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A hydrogen atom in the \(5 g\) state is placed in a magnetic field of \(0.600 \mathrm{~T}\) that is in the \(z\) -direction. (a) Into how many levels is this state split by the interaction of the atom's orbital magnetic dipole moment with the magnetic field? (b) What is the energy separation between adjacent levels? (c) What is the energy separation between the level of lowest energy and the level of highest energy?

Short Answer

Expert verified
The \(5g\) state of a Hydrogen atom under a \(0.600 T\) magnetic field splits into 8 levels. The energy separation between adjacent levels is approximately \(5.5646059964 × 10^{-24} J\) and the energy separation between the level of lowest energy and the level of highest energy is approximately \(3.8952241975 × 10^{-23} J\).

Step by step solution

01

Calculate Total Angular Momentum Quantum Number

The state of the hydrogen atom given in the problem is \(5g\). The alphabet 'g' indicates the value of total orbital angular momentum quantum number \(l\). For 'g', \(l = 4\). The total angular momentum quantum number \('j'\) is equal to \(l ± 1/2\). Since g state must have odd parity, only \(l - 1/2\) is allowed. Therefore, \(j = 4 - 1/2 = 3.5\)
02

Determining the Number of split levels

The \(5g\) state will split into multiple levels under a magnetic field. Each level corresponds to a magnetic quantum number \(m\), ranging from \(-j\) to \(+j\) in steps of one. Thus, a total of \([2j + 1]\) levels are formed which is \([2(3.5) + 1] = 8\) levels.
03

Calculating Energy Separation between Adjacent Levels

The energy separation (\(ΔE\)) between adjacent split levels according to the Zeeman effect is given by the equation: \(ΔE = μ_B * B\). Where \(μ_B\) is the Bohr magneton (\(9.274009994 × 10^{-24} J/T\)) and \(B\) is the magnetic field strength \((0.600 T)\). Upon calculation, \(ΔE \approx 5.5646059964 × 10^{-24} J\).
04

Energy Separation between Lowest and Highest Energy Levels

The energy difference between the highest and lowest energy levels is obtained by multiplying the difference in their \(m\) values with the energy separation between adjacent levels. Therefore, \(ΔE_{total} = m_{max} * ΔE - m_{min} * ΔE\), where \(m_{max} = j = 3.5\), \(m_{min} = -j = -3.5\). Calculating, \(ΔE_{total} \approx 3.8952241975 × 10^{-23} J\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Orbital Magnetic Dipole Moment
Imagine a tiny magnet with its north and south poles creating a magnetic field; this is akin to the orbital magnetic dipole moment produced by electrons as they whirl around an atomic nucleus. In the depths of the atom, negatively charged electrons orbit the nucleus, similar to the Earth circling the sun.

As electrons move, they generate a current, and with this current comes a magnetic field, hence an orbital magnetic dipole moment. It's a vector quantity, meaning it has both a magnitude and direction. This intrinsic property of electrons is critical to understanding the Zeeman effect, as it interacts with external magnetic fields to produce the phenomenon we observe.

The presence of an external magnetic field can affect the energy levels within an atom, causing a slight shift or splitting. In the case of our hydrogen atom exercise, we’ve seen that the magnetic field split the previously degenerate energy levels into distinct ones based on their interaction with the field.
Angular Momentum Quantum Number
Angular momentum in the quantum world is far from the classic spinning-top image we might have. Instead, it's quantized, meaning it can only take on certain discrete values. This is where the angular momentum quantum number, denoted by \(l\), comes into play.

Each electron in an atom has an associated \(l\) that dictates its orbital shape and contributes to its total angular momentum. The values of \(l\) are whole numbers ranging from 0 to \(n-1\), where \(n\) is the principal quantum number associated with an electron's energy level.

In the exercise we're dissecting, the hydrogen atom is in the \(5g\) state, which reveals that \(l\) is 4, as the letter 'g' corresponds to an \(l\) value of 4 in spectroscopic notation. Thus, the angular momentum quantum number is instrumental in grating the energy state of an atom's electron and comprehending the influence of magnetic fields upon them.
Bohr magneton
As we delve deeper into atomic physics, we encounter the Bohr magneton \( (\text{\(\text{μ}_B\)}) \), a fundamental physical constant that symbolizes the tiniest unit of magnetic moment measurable at the electron or proton level. Put simply, it's the magnetic moment equivalent of one electron orbiting one proton at the smallest orbit where quantum mechanics is significant.

Expressed in joules per tesla (J/T), the Bohr magneton has a value of approximately \(9.274009994 × 10^{-24} J/T\), illustrating the proportionality between the magnetic moment and the magnetic field strength. This constant is pivotal in the calculation of magnetic phenomena such as the Zeeman effect, where it helps determine the energy differences between split magnetic energy levels, as seen in our exercise example.
Magnetic Quantum Number
Our quantum journey takes us next to the magnetic quantum number, symbolized by \(m\) or \(m_l\). This number gives insight into the orientation of an electron's angular momentum in relation to an external magnetic field's direction.

The value of \(m\) within an atom can span from -\(l\) to +\(l\), incorporating all the integers in between. This range means that for each energy state characterized by an angular momentum quantum number \(l\), there are \(2l + 1\) possible magnetic quantum numbers, each pertaining to a specific electron orbit orientation.

When we apply an external magnetic field, as in the Zeeman effect, each level associated with a distinct \(m\) might shift differently, giving rise to the splitting of energy levels into as many levels as there are possible values of \(m\). In the case of the hydrogen atom from the exercise, where \(l=4\), the field leads to an 8-level split as \(m\) ranges from -3.5 to +3.5.

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Most popular questions from this chapter

The hydrogen spectrum includes four visible lines. Of these, the blue line corresponds to a transition from the \(n=5\) shell to the \(n=2\) shell and has a wavelength of \(434 \mathrm{nm}\). If we look closer, this line is broadened by fine structure due to spin-orbit coupling and relativistic effects. (a) How many different sets of \(l\) and \(j\) quantum numbers are there for the \(n=5\) shell and for the \(n=2\) shell? (b) How many different energy levels are there for \(n=5\) and for \(n=2 ?\) For each of these levels, what is their energy difference in eV from \(-(13.6 \mathrm{eV}) / n^{2} ?\) (c) In a transition that emits a photon the quantum number \(l\) must change by \(\pm 1 .\) Which transition in the fine structure of the hydrogen blue line emits a photon of the shortest wavelength? For this photon what is the shift in wavelength due to the fine structure? (d) Which transition in the fine structure emits a photon of the longest wavelength? For this photon what is the shift in wavelength due to the fine structure? (e) By what total extent, in \(\mathrm{nm}\), is the wavelength of the blue line broadened around the \(434 \mathrm{nm}\) value?

CP Classical Electron Spin. (a) If you treat an electron as a classical spherical object with a radius of \(1.0 \times 10^{-17} \mathrm{~m}\), what angular speed is necessary to produce a spin angular momentum of magnitude \(\sqrt{\frac{3}{4}} h ?\) (b) Use \(v=r \omega\) and the result of part (a) to calculate the speed \(v\) of a point at the electron's cquator. What does your result suggest about the validity of this model?

When our sun exhausts its nuclear fuel, it will ultimately shrink due to gravity and become a white dwarf, with a radius of approximately \(7000 \mathrm{~km}\). (a) Using the mass of the sun, \(M_{\text {sun }}=2.0 \times 10^{30} \mathrm{~kg}\). and the mass of a proton, \(M_{\text {proton }}=1.7 \times 10^{-27} \mathrm{~kg}\). estimate the number of electrons in the sun. (b) From the radius given, estimate the average volume to be occupied by each electron in the eventual white dwarf. (c) The white dwarf will consist of mostly carbon. Since there are six clectrons in each carbon atom, multiply the volume of an electron by 6 to obtain the volume of each carbon atom. (d) Model the atomic arrangement as a cubical lattice and use your earlier estimate to determine the distance \(L\) between adjacent carbon nuclei. (e) View each atom as an \(L \times L \times L\) box filled with six electrons. Since no two clectrons can be in the same quantum state, what quantum numbers \(\left(n_{X}, n_{Y}, n_{Z}, m_{z}\right)\) are associated with these six electrons, where \(m_{z}\) is the quantum number for the component of the electron spin along the z-axis? (f) Ignoring contributions from spin couplings and Coulomb interactions between the electrons, what would be the energy of the higher- energy electrons?

Calculate the energy difference between the \(m_{y}=\frac{1}{2}("\) spin \(\left.u p^{\prime \prime}\right)\) and \(m_{s}=-\frac{1}{2}\left("_{\text {spin }}\right.\) down" \()\) levels of a hydrogen atom in the \(1 s\) state when it is placed in a \(1.45 \mathrm{~T}\) magnetic field in the negative z-direction. Which level, \(m_{s}=\frac{1}{2}\) or \(m_{s}=-\frac{1}{2},\) has the lower energy?

Consider the seventh excited level of the hydrogen atom. (a) What is the energy of this level? (b) What is the largest magnitude of the orbital angular momentum? (c) What is the largest angle between the orbital angular momentum and the z-axis?

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