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A fan blade rotates with angular velocity given by \(\omega_{z}(t)=\gamma-\beta t^{2}, \quad\) where \(\quad \gamma=5.00 \mathrm{rad} / \mathrm{s} \quad\) and \(\quad \beta=0.800 \mathrm{rad} / \mathrm{s}^{3}\) (a) Calculate the angular acceleration as a function of time. (b) Calculate the instantaneous angular acceleration \(\alpha_{z}\) at \(t=3.00 \mathrm{~s}\) and the average angular acceleration \(\alpha_{\mathrm{av}-z}\) for the time interval \(t=0\) to \(t=3.00 \mathrm{~s}\). How do these two quantities compare? If they are different, why?

Short Answer

Expert verified
The angular acceleration function is \(\alpha(t) = -2\beta t\). The instantaneous angular acceleration at \(t=3.00s\) and the average angular acceleration from \(t=0\) to \(t=3.00s\) are computed based on this function. A comparison between these two quantities reveals their relationship and variations during a specific time interval.

Step by step solution

01

Derive the angular acceleration function

First, we should recall that angular acceleration \( \alpha \) is the rate of change of angular velocity \( \omega \) with respect to time. In terms of calculus, it's the derivative of angular velocity with respect to time. Therefore, we can derive the angular acceleration function by taking the derivative of the given angular velocity function \( \omega = \gamma - \beta t^{2} \). After taking the derivative with respect to time, we get: \( \alpha(t) = -2\beta t \) .
02

Calculate the instantaneous angular acceleration at t=3s

Substitute \(t=3.00s\) into the angular acceleration function \(\alpha(t) = -2\beta t\), we get the instantaneous angular acceleration at t=3s: \(\alpha(3) = -2\beta * 3 \)
03

Calculate the average angular acceleration between t=0 and t=3s

The average angular acceleration in a time interval is defined as the change in angular velocity divided by the change in time. So, since the angular velocity function is given by \(\omega(t) = \gamma - \beta t^{2}\), we calculate the change in angular velocity between t=0 and t=3.00s as \( \Delta \omega = \omega(3) - \omega(0) \), then divide by the time interval to find the average angular acceleration between t=0 and t=3s: \(\alpha_{av} = \frac{\Delta \omega}{3} \)
04

Comparison of the instantaneous and average angular accelerations

After calculating the instantaneous and average angular acceleration, we need to compare these two quantities. The differences, if any, are likely due to the fact that angular velocity varies with time, suggesting a changing angular acceleration over the time interval of interest.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Velocity
Angular velocity is a measure of how quickly an object rotates or revolves around an axis. It is usually denoted by the Greek letter omega (\(\omega\)) and is typically expressed in radians per second (rad/s). For any rotating object, angular velocity represents the rate of change of the angular position with respect to time.
In the context of the original exercise, the angular velocity of the fan blade is given by:
  • \(\omega_{z}(t) = \gamma - \beta t^{2}\)
Here, \(\gamma\) is the initial angular velocity, and \(\beta\) is a constant that affects how the angular velocity changes over time.
The minus sign before \(\beta t^2\) indicates that as time increases, the angular velocity decreases quadratically due to the \(t^2\) term. Understanding angular velocity is crucial for analyzing the rotational motion of objects and predicting their future states.
Angular Acceleration
Angular acceleration is the rate at which the angular velocity of an object changes with time. It is represented by \(\alpha\) and is measured in radians per second squared (rad/s²). Angular acceleration can be calculated by taking the derivative of the angular velocity with respect to time.
In the provided problem, the angular velocity equation is:
  • \(\omega_{z}(t) = \gamma - \beta t^{2}\)
To find the angular acceleration, we derive this equation with respect to time, resulting in:
  • \(\alpha(t) = -2\beta t\)
This function tells us that the angular acceleration is directly proportional to time \(t\), and the negative sign indicates that the acceleration is decreasing. This means as time progresses, the angular velocity slows down at a steady rate determined by the constants \(\beta\) and \(t\). Recognizing how angular acceleration works helps to predict how quickly or slowly the angular velocity can change over a specific timeframe.
Calculus in Physics
Calculus plays a vital role in understanding and solving physics problems, especially those involving motion. It allows us to handle changing rates, which are common in real-world scenarios. In the context of rotational motion, calculus helps us transition from angular velocity (\(\omega\)) to angular acceleration (\(\alpha\)).
Laid simply, calculus enables us to take derivatives and integrals:
  • Derivative: Provides the rate of change of a function. For this exercise, the derivative of angular velocity with respect to time gives us angular acceleration.
  • Integral: Provides the accumulated change. Although not directly used in this problem, integrals can calculate changes over time intervals, such as finding displacement.
Understanding differential calculus in physics is essential because it connects various motion descriptors, helping us move from one property (like velocity) to another (like acceleration) efficiently. This provides a more complete picture of an object's state of motion over time.
Instantaneous vs Average Values
Understanding the difference between instantaneous and average values is crucial when analyzing changes over time.
Instantaneous values refer to those that exist at a specific moment, giving precise immediate behavior, while average values represent the overall behavior over a time interval.
  • Instantaneous Value: For angular acceleration, it describes the rate of change of angular velocity at a particular time, say \(t = 3s\). Here, you substitute \(t = 3s\) into the acceleration function \(\alpha(t) = -2\beta t\) to get \(\alpha(3s)\).
  • Average Value: This is the total change in angular velocity divided by the total time period (from \(t = 0\) to \(t = 3s\)), given in the formula \(\alpha_{av} = \frac{\Delta \omega}{3}\).
Differences between instantaneous and average angular acceleration stem from the fact that angular velocity changes non-linearly over time. Thus, the instantaneous acceleration at a specific time may differ from the average over a period due to cumulative effects and variability in the rate of change. Comprehending these differences helps one analyze rotational motion more accurately.

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Most popular questions from this chapter

A uniform disk has radius \(R_{0}\) and mass \(M_{0}\). Its moment of inertia for an axis perpendicular to the plane of the disk at the disk's center is \(\frac{1}{2} M_{0} R_{0}^{2}\). You have been asked to halve the disk's moment of inertia by cutting out a circular piece at the center of the disk. In terms of \(R_{0}\), what should be the radius of the circular piece that you remove?

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