/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 31 Three small blocks, each with ma... [FREE SOLUTION] | 91Ó°ÊÓ

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Three small blocks, each with mass \(m\), are clamped at the ends and at the center of a rod of length \(L\) and negligible mass. Compute the moment of inertia of the system about an axis perpendicular to the rod and passing through (a) the center of the rod and (b) a point onefourth of the length from one end.

Short Answer

Expert verified
The moment of inertia of the system about an axis perpendicular to the rod and passing through the center of the rod is \(m*(L^2)/4\) and through a point one-fourth of the length from one end is \((7m*L^2)/8\)

Step by step solution

01

Calculate Moments of Inertia for the Center of the Rod

For the first part of the problem, the rotation axis is at the center of the rod. The moment of inertia \(I\) of a point mass \(m\) a distance \(r\) from the axis of rotation is given by \(I=mr^2\). In this case, there are one mass at the center of the rod (r=0) and two masses each at a distance \( L/2 \) from the center of the rod. So, the total moment of inertia, \( I_{total} \), about the center of the rod is \( I_{total} = m*(0)^2 + 2*m*(L/2)^2 = m*(L^2)/4 \)
02

Calculate Moments of Inertia for One-fourth of the Length from One End

For the second part, the rotation axis is at one-fourth of the length from one end. Now, there are one mass at the distance \( L/4 \) from the axis, one mass at the distance \( L/2 \) and one mass at distance \( 3L/4 \). So, the total moment of inertia, \( I'_{total} \), about this point is \( I'_{total} = m*(L/4)^2 + m*(L/2)^2 + m*(3L/4)^2 = (m*L^2)/16 + (m*L^2)/4 + (9m*L^2)/16 = (14m*L^2)/16 = (7m*L^2)/8 \)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rotational Dynamics
Rotational dynamics is a foundational component of physics that deals with forces and torques and their effect on motion, specifically rotational motion. The moment of inertia plays an integral role in this as it quantifies how much torque is needed for an object to attain a given angular acceleration. It is very similar to mass in linear dynamics, which indicates how much force is needed to achieve an acceleration.

When confronted with a problem such as measuring the moment of inertia, it's important to understand that it depends on both the mass of the objects in question as well as their distribution with respect to the rotation axis. In the exercise provided, three blocks of equal mass are positioned at varying distances from the axis of rotation, drastically affecting the system's moment of inertia.

To make the problem more digestible, consider each block individually as a point mass and calculate its contribution to the total moment of inertia before summing them up. The position of the specific axis of rotation is crucial, as the same physical system will have a different moment of inertia when measured around different axes, shown in the exercise's two scenarios.
Physics Problem Solving
In physics problem solving, starting with a systematic approach is instrumental in understanding and tackling exercises efficiently. First, qualitatively understanding the scenario is essential before jumping to quantitative analysis. Following this, identifying the formula or principle (like the expression for moment of inertia, \( I = mr^2 \)) is a necessary next step.

Once the appropriate formulas are identified, breaking the problem down into smaller, manageable parts simplifies the process. In the exercise, this means calculating the moment of inertia for each individual mass relative to the axis and summing them to arrive at the total moment of inertia. It's also crucial to be rigorous about units and to square distances accurately when they're substituted into the formulas for moment of inertia.

Lastly, reviewing the calculated results for physical plausibility can help catch mistakes. For example, the moment of inertia should be larger when the mass distribution is further from the axis of rotation, as seen when comparing the results from points (a) and (b) in the exercise.
Mechanics
Mechanics is the branch of physics dealing with the motion of objects and the forces acting on them. This includes both translational motion, which is movement from one place to another, and rotational motion, which involves an object spinning around an axis. The principles of mechanics are applied in the exercise to calculate the moment of inertia, crucial for understanding rotational motion.

In any mechanical problem, particularly those like our example that involve rotational dynamics, it is helpful to visualize the system and sketch it if possible. Creating a diagram can aid in understanding the physical arrangement of the masses and their distances from the chosen axis of rotation, which are pivotal in determining the moment of inertia.

Understanding rotational motion also requires familiarity with torque, angular momentum, and equilibrium concepts, all closely related to the moment of inertia. In terms of the conservation of angular momentum, an object's moment of inertia coupled with its angular velocity remains constant unless acted on by an external torque, illustrating the inertia's role as the rotational counterpart to mass in linear motion.

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Most popular questions from this chapter

A fan blade rotates with angular velocity given by \(\omega_{z}(t)=\gamma-\beta t^{2}, \quad\) where \(\quad \gamma=5.00 \mathrm{rad} / \mathrm{s} \quad\) and \(\quad \beta=0.800 \mathrm{rad} / \mathrm{s}^{3}\) (a) Calculate the angular acceleration as a function of time. (b) Calculate the instantaneous angular acceleration \(\alpha_{z}\) at \(t=3.00 \mathrm{~s}\) and the average angular acceleration \(\alpha_{\mathrm{av}-z}\) for the time interval \(t=0\) to \(t=3.00 \mathrm{~s}\). How do these two quantities compare? If they are different, why?

A computer disk drive is turned on starting from rest and has constant angular acceleration. If it took \(0.0865 \mathrm{~s}\) for the drive to make its second complete revolution, (a) how long did it take to make the first complete revolution, and (b) what is its angular acceleration, in rad/s \(^{2}\) ?

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A circular saw blade with radius \(0.120 \mathrm{~m}\) starts from rest and turns in a vertical plane with a constant angular acceleration of \(2.00 \mathrm{rev} / \mathrm{s}^{2} .\) After the blade has turned through \(155 \mathrm{rev},\) a small piece of the blade breaks loose from the top of the blade. After the piece breaks loose, it travels with a velocity that is initially horizontal and equal to the tangential velocity of the rim of the blade. The piece travels a vertical distance of \(0.820 \mathrm{~m}\) to the floor. How far does the piece travel horizontally, from where it broke off the blade until it strikes the floor?

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