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Consider the seventh excited level of the hydrogen atom. (a) What is the energy of this level? (b) What is the largest magnitude of the orbital angular momentum? (c) What is the largest angle between the orbital angular momentum and the z-axis?

Short Answer

Expert verified
The energy of the seventh excited level is -0.2125 eV, the maximum magnitude of the orbital angular momentum is √56ħ, and the largest angle between the orbital angular momentum and the z-axis is 180°.

Step by step solution

01

Calculation of Energy

The energy level of an atom is given by the formula \( E_n = E_1/n^2 \), where \( E_1 = -13.6 \) eV is the ground state energy level and \( n \) is the principal quantum number. For the seventh excited state of hydrogen atom, \( n=8 \) (since n starts from \( n=1 \) for the ground state). Thus, the energy of this level is \( E_8 = -13.6 / 8^2 = -0.2125 \) eV.
02

Determine Orbital Angular Momentum

The maximum magnitude of orbital angular momentum is given by the formula \(L_max = √l(l+1)ħ\), where \( l \) is the orbital quantum number and \( ħ \) is the reduced Planck's constant. For the n=8 state, the maximum value of \( l \) is 7. Therefore, \( L_{max} = √7(7+1)ħ = √56ħ \) .
03

Calculate the Largest Angle

The largest angle \( α \) between the orbital angular momentum and z-axis is obtained when the z-component of the orbital angular momentum is at its minimum, i.e., \( m_l = -l \). The z-component of the orbital angular momentum is given by \( L_z = m_lħ \). The angle is determined by the equation \( cos(α) = L_z/L = m_l/l \). For the minimum \( m_l \) i.e., \( m_l = -l = -7 \), \( cos(α) = -1 \), giving \( α = 180° \)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Quantum Numbers
The concept of quantum numbers is fundamental to the study of quantum mechanics and the structure of the atom. Quantum numbers are a set of numerical values that describe the unique quantum state of an electron in an atom. There are four primary quantum numbers: the principal quantum number (), the azimuthal (or angular momentum) quantum number (), the magnetic quantum number (), and the spin quantum number ().

The principal quantum number () is related to the electron's energy level and determines the size and energy of an orbital where the electron can be found. For the hydrogen atom in the exercise, in its seventh excited state, we have (=8), indicating the electron is in the eighth energy level. Larger values of () mean higher energy levels and greater distances from the nucleus.
  • The azimuthal quantum number (), also known as the orbital angular momentum quantum number, defines the shape of the orbital and has integer values ranging from 0 to (-1). In our case, for (=8), () can be any integer from 0 to 7.
  • The magnetic quantum number (), associated with the orientation of the orbital in space, ranges from (-_) to (+_), including zero.
  • The spin quantum number () describes the electron's intrinsic spin, with possible values of (+1/2) or (-1/2).
The comprehension of these quantum numbers aids students in visualizing the probable location and behavior of electrons within an atom, paving the way for further concepts such as orbital angular momentum.
Orbital Angular Momentum

Quantifying an Electron's Movement

Orbital angular momentum plays a pivotal role in the characterization of an electron's movement within an atom. It's a measure of the amount of rotation an electron has around the nucleus, quantified by the azimuthal quantum number (). This physical quantity brings some of the classical mechanics concepts into the quantum realm and is given by the expression (_ = √_(+1)ħ), with () being the azimuthal quantum number and () representing the reduced Planck's constant. In our exercise, for the principal quantum number (=8), the maximum value of () is 7, thus the calculated maximum orbital angular momentum is (__ax = √56ħ).

Orbital Shape and Electron Clouds

The orbital quantum number is also intrinsically linked to the shape of the orbitals where electrons reside, defining the electron clouds that make up the atom's structure. Each value of () correlates with a particular orbital shape: s (spherical), p (dumbbell-shaped), d (cloverleaf), and f (complex shapes). The different shapes imply different possibilities for the electron's location and hence its energy state.

A full grasp of orbital angular momentum is crucial for students as it bridges the gap between visualizing an atom's structure and understanding the dynamic behavior of electrons.
Energy Levels in Atoms
Atoms are made up of protons, neutrons, and electrons, with the electrons residing in energy levels or shells around the nucleus. This concept is essential for explaining the structure and behavior of atoms. Each energy level corresponds to a specific principal quantum number (), and the energy associated with each level can be calculated with the formula (_n = _1/n^2), where (_1) is the ground state energy level. The ground state is the lowest energy state of the atom, and for hydrogen, this value is (-13.6 eV).

Excited States and Photon Emission

When atoms absorb energy, electrons can be 'excited' to higher energy levels, and subsequently, when they return to lower energy levels, they emit energy in the form of photons. The energy of these photons corresponds to the difference between the two energy levels. In our exercise, the energy for the seventh excited state of a hydrogen atom (which is actually the eighth energy level, (=8)), is calculated to be (-0.2125 eV).

Understanding energy levels helps to explain the emission spectra of elements, the formation of ions, and the chemical behavior of atoms. This knowledge is not only academically interesting but also lays the groundwork for applications in fields such as spectroscopy, quantum computing, and chemical bonding theories.

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Most popular questions from this chapter

Spin- \(\frac{3}{2}\) particles have four distinct spin states corresponding to \(S_{z}=m_{z} h,\) where \(m_{z}\) may be \(\pm \frac{1}{2}\) or \(\pm \frac{3}{2} .\) We can write the corresponding normalized wave functions as \(\psi_{m_{i}}(\vec{r})\). (a) What is the magnitude of such a particle's spin \(\vec{S} ?\) (b) Suppose we have three identical entangled spin- \(\frac{3}{2}\) particles, each sharing an equal probability for exhibiting \(m_{z}=\pm \frac{1}{2}\) or \(m_{z}=-\frac{3}{2}\) but a zero probability for being in the state \(m_{z}=+\frac{3}{2}\). The three-particle wave function is a sum of products such as \(\psi_{-1 / 2}\left(\vec{r}_{1}\right) \psi_{+1 / 2}\left(\vec{r}_{2}\right) \psi_{-3 / 2}\left(\vec{r}_{3}\right),\) which we abbreviate as \(\psi-1 / 2 \psi+1 / 2 \psi-3 / 2 \cdot\) (It is understood that the \(n\) th factor corresponds to the position \(\vec{r}_{n}\) ) Write the normalized three-particle wave function for the entangled state. Be mindful of the Pauli exclusion principal. (c) The three entangled particles are sent off in three different directions toward magnctic containment facilities \(A, B,\) and \(C\) located, respectively. at \(\vec{r}_{1,2,3},\) where they are captured and retained in circular orbits. After an hour, the particle in facility \(A\) is sent through a Stern-Gerlach magnet, where it is determined that its state is \(m_{2}=+\frac{1}{2}\). What is the threeparticle wave function after this measurement? (d) At this time, what is the probability that a measurement in facility \(B\) will show that its particle is in each of the states \(m_{z}=-\frac{1}{2},+\frac{1}{2},-\frac{3}{2},\) and \(+\frac{3}{2} ?\) (e) Subsequently. the particle in facility \(C\) is measured to have \(m_{z}=-\frac{3}{2} .\) What is the wave function after this measurement? (f) At this time, what is the probability that a measurement in facility \(B\) will show that its particle is in each of the states \(m_{z}=-\frac{1}{2},+\frac{1}{2},-\frac{3}{2},\) and \(+\frac{3}{2} ?\)

A hydrogen atom is in a state that has \(L_{z}=2 h .\) In the semiclassical vector model, the angular momentum vector \(\overrightarrow{\boldsymbol{L}}\) for this state makes an angle \(\theta_{L}=63.4^{\circ}\) with the \(+z\) -axis. (a) What is the \(l\) quantum number for this state? (b) What is the smallest possible \(n\) quantum number for this state?

Make a list of the four quantum numbers \(n, l, m_{l},\) and \(m_{x}\) for each of the 10 electrons in the ground state of the neon atom. Do not refer to Table 41.2 or 41.3

A particle is in a three-dimensional cubical box that has side length \(L\). For the state \(n_{X}=3, n_{Y}=2,\) and \(n_{Z}=1,\) for what planes (in addition to the walls of the box is the probability distribution function zero?

Take the size of a Rydberg atom to be the diameter of the orbit of the excited electron. If the researchers want to perform this experiment with the rubidium atoms in a gas, with atoms separated by a distance 10 times their size, the density of atoms per cubic centimeter should be about (a) \(10^{5}\) atoms \(/ \mathrm{cm}^{3} ;\) (b) \(10^{8}\) atoms \(/ \mathrm{cm}^{3} ;\) (c) \(10^{11}\) atoms \(/ \mathrm{cm}^{3}\) (d) \(10^{21}\) atoms \(/ \mathrm{cm}^{3}\).

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