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A \(30.0 \mathrm{~kg}\) crate is initially moving with a velocity that has magnitude \(3.90 \mathrm{~m} / \mathrm{s}\) in a direction \(37.0^{\circ}\) west of north. How much work must be done on the crate to change its velocity to \(5.62 \mathrm{~m} / \mathrm{s}\) in a direction \(63.0^{\circ}\) south of east?

Short Answer

Expert verified
Substitute the calculated values of \(KE_{final}\) and \(KE_{initial}\) in the formula to get the work done on the crate.

Step by step solution

01

Initial Kinetic Energy

To start with, we need to calculate the initial kinetic energy of the crate. This can be done using the formula \(KE = 0.5 * m * v^2\), where \(m = 30.0kg\) (mass of the crate) and \(v = 3.9 m/s\) (initial velocity of the crate). Hence, \(KE_{initial} = 0.5 * 30.0 * (3.9)^2 \).
02

Final Kinetic Energy

Next, calculate the final kinetic energy of the crate using the same formula \(KE = 0.5 * m * v^2\), but this time with \(m = 30.0kg\) (mass of the crate) and \(v = 5.62 m/s\) (final velocity of the crate). Thus, \(KE_{final} = 0.5 * 30.0 * (5.62)^2 \).
03

Work Done

Now, the work done on the crate to change its velocity can be found out using the work-kinetic energy theorem which is \(W = \Delta KE\). Substituting the values, we get \(W = KE_{final} - KE_{initial}\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Energy
Kinetic energy is a component of the total energy possessed by an object in motion. It's defined by the formula:
\( KE = \frac{1}{2}mv^2 \)
In this equation, \( KE \) represents the kinetic energy, \( m \) is the mass of the object, and \( v \) is its velocity. This form of energy is directly proportional to the mass: the more massive the object, the more kinetic energy it holds, if it's moving at the same speed. Likewise, kinetic energy significantly increases with velocity, as it's a quadratic relationship. Understanding kinetic energy is crucial because it helps us predict the impact forces in collisions and the work needed to alter an object's motion.
Work Done in Physics
In physics, the concept of 'work done' correlates directly with energy transfer. When we say that work is done on an object, it implies that energy has been transferred to or from the object to change its state of motion. The amount of work done by a force is calculated using the formula:
\( W = Fd \ cos(\theta) \)
where \( W \) is the work done, \( F \) is the magnitude of the force applied, \( d \) is the displacement of the object, and \( \theta \) is the angle between the force and the displacement direction. In the specific context of kinetic energy, work is said to be done when the energy is used to change an object's speed, represented through the work-kinetic energy theorem:
\( W = \Delta KE \).
This theorem states that the net work done on an object equals the change in its kinetic energy.
Velocity
Velocity is a vector quantity that expresses both the speed and the direction of an object's movement. Mathematically, velocity is defined by:
\( \textbf{v} = \frac{\Delta \textbf{x}}{\Delta t} \),
where \( \textbf{v} \) is the velocity vector, \( \Delta \textbf{x} \) is the change in position, and \( \Delta t \) is the change in time. In physics problems, understanding the vector nature of velocity is essential. Velocity isn't just about how fast something is moving; it's also about where it's going. Any change in the magnitude or direction of velocity implies acceleration, and therefore a force must be acting on the object. For example, the crate in the exercise experienced a change in velocity, indicating that work was done to change not only its speed but also its direction.
Physics Problem Solving
Physics problem solving often involves applying fundamental principles and formulas to find unknowns using given information. Key steps in solving a physics problem include understanding the problem, visualizing it, identifying the relevant principles (such as the work-kinetic energy theorem), setting up the equations, and then solving for the unknowns.
To avoid confusion, it is helpful to break the problem down into smaller parts and solve them step by step, as demonstrated in the crate problem. Tackle the initial and final states separately, and use clear vector directions for quantities like velocity. It's also essential to mind units consistency and correctly apply vector mathematics when dealing with angles and directions. Clear and structured thinking aids in simplifying complex problems into manageable calculations.

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