/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 73 An \(8.00 \mathrm{~kg}\) box sit... [FREE SOLUTION] | 91Ó°ÊÓ

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An \(8.00 \mathrm{~kg}\) box sits on a ramp that is inclined at \(33.0^{\circ}\) above the horizontal. The coefficient of kinetic friction between the box and the surface of the ramp is \(\mu_{\mathrm{k}}=0.300 .\) A constant horizontal force \(F=26.0 \mathrm{~N}\) is applied to the box (Fig. \(\mathbf{P} 5.73),\) and the box moves down the ramp. If the box is initially at rest, what is its speed \(2.00 \mathrm{~s}\) after the force is applied?

Short Answer

Expert verified
The speed of the box 2 seconds after the force is applied is \(4.10 \, m/s\).

Step by step solution

01

Calculate the force of gravity

First we need to calculate the force of gravity on the box, which is its weight. The weight \( W \) can be found using the equation \( W = m \cdot g \), where \( m = 8.00 \, kg \) is the mass of the box and \( g = 9.8 \, m/s^2 \) is the acceleration due to gravity. This results in \( W = 78.4 \, N \).
02

Determine the components of the weight

Next, we need to find the components of the force of gravity parallel and perpendicular to the incline. The component of weight along the incline (downwards) is given by \( W_{//} = W \cdot \sin(\theta) \), where \( \theta = 33.0^{\circ} \). This results in \( W_{//} = 42.62 \, N \). The component of weight perpendicular to the incline is \( W_{\perp} = W \cdot \cos(\theta) \), resulting in \( W_{\perp} = 65.86 \, N \).
03

Calculate frictional force

The force of friction can be found using the equation \( f = \mu_{k} \cdot N \), where \( \mu_{k} = 0.300 \) is the coefficient of kinetic friction and \( N = W_{\perp} \). Substituting the values, we find \( f = 19.76 \, N \).
04

Determine Net Force

The net force acting on the box along the direction of motion can be calculated using the equation \( F_{net} = F - W_{//} - f \), where \( F = 26.0 \, N \) is the applied force. Substituting the values, we find \( F_{net} = -16.38 \, N \). This negative sign indicates that the direction of the net force is opposed to the direction of motion.
05

Calculate acceleration

We can find the acceleration of the box by using Newton's second law, which states \( F_{net} = m \cdot a \), where \( a \) is the acceleration. Rearranging this equation gives \( a = F_{net} / m \) which results in \( a = -2.05 \, m/s^2 \).
06

Find final speed

Now we can find the final speed of the box using the equation \( v = u + a \cdot t \), where \( u = 0 \, m/s \) is the initial speed, \( a = -2.05 \, m/s^2 \) is the acceleration and \( t = 2.00 \, s \) is the time. This results in \( v = -4.10 \, m/s \). The negative sign indicates that the direction of velocity is opposed to the direction of motion. In terms of speed, we ignore the direction and thus the speed is \( 4.10 \, m/s \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Force of Gravity
Understanding the force of gravity is crucial when studying physics, especially when objects are placed on an inclined plane. Gravity, a fundamental force of nature, pulls objects towards the center of the Earth with an acceleration of approximately \(9.8 \mathrm{m/s^2}\) - this value is often denoted as \(g\).
In this scenario, the box's weight, which represents the force of gravity acting upon it, is calculated by multiplying the mass (\(m\)) by the acceleration due to gravity (\(g\)), resulting in \(W=mg\). Subsequently, this weight interacts with the inclined plane, introducing a unique set of challenges and considerations for the box's motion.
Components of Weight in Inclined Plane
On an inclined plane, the weight of an object breaks down into two primary components: one that acts parallel to the plane and one that is perpendicular.

Parallel Component

This component (\(W_{//}\)) pulls the object down the incline, calculated by \(W \cdot \sin(\theta)\). This force drives the object's potential motion along the plane.

Perpendicular Component

Meanwhile, the perpendicular component (\(W_{\perp}\)) exerts a force directly onto the surface of the incline, computed by \(W \cdot \cos(\theta)\), which influences the normal force and friction experienced by the object. It's important for students to visualize how the weight of an object is resolved into these two components to understand the resultant motion on inclined planes better. The angle of incline (\(\theta\)) plays a pivotal role, altering the magnitude of each component—and thus affecting the motion.
Coefficient of Kinetic Friction
When two surfaces are in motion relative to each other, kinetic friction comes into play. The coefficient of kinetic friction (\(\mu_k\)) is a dimensionless value that quantifies the friction between moving surfaces. This coefficient is determined experimentally and varies based on the materials in contact.

For the box sliding down the ramp, the kinetic friction force opposes the motion and is calculated as the product of this coefficient and the normal force (\(N\)), the force perpendicular to the inclined plane. Kinetic friction is essential in calculations as it significantly affects an object's acceleration and speed. In our textbook problem, it helps in understanding why the box does not accelerate at the acceleration due to gravity alone but rather at a reduced rate due to the opposing frictional force.
Newton's Second Law
Newton's second law of motion is the foundation for understanding the relationship between forces acting upon an object and the resulting motion. It states that the net force \(F_{net}\) acting on an object is equal to the mass \(m\) of the object multiplied by its acceleration \(a\), or \(F_{net} = m \cdot a\).
By applying this law to the box on the inclined plane, we can deduce its acceleration by rearranging this formula to \(a = F_{net} / m\). The net force is a sum of all forces acting along the direction of intended motion, which, after factoring in the applied force, gravitational force, and friction, could indicate whether the box accelerates or decelerates.
Newton's second law is a powerful tool for solving problems involving motion. By utilizing it, we directly link the forces at play to the changes in motion of the box, resulting in the ability to predict its speed after a certain time as presented in our exercise.

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Most popular questions from this chapter

A stone with mass \(0.80 \mathrm{~kg}\) is attached to one end of a string \(0.90 \mathrm{~m}\) long. The string will break if its tension exceeds \(60.0 \mathrm{~N}\). The stone is whirled in a horizontal circle on a frictionless tabletop; the other end of the string remains fixed. (a) Draw a free-body diagram of the stone. (b) Find the maximum speed the stone can attain without the string breaking.

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BIO Stay Awake! An astronaut is inside a \(2.25 \times 10^{6} \mathrm{~kg}\) rocket that is blasting off vertically from the launch pad. You want this rocket to reach the speed of sound \((331 \mathrm{~m} / \mathrm{s})\) as quickly as possible, but astronauts are in danger of blacking out at an acceleration greater than \(4 g\). (a) What is the maximum initial thrust this rocket's engines can have but just barely avoid blackout? Start with a free-body diagram of the rocket. (b) What force, in terms of the astronaut's weight \(w\), does the rocket exert on her? Start with a free-body diagram of the astronaut. (c) What is the shortest time it can take the rocket to reach the speed of sound?

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