/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 116 Friction and Climbing Shoes. Sho... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Friction and Climbing Shoes. Shoes made for the sports of bouldering and rock climbing are designed to provide a great deal of friction between the foot and the surface of the ground. Such shoes on smooth rock might have a coefficient of static friction of 1.2 and a coefficient of kinetic friction of 0.90 . For a person wearing these shoes, what's the maximum angle (with respect to the horizontal) of a smooth rock that can be walked on without slipping? (a) \(42^{\circ} ;\) (b) \(50^{\circ} ;\) (c) \(64^{\circ} ;\) (d) larger than \(90^{\circ}\).

Short Answer

Expert verified
After calculation, we get that the maximum angle a person can walk on without slipping is approximately \( 50^{\circ} \), so the correct answer is (b) \( 50^{\circ} \).

Step by step solution

01

Understand the Concept of Friction

Friction is a force that resists the relative motion of solid surfaces, fluid layers, and material elements sliding against each other. In this case, we're interested in the static friction that exists between the climber's shoes and the rock surface. The maximum static friction force that can be exerted without causing an object to move can be calculated using the formula: \( F_{friction} = μ_{static} \cdot F_{normal} \). Here, \( μ_{static} \) is the coefficient of static friction and \( F_{normal} \) is the normal force.
02

Relate the Forces Involved

When a person is walking on a slope, the gravitational force that pulls the person downward can be split into two components: one parallel to the slope and the other one perpendicular to it. The maximum angle at which the person can walk without slipping is when the force parallel to the slope (\( F_{parallel} = mg \cdot sin(θ) \)) is equal to the maximum static friction force (\( F_{friction} = μ_{static} \cdot mg \cdot cos(θ) \)). Thus, we have the equation: \( mg \cdot sin(θ) = μ_{static} \cdot mg \cdot cos(θ) \). The mass (\( m \)) and acceleration due to gravity (\( g \)) will cancel out.
03

Determine the Maximum Walking Angle

Solving the previous equation for \( θ \), we get \( tan(θ) = μ_{static} \), which simplifies to \( θ = arc \ tan(μ_{static}) \). By substituting the given value for \( μ_{static} = 1.2 \), we can find the maximum angle \( θ \) that will make the person slip.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coefficient of Static Friction
The coefficient of static friction (\r \( \mu_{static} \) \r) is a dimensionless number that quantifies the ability of two surfaces to resist sliding motion when at rest relative to each other. When the coefficient is high, a greater force is required to overcome this resistance and initiate movement. In the context of climbing shoes, a higher \r \( \mu_{static} \) \r indicates better gripping capability, which is essential for climbers to maintain their position without slipping on steep rock faces.

For a climbing shoe with \r \( \mu_{static} \) \r of 1.2, this means the static friction force can be greater than the weight of the climber before slipping occurs. The high value is specifically designed to enhance safety and performance in climbing sports. By understanding \r \( \mu_{static} \) \r, climbers can select appropriate footwear based on the terrain's difficulty and the required grip strength.
Coefficient of Kinetic Friction
While the coefficient of static friction accounts for the resistance before movement starts, the coefficient of kinetic friction (\r \( \mu_{kinetic} \) \r) measures the resistance between two moving surfaces. It tends to be lower because once the motion has initiated, less force is required to maintain it compared to starting it.

The given coefficient of kinetic friction for climbing shoes is 0.90. This value plays a role once a climber's foot begins to slip on the rock. The shoes are designed to still provide considerable resistance against the motion, which can be crucial in preventing a fall mid-climb. For climbers, an understanding of \r \( \mu_{kinetic} \) \r is just as vital since it helps in maintaining control during dynamic movements where slight slips are possible.
Normal Force
The normal force (\r \( F_{normal} \) \r) is the component of contact force that is perpendicular to the surface upon which an object rests. It is equal in magnitude and opposite in direction to the component of the gravitational force pushing the object against the surface. For a climber on an incline, normal force plays a decisive role in determining how much static friction can be generated.

Considering a climber on a smooth rock with a certain incline, the normal force would be represented mathematically as \r \( F_{normal} = mg \cdot \cos(\theta) \) \r, with \r \( m \) \r representing mass, \r \( g \) \r gravitational acceleration, and \r \( \theta \) \r the angle of incline. As the angle increases, the normal force decreases, reducing the available static friction that is based on this normal force and thus affecting the climber's ability to maintain grip.
Maximum Static Friction Force
The maximum static friction force (\r \( F_{friction} \) \r) is the threshold at which static friction can no longer hold an object steady against the force that's trying to move it. It is given by the product of the coefficient of static friction and the normal force, \r \( F_{friction} = \mu_{static} \cdot F_{normal} \) \r.

This force is point-specific—it is the maximum amount of friction that can be exerted at the very instant before motion begins. For our climber, the maximum static friction force determines the steepest angle they can stand on without slipping. It sets the limit for their ascent and is crucial for safety. Mathematically, the balance between the gravitational component trying to pull the climber down the slope and the static friction resisting it defines the maximum angle of stability. This concept is at the heart of calculating safe climbing strategies and designing gear that allows climbers to push the boundaries of their sport.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The cosmo Clock 21 Ferris wheel in Yokohama, Japan, has a diameter of \(100 \mathrm{~m}\). Its name comes from its 60 arms, each of which can function as a second hand (so that it makes one revolution every \(60.0 \mathrm{~s}\) ). (a) Find the speed of the passengers when the Ferris wheel is rotating at this rate. (b) A passenger weighs \(882 \mathrm{~N}\) at the weight-guessing booth on the ground. What is his apparent weight at the highest and at the lowest point on the Ferris wheel? (c) What would be the time for one revolution if the passenger's apparent weight at the highest point were zero? (d) What then would be the passenger's apparent weight at the lowest point?

Friction in an Elevator. You are riding in an elevator on the way to the 18 th floor of your dormitory. The elevator is accelerating upward with \(a=1.90 \mathrm{~m} / \mathrm{s}^{2} .\) Beside you is the box containing your new computer; the box and its contents have a total mass of \(36.0 \mathrm{~kg} .\) While the elevator is accelerating upward, you push horizontally on the box to slide it at constant speed toward the elevator door. If the coefficient of kinetic friction between the box and the elevator floor is \(\mu_{\mathrm{k}}=0.32,\) what magnitude of force must you apply?

A large crate with mass \(m\) rests on a horizontal floor. The coefficients of friction between the crate and the floor are \(\mu_{\mathrm{s}}\) and \(\mu_{\mathrm{k}} .\) A woman pushes downward with a force \(\overrightarrow{\boldsymbol{F}}\) on the crate at an angle \(\theta\) below the horizontal. (a) What magnitude of force \(\vec{F}\) is required to keep the crate moving at constant velocity? (b) If \(\mu_{\mathrm{s}}\) is greater than some critical value, the woman cannot start the crate moving no matter how hard she pushes. Calculate this critical value of \(\mu_{\mathrm{s}}\)

A box with mass \(m\) sits at the bottom of a long ramp that is sloped upward at an angle \(\alpha\) above the horizontal. You give the box a quick shove, and after it leaves your hands it is moving up the ramp with an initial speed \(v_{0}\). The box travels a distance \(d\) up the ramp and then slides back down. When it returns to its starting point, the speed of the box is half the speed it started with; it has speed \(v_{0} / 2 .\) What is the coefficient of kinetic friction between the box and the ramp? (Your answer should depend on only \(\alpha\).)

A box with mass \(10.0 \mathrm{~kg}\) moves on a ramp that is inclined at an angle of \(55.0^{\circ}\) above the horizontal. The coefficient of kinetic friction between the box and the ramp surface is \(\mu_{\mathrm{k}}=0.300 .\) Calculate the magnitude of the acceleration of the box if you push on the box with a constant force \(F=120.0 \mathrm{~N}\) that is parallel to the ramp surface and (a) directed down the ramp, moving the box down the ramp; (b) directed up the ramp, moving the box up the ramp.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.