers to the rate at which an object spins around an axis. In this exercise, the fan's angular velocity is given in revolutions per minute (rev/min) and then converted to revolutions per second (rev/s).

Remember, angular velocity can be positive or negative. A positive value usually indicates that the object is spinning in a specific direction (e.g., clockwise), while a negative value may mean it's spinning in the opposite direction (e.g., counterclockwise). In the context of the problem, we are dealing with a decreasing angular velocity from 8.33 rev/s to 3.33 rev/s, showing that the fan is slowing down while it spins.
  • Conversion is key - ensuring you have consistent units helps solve problems accurately.
  • Understanding initial and final angular velocities is crucial for calculating acceleration and displacement.
Angular Acceleration
Angular acceleration describes how quickly the angular velocity of an object changes. It's the rate of change of angular velocity over time and can inform us about how a rotating object's speed is changing.

In the solution, angular acceleration is computed using the formula \[ \alpha = \frac{\omega_f - \omega_i}{t}\]where \(\omega_f\) is the final angular velocity, \(\omega_i\) is the initial angular velocity, and \(t\) is the time over which the change occurs. When calculated, the fan's angular acceleration is \(-1.25 \, \text{rev/s}^{2}\). This negative value represents a uniform decrease in angular velocity, also known as deceleration.
  • Angular acceleration tells us how fast the rotational speed changes.
  • It's crucial for predicting the future motion of rotating objects.
  • The sign (positive or negative) indicates acceleration or deceleration.
Uniform Deceleration
Uniform deceleration in angular motion means that the rate at which an object is slowing down is constant. In this exercise, because the fan's angular acceleration is constant at \(-1.25 \, \text{rev/s}^{2}\), we say the fan experiences uniform deceleration.

When dealing with uniform deceleration, the equations of motion for angular displacement take a specific form that allows us to predict the motion over time. In the exercise, the student's task is to use this concept to calculate the total number of revolutions the fan makes in a given period and to determine how long it takes to come to a complete stop.
  • Understanding uniform deceleration is crucial for analyzing how objects come to rest.
  • Predicting when and how quickly an object will stop can be done using the motion equations.
  • The constant rate makes calculations straightforward once the acceleration is known.
Angular Displacement
Angular displacement refers to the angle through which an object rotates, measured in terms of revolutions or degrees. It's a key measure of how far a rotatable object has turned.

In this exercise, the fan’s angular displacement during 4 seconds is calculated using the formula, \[ \theta = \omega_i t + \frac{1}{2} \alpha t^2\] Here, \(\theta\) represents the angular displacement, \(\omega_i\) is the initial angular velocity, \(\alpha\) is the angular acceleration, and \(t\) is time. Substituting the known values, the total angular displacement is found to be 25 revolutions.
  • Angular displacement tells us how much an object has rotated in a certain period.
  • It's useful for determining the total rotation even when velocity changes.
  • Helps in planning real-world applications where rotational motion is involved.

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Most popular questions from this chapter

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