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A racetrack curve has radius \(90.0 \mathrm{~m}\) and is banked at an angle of \(18.0^{\circ} .\) The coefficient of static friction between the tires and the roadway is \(0.400 .\) A race car with mass \(1200 \mathrm{~kg}\) rounds the curve with the maximum speed to avoid skidding. (a) As the car rounds the curve, what is the normal force exerted on it by the road? What are the car's (b) radial acceleration and (c) speed?

Short Answer

Expert verified
The normal force exerted on the car by the road is 11217N. The car's radial acceleration is 6.22 m/s^2 and its maximum speed is 23.6 m/s.

Step by step solution

01

Calculating Normal Force

First of all, find the components of gravitational force. To do this, break it down into two components: one perpendicular to the road's surface and the other parallel to the surface. The perpendicular component is given by \( mg\cos \theta \), where \( m \) is the mass of the car, \( g \) is the gravitational force and \( \theta \) is the angle of the banked curve. The parallel component of the gravitational force is given by \( mg\sin \theta \). In equilibrium, the total force on the car perpendicular to the road surface should be zero. The perpendicular component of gravitational force is balanced by the normal force. Therefore, the normal force \( F_N \) is \( F_N = mg\cos \theta \). Plugging in the given values, we get \( F_N = 1200kg * 9.8 m/s^2 * \cos18^{\circ} = 11217N \).
02

Calculating Radial Acceleration

The radial acceleration (also called centripetal acceleration) of the car can be determined using the formula: \( a_r = \frac{v^2}{r} \). Here \(v\) is the velocity of the car and \(r\) is the radius of the curve. The maximum velocity before skidding occurs when the friction between the tires and road is maximum. This friction is equal to \( uF_N \), where \( u \) is the coefficient of static friction. The equilibrium in the radial direction implies that the radial acceleration times mass (\(a_r m\)) is equal to the sum of the horizontal (radial) component of gravitational force and friction. Combining these two equations we get: \( u mg \cos \theta = m a_r - mg \sin \theta \) hence \( a_r = g(u \cos \theta + \sin \theta) \). Substituting the given values we get \( a_r = 9.8m/s^2 * (0.4 \cos 18^{\circ} + \sin 18^{\circ}) = 6.22 m/s^2 \).
03

Calculating Maximum Speed

The maximum speed can be found by rearranging the equation for centripetal acceleration: \( v = \sqrt{a_rr} \). After substitution the given values, we get \( v = \sqrt{6.22 m/s^2 * 90.0 m} = 23.6 m/s \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Static Friction
Static friction is the force that keeps an object at rest when other forces try to move it. It acts between two surfaces, preventing them from sliding past each other. In this exercise, static friction plays a crucial role in allowing the race car to navigate the banked curve without skidding.

This frictional force depends on two factors:
  • The normal force (perpendicular force) exerted by the road on the tires.
  • The coefficient of static friction, which is a measure of the stickiness between the two surfaces.
The maximum static frictional force can be calculated using the formula: \[ f_s = ext{coefficient of static friction} imes ext{normal force} \]This means it's important to know the normal force, as it directly influences the frictional force that prevents skidding.

When cornering, if the centripetal force, required to keep the car moving in a circle, exceeds this maximum static frictional force, the car will begin to skid. However, as long as the frictional force is greater than or equal to the required centripetal force, the car remains securely on the track.
Centripetal Acceleration
Centripetal acceleration is crucial for understanding how objects move in circular paths. It is the acceleration directed towards the center of the circle, keeping the object moving along the curve. For this exercise, the race car experiences centripetal acceleration as it rounds the track.

The formula for centripetal acceleration is:\[ a_c = \frac{v^2}{r} \]where:
  • \( v \) is the velocity of the car.
  • \( r \) is the radius of the circular path.
Centripetal acceleration is always perpendicular to the velocity of the car because it's directed towards the center of the circle. This is a key requirement for maintaining circular motion.

In the context of this exercise, the balance of forces involves static friction and gravitational forces contributing toward generating enough centripetal acceleration to keep the car on track without skidding. The car’s speed determines how effectively this balance is achieved.
Normal Force
The normal force is a force exerted by a surface in response to an object resting on it. It acts perpendicular (or "normal") to the surface, which, in this scenario, is the banked curve of the racetrack.

On a flat surface, normal force usually equals the gravitational force exerted by the object (weight). However, on an inclined surface, such as the banked curve described, the normal force changes its magnitude because it's influenced by both gravity and the angle of the incline.

For a banked curve, the normal force is calculated as:\[ F_N = mg\cos(\theta) \]Here,
  • \( m \) is the mass of the race car.
  • \( g \) is the acceleration due to gravity (approximately \(9.8 \text{m/s}^2\)).
  • \( \theta \) is the angle of the bank.
In this exercise, after computing this, the normal force acts as a stabilizing component, helping the car to effectively use static friction to maintain its trajectory and accommodate the necessary centripetal force for staying on the curved path.

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Most popular questions from this chapter

You are lowering two boxes, one on top of the other, down a ramp by pulling on a rope parallel to the surface of the ramp (Fig. E5.33). Both boxes move together at a constant speed of \(15.0 \mathrm{~cm} / \mathrm{s}\). The coefficient of kinetic friction between the ramp and the lower box is 0.444 , and the coefficient of static friction between the two boxes is 0.800 . (a) What force do you need to exert to accomplish this? (b) What are the magnitude and direction of the friction force on the upper box?

A flat (unbanked) curve on a highway has a radius of \(170.0 \mathrm{~m}\). A car rounds the curve at a speed of \(25.0 \mathrm{~m} / \mathrm{s}\). (a) What is the minimum coefficient of static friction that will prevent sliding? (b) Suppose that the highway is icy and the coefficient of static friction between the tires and pavement is only one-third of what you found in part (a). What should be the maximum speed of the car so that it can round the curve safely?

Friction and Climbing Shoes. Shoes made for the sports of bouldering and rock climbing are designed to provide a great deal of friction between the foot and the surface of the ground. Such shoes on smooth rock might have a coefficient of static friction of 1.2 and a coefficient of kinetic friction of 0.90 . For a person wearing these shoes, what's the maximum angle (with respect to the horizontal) of a smooth rock that can be walked on without slipping? (a) \(42^{\circ} ;\) (b) \(50^{\circ} ;\) (c) \(64^{\circ} ;\) (d) larger than \(90^{\circ}\).

An \(8.00 \mathrm{~kg}\) block of ice, released from rest at the top of a 1.50-m-long friction less ramp, slides downhill, reaching a speed of \(2.50 \mathrm{~m} / \mathrm{s}\) at the bottom. (a) What is the angle between the ramp and the horizontal? (b) What would be the speed of the ice at the bottom if the motion were opposed by a constant friction force of \(10.0 \mathrm{~N}\) parallel to the surface of the ramp?

Genesis Crash. On September \(8,2004,\) the Genesis spacecraft crashed in the Utah desert because its parachute did not open. The \(210 \mathrm{~kg}\) capsule hit the ground at \(311 \mathrm{~km} / \mathrm{h}\) and penetrated the soil to a depth of \(81.0 \mathrm{~cm}\). (a) What was its acceleration (in \(\mathrm{m} / \mathrm{s}^{2}\) and in \(g\) 's) assumed to be constant, during the crash? (b) What force did the ground exert on the capsule during the crash? Express the force in newtons and as a multiple of the capsule's weight. (c) How long did this force last?

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