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BIO Force During a Jump. When jumping straight up from a crouched position, an average person can reach a maximum height of about \(60 \mathrm{~cm} .\) During the jump, the person's body from the knees up typically rises a distance of around \(50 \mathrm{~cm} .\) To keep the calculations simple and yet get a reasonable result, assume that the entire body rises this much during the jump. (a) With what initial speed does the person leave the ground to reach a height of \(60 \mathrm{~cm} ?\) (b) Draw a free-body diagram of the person during the jump. (c) In terms of this jumper's weight \(w\), what force does the ground exert on him or her during the jump?

Short Answer

Expert verified
The initial speed required for a person to jump up to a height of 60 cm is given by \(v_{\text{initial}} = \sqrt{2gh}\). In a free-body diagram, the person jumping experiences two forces: their weight acting downwards and the force exerted by the ground acting upwards. During the jump, the force exerted by the ground is \(F_{\text{ground}} = m(g + a) \), where \( m(g + a) \) is the net force acting on the jumper.

Step by step solution

01

Calculation of Initial Speed

Our first goal is to find out the initial speed (\(v_{\text{initial}}\)). This speed can be found by using the physical equation of motion, which is \(h = v_{\text{initial}}t - 0.5gt^2\). Here, \(h\) is the height (which is 60 cm or 0.6 m), \(t\) is time and \(g\) is the acceleration due to gravity, which is approximately \(9.8 \, m/s^2\). Since the person reaches the maximum height, their final speed (\(v_{\text{final}}\)) is 0. Therefore, we can use another equation of motion: \(v_{\text{final}}^2 = v_{\text{initial}}^2 -2gh\). Solving this for \(v_{\text{initial}}\) gives us \(\sqrt{2gh}\).
02

Creating a Free-Body Diagram

In a free-body diagram for the jumper during the leaps, two forces are at play: the force exerted by the Earth (i.e., the weight of the person) pointing downwards, and the force exerted by the ground on the person (force exerted due to the jump) pointing upwards.
03

Calculation of the Force Exerted on the Ground

The net force during the jump is the difference between the upward force (force with which the ground pushes the person upwards, given as \(F_{\text{ground}}\)) and the downward force (the person's weight). According to Newton's second law of motion, we can thus write the equation \(F_{\text{net}} = ma = F_{\text{ground}} - w\), or \(F_{\text{ground}} = ma + w = m(g + a) \). Here \(a\) is the acceleration, which equals the initial velocity divided by the time taken to reach maximum height. The time can be obtained from the equation of motion: \(t = v_{\text{initial}}/g = \sqrt{2h/g}/g\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinematics Equations
To start off, kinematics is the branch of physics that describes the motion of objects. When analyzing the physics of jumping, we utilize kinematics equations to predict the motion of the jumper. These fundamental equations relate displacement, velocity, acceleration, and time.

Specifically, in the context of jumping, we use the equation \(h = v_{\text{initial}}t - 0.5gt^2\) where \(h\) is the vertical distance jumped, \(v_{\text{initial}}\) is the initial velocity at which the jump begins, \(t\) is the time in the air, and \(g\) is the acceleration due to gravity. When a person reaches their maximum height in a jump, their vertical velocity is zero, allowing us to use another equation: \(v_{\text{final}}^2 = v_{\text{initial}}^2 -2gh\) to calculate the initial launching speed required for reaching a certain height.

Understanding these equations is essential for further analysis, such as determining the force exerted during a jump.
Free-Body Diagram
A free-body diagram is a graphical illustration used to visualize the applied forces, moments, and subsequent reactions on a body in a given condition. In the scenario of a person jumping, the diagram would showcase two main forces.

The weight of the jumper, denoted as \(w\), points downwards due to gravity. On the opposite end, there's the force from the ground pushing upwards, which is the action force that propels the jumper into the air. By drawing a free-body diagram, one can easily see these forces and understand that the net force is what actually creates the acceleration needed to jump.

This visual tool simplifies complex situations into manageable parts and aids in the understanding and application of Newton's second law of motion.
Newton's Second Law of Motion
Newton's second law of motion is fundamental in understanding the dynamics of a jump. It states that the acceleration of an object is directly proportional to the net force acting upon it and inversely proportional to its mass, mathematically expressed as \(F_{\text{net}} = ma\).

During a jump, the net force is the sum of all the individual forces acting on the person. If the ground exerts a force stronger than the person's weight, the net force will push the person upward, causing an acceleration. The interplay of these forces determines the motion of the jumper and can be captured in mathematical expressions that allow us to analyze and predict the outcome of physical activities like jumping.
Force Analysis
Force analysis involves breaking down the forces acting on a body and the effects they have on movement. When jumping, the force analysis will include the force the ground exerts on the person \(F_{\text{ground}}\) and the person's weight \(w\).

According to Newton's laws, the ground must push the person up with a force greater than their weight to initiate a jump. The difference between these two forces generates the net force, which, through the second law of motion, results in the upward acceleration that lifts the person off the ground. The greater this net force, the greater the acceleration and hence, the higher a person can jump.
Gravitational Acceleration
Gravitational acceleration \(g\) is the acceleration on an object due to the force of gravity. Near Earth's surface, this value is approximately \(9.8 \, m/s^2\), acting downwards towards the center of the Earth.

When analyzing jumps, gravitational acceleration plays a crucial role as it counteracts the jumper's upward velocity until the jumper reaches a momentary stop at the peak of the jump. It then accelerates the person back down to the ground following the peak. Gravitational acceleration is central to the kinematics equations used to describe the arc of a jump, as well as understanding the body's weight and the force required to overcome this acceleration during the initial phase of a jump.

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Most popular questions from this chapter

If the coefficient of static friction between a table and a uniform, massive rope is \(\mu_{\mathrm{s}},\) what fraction of the rope can hang over the edge of the table without the rope sliding?

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