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Consider a wave function given by \(\psi(x)=A \sin k x,\) where \(k=2 \pi / \lambda\) and \(A\) is a real constant. (a) For what values of \(x\) is there the highest probability of finding the particle described by this wave function? Explain. (b) For which values of \(x\) is the probability zero? Explain.

Short Answer

Expert verified
For the highest probability, the values of \(x\) are given by \(\frac{\pi}{2 k} + \frac{n \pi}{k}\), where \(n\) is any integer. The probability is zero wherever \(x= \frac{n \pi}{k}\), where \(n\) is an integer.

Step by step solution

01

Determine the absolute maximum points of the wave function

The maximum probability of finding the particle corresponds to the absolute maximum points of the wave function. To find these points, one needs to find the maximum points of the wave function \(\psi(x)=A \sin k x\). The function \(\sin kx\) has maximum points where it equals to 1. So, solve the equation \(A \sin k x = A\) for \(x\). Since \(\sin k x = 1\), it means \(k x= \frac{\pi}{2} + n \pi\), where \(n\) is any integer. Therefore, \(x= \frac{\pi}{2 k} + \frac{n \pi}{k}\).
02

Determine the points where the wave function equals zero

The probability of finding the particle is zero wherever the wave function equals zero. So, solve the equation \(\psi(x)=A \sin k x = 0\) for \(x\). This results to \(k x = n \pi\), where \(n\) is any integer, and gives \(x= \frac{n \pi}{k}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quantum Mechanics
Quantum mechanics is a fundamental theory in physics that seeks to explain the behavior of matter and energy at the smallest scales, such as atoms and subatomic particles. It differs from classical physics mainly because it introduces the concept of probabilities and uncertainties. Instead of predicting exact outcomes, quantum mechanics uses probability to describe various potential outcomes.

In this domain, particles act in ways that defy classic intuitions, and understanding these behaviors often involves complex mathematical equations. Quantum mechanics heavily relies on wave functions to predict the probability of a particle's properties. The theory employs mathematical constructs like wave equations to express phenomena never fully grasped in classical terms.
  • Wave functions describe the quantum state of a system and contain all the necessary information.
  • Probabilities in quantum mechanics follow from the square of the wave function's amplitude.
Despite its complexities, quantum mechanics is crucial for the advancement of technology, from computing to medical imaging.
Probability Amplitude
The probability amplitude is central to calculating the likelihood of various quantifiable outcomes in quantum mechanics. It's essentially the value of a wave function at a given point, with its square giving the probability density.

For instance, if a particle is described by wave function \( \psi(x) = A \sin(kx) \), the function provides insight into the particle's position:
  • The square of the amplitude, \( |\psi(x)|^2 \), represents the probability density at position \( x \).
  • To find the probability of the particle's location within a certain range, integrate the probability density over that range.
This concept helps physicists predict where particles might be, which is crucial in fields like quantum chemistry and electronic engineering.
Particle in a Box
A classic problem in quantum mechanics is the particle in a box, which illustrates the principles of quantum behavior under constraints. The particle is confined in a perfectly rigid box where it can only occupy certain energies. The wave function \( \psi(x) = A \sin(kx) \) describes how the particle behaves within the box.

Key characteristics of the particle in a box:
  • The wave function has fixed endpoints, meaning \( \psi(x) \) must be zero at the box's boundaries.
  • The allowed energy states are quantized, meaning the particle can only occupy discrete energy levels.
  • The probability of finding a particle is highest at certain points, often the midpoint of the box.
This basic model introduces concepts of quantization and constraints affecting a particle's behaviors, leading to phenomena like tunneling.
Wave-Particle Duality
Wave-particle duality is a fundamental concept of quantum mechanics that explains how particles, like photons and electrons, exhibit both wave-like and particle-like properties. This duality is inherent in all quantum objects.

When considering a particle with a wave function, you can see it behaves like a wave in terms of interference and diffraction, and like a particle when it interacts such as with absorption or emission of light.
  • Wave behavior is observed in experiments like the double-slit experiment, where particles create interference patterns like waves.
  • Particle behavior is demonstrated by clear impacts seen in detectors.
The concept challenges the conventional distinction between particles and waves, pushing boundaries in how we understand the natural world. It is integral to developing technologies such as electron microscopes and lasers, demonstrating its practical significance.

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Most popular questions from this chapter

A particle moving in one dimension (the \(x\) -axis) is described by the wave function $$ \psi(x)=\left\\{\begin{array}{ll} A e^{-b x}, & \text { for } x \geq 0 \\ A e^{b x}, & \text { for } x<0 \end{array}\right. $$ where \(b=2.00 \mathrm{~m}^{-1}, A>0,\) and the \(+x\) -axis points toward the right. (a) Determine \(A\) so that the wave function is normalized. (b) Sketch the graph of the wave function. (c) Find the probability of finding this particle in each of the following regions: (i) within \(50.0 \mathrm{~cm}\) of the origin, (ii) on the left side of the origin (can you first guess the answer by looking at the graph of the wave function?), (iii) between \(x=0.500 \mathrm{~m}\) and \(x=1.00 \mathrm{~m}\).

Protons, neutrons, and many other particles are made of more fundamental particles called quarks and antiquarks (the antimatter equivalent of quarks). A quark and an antiquark can form a bound state with a variety of different energy levels, each of which corresponds to a different particle observed in the laboratory. As an example, the \(\psi\) particle is a low-energy bound state of a so-called charm quark and its antiquark, with a rest energy of \(3097 \mathrm{MeV} ;\) the \(\psi(2 \mathrm{~S})\) particle is an excited state of this same quark-antiquark combination, with a rest energy of \(3686 \mathrm{MeV}\). A simplified representation of the potential energy of interaction between a quark and an antiquark is \(U(x)=A|x|,\) where \(A\) is a positive constant and \(x\) represents the distance between the quark and the antiquark. You can use the WKB approximation (see Challenge Problem 40.64 ) to determine the bound- state energy levels for this potential-energy function. In the WKB approximation, the energy levels are the solutions to the equation $$ \int_{a}^{b} \sqrt{2 m[E-U(x)]} d x=\frac{n h}{2} \quad(n=1,2,3, \ldots) $$ Here \(E\) is the energy, \(U(x)\) is the potential-energy function, and \(x=a\) and \(x=b\) are the classical turning points (the points at which \(E\) is equal to the potential energy, so the Newtonian kinetic energy would be zero). (a) Determine the classical turning points for the potential \(U(x)=A|x|\) and for an energy \(E\). (b) Carry out the above integral and show that the allowed energy levels in the WKB approximation are given by $$ E_{n}=\frac{1}{2 m}\left(\frac{3 m A h}{4}\right)^{2 / 3} n^{2 / 3} \quad(n=1,2,3, \ldots) $$ (Hint: The integrand is even, so the integral from \(-x\) to \(x\) is equal to twice the integral from 0 to \(x .\) ) (c) Does the difference in energy between successive levels increase, decrease, or remain the same as \(n\) increases? How does this compare to the behavior of the energy levels for the harmonic oscillator? For the particle in a box? Can you suggest a simple rule that relates the difference in energy between successive levels to the shape of the potential-energy function?

An electron is bound in a square well that has a depth equal to six times the ground-level energy \(E_{1-\mathrm{IDW}}\) of an infinite well of the same width. The longest-wavelength photon that is absorbed by this electron has a wavelength of \(582 \mathrm{nm}\). Determine the width of the well.

A fellow student proposes that a possible wave function for a free particle with mass \(m\) (one for which the potential-energy function \(U(x)\) is zero) is $$ \psi(x)=\left\\{\begin{array}{ll} e^{+\kappa x}, & x<0 \\ e^{-\kappa x}, & x \geq 0 \end{array}\right. $$ where \(\kappa\) is a positive constant. (a) Graph this proposed wave function. (b) Show that the proposed wave function satisfies the Schrödinger equation for \(x<0\) if the energy is \(E=-\hbar^{2} \kappa^{2} / 2 m-\) that is, if the energy of the particle is negative. (c) Show that the proposed wave function also satisfies the Schrödinger equation for \(x \geq 0\) with the same energy as in part (b). (d) Explain why the proposed wave function is nonetheless not an acceptable solution of the Schrödinger equation for a free particle. (Hint: What is the behavior of the function at \(x=0 ?\) ) It is in fact impossible for a free particle (one for which \(U(x)=0\) ) to have an energy less than zero.

An electron with initial kinetic energy \(5.0 \mathrm{eV}\) encounters a barrier with height \(U_{0}\) and width \(0.60 \mathrm{nm}\). What is the transmission coefficient if (a) \(U_{0}=7.0 \mathrm{eV} ;\) (b) \(U_{0}=9.0 \mathrm{eV}\) (c) \(U_{0}=13.0 \mathrm{eV} ?\)

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