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\(\mathrm{A} \Sigma+\) particle has a mean lifetime of \(80.2 \mathrm{ps} .\) A physicist measures that mean lifetime to be 403 ps as the particle moves in his lab. The rest mass of the particle is \(2.12 \times 10^{-27} \mathrm{~kg} .\) (a) How fast is the particle moving? (b) How far does it travel, as measured in the lab frame, over one mean lifetime? (c) What are its rest, kinetic, and total energies in the lab frame of reference? (d) What are its rest, kinetic, and total energies in the particle's frame?

Short Answer

Expert verified
The relative velocity of the \(\Sigma+\) particle is approximately \(2.53 \times 10^8 \, m/s\). The distance it travels over one mean lifetime is approximately \(102 \, m\). In the lab frame, its rest energy is approximately \(1.9 \times 10^{-10} \, J\), its kinetic energy is \(7.6 \times 10^{-10} \, J\), and its total energy is \(9.5 \times 10^{-10} \, J\). In the particle's frame, its rest, kinetic, and total energies are \(1.9 \times 10^{-10} \, J\), \(0 \, J\), and \(1.9 \times 10^{-10} \, J\) respectively.

Step by step solution

01

Calculate Relative Velocity

From the problem, it can be seen that the time dilation formula \(\Delta t = \gamma \Delta t_0\) is applicable, where \(\Delta t = 403 \, ps\), the dilated time and \(\Delta t_0 = 80.2 \, ps\), the mean lifetime in the rest frame. Therefore, \(\gamma = \frac{\Delta t}{\Delta t_0}\). Given that \(\gamma = \frac{1}{\sqrt{1 - \frac{v^2}{c^2}}}\), isolate \(v\) to find the relative velocity:\(v = c \cdot \sqrt{1 - \frac{1}{\gamma^2}}\).
02

Calculate the Distance

The distance traveled by the particle in its mean lifetime in the lab frame is given by \(d = v\Delta t\). Multiply the velocity from Step 1 by the given dilated time to find the distance.
03

Calculate Rest, Kinetic, and Total Energies in the Lab Frame

The rest energy is given by \(E_{0} = mc^2\), where \(m\) is the rest mass of the particle and \(c\) is the speed of light. The total energy is given by \(E = \gamma mc^2\), and the kinetic energy is the difference between the total and rest energies, or \(K.E. = E - E_{0}\). Calculate these values using the respective formulae.
04

Calculate Rest, Kinetic, and Total Energies in the Particle's Frame

In the particle's frame, it isn't moving, hence its rest energy is the same as what was calculated in Step 3 \(E_{0} = mc^2\). Since it isn't moving, it doesn't have kinetic energy in its own frame, \(K.E. = 0\). The total energy is simply the rest energy, \(E = E_{0}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Relativity
Understanding relativity is crucial when analyzing problems involving high speeds comparable to the speed of light. It's the framework developed by Albert Einstein, best known through his Theory of General Relativity and Special Relativity. The latter is especially relevant here as it deals with objects moving at constant high speeds in straight lines, and it introduces the mind-bending concept that time is not absolute but relative—hence 'relativity.' This concept leads to what we call 'time dilation,' where a moving observer measures time to pass more slowly compared to a stationary observer. A practical consequence is that, for high-speed particles in physics experiments, we can observe them lasting longer, from our perspective, than they would if they were at rest. This connects directly to the exercise's scenario, where the \(\Sigma+\) particle's lifetime appears extended, illustrating the warping of spacetime due to its high velocity.
Mean Lifetime
The 'mean lifetime' of a particle, sometimes referred to as 'average lifetime,' is the average time a particle is expected to exist before decaying. This value is a probabilistic measure used in particle physics to describe the stability of subatomic particles. The mean lifetime is a rest frame property—meaning it's the time measured when the particle is not moving relative to the observer. When the particle is moving at speeds close to the speed of light, as observed in the lab frame, the measured lifetime becomes longer due to time dilation, which aligns with the exercise's observations. Time dilation directly affects the mean lifetime calculation, and this change is exactly what allows physicists to infer the speed of high-velocity particles without directly measuring their speed.
Rest Mass
Every elementary particle has an intrinsic property called 'rest mass,' sometimes simply called 'mass.' The rest mass is the mass that an object has when it is not in motion relative to an observer. It is a fundamental characteristic of particles and does not change regardless of the speed of the particle. In formulas involving relativity, rest mass is important because it helps us calculate both the rest energy of the particle using Einstein's famous equation \(E = mc^2\), and also its total energy when moving at high speeds. The concept of rest mass is pivotal in understanding how energy and momentum are linked in relativistic physics, as seen when calculating kinetic and total energies in the given exercise.
Kinetic Energy
Kinetic energy is the energy that an object possesses due to its motion. In classical physics, it's simply calculated as \(\frac{1}{2}mv^2\) where \(m\) is the mass, and \(v\) is the velocity of the object. However, this equation becomes insufficient at velocities approaching the speed of light, which is why relativistic physics provides a more comprehensive understanding. In the relativistic setting, kinetic energy is seen as the additional energy a particle gains due to its motion on top of its rest energy. It is derived from the total energy \(E\) minus the rest energy \(E_0 = mc^2\). The exercise provided is a prime example of applying these concepts to a real-world scenario, where the kinetic energy is a critical component in understanding the dynamics of subatomic particles.
Total Energy
Total energy in the context of relativity is the sum of an object's rest energy and its kinetic energy. Mathematically, it is represented as \(E = \gamma mc^2\), where \(\gamma\) is the Lorentz factor, which corrects for the effects of relativity at high speeds, \(m\) is the rest mass, and \(c\) is the speed of light. Unlike classical energy conservation, relativity tells us that mass and energy are interchangeable and so the total energy must account for kinetic, potential, and mass energies. The exercise demonstrates this by requiring the calculation of the total energy in the lab frame, where the particle is in motion, and also in the particle's frame, where the particle is at rest, thus its total energy is simply its rest energy. To understand any particle's behavior at relativistic speeds, grasping the concept of total energy is essential.

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Most popular questions from this chapter

Physicists and engineers from around the world came together to build the largest accelerator in the world, the Large Hadron Collider (LHC) at the CERN Laboratory in Geneva, Switzerland. The machine accelerates protons to high kinetic energies in an underground ring \(27 \mathrm{~km}\) in circumference. (a) What is the speed \(v\) of a proton in the \(\mathrm{LHC}\) if the proton's kinetic energy is \(7.0 \mathrm{TeV} ?\) (Because \(v\) is very close to \(c,\) write \(v=(1-\Delta) c\) and give your answer in terms of \(\Delta .\) ) (b) Find the relativistic mass, \(m_{\text {rel }}\), of the accelerated proton in terms of its rest mass.

One way to strictly enforce a speed limit would be to alter the laws of nature. Suppose the speed of light were \(65 \mathrm{mph}\) and your workplace was 30 miles from your home. Assume you travel to work at a typical driving speed of 60 mph. (a) If you drove at that speed for the round trip to and from work, light, how much would your wristwatch lag your kitchen clock each day? (b) Estimate the length of your car. (c) If you were driving at your estimated driving speed, how long would your car be when viewed from the roadside? (d) What would be the speed relative to you of similar cars traveling toward you in the opposite lane with the same ground speed as you? (e) How long would you measure those cars to be? (f) If the total mass of you and your car was \(2000 \mathrm{~kg}\), how much work would be required to get you up to speed? (Note: Your rest mass energy in this world is \(m c^{2}\), where \(c=65\) mph. ) (g) How much work would be required in the real world, where the speed of light is \(3.0 \times 10^{8} \mathrm{~m} / \mathrm{s},\) to get you up to speed?

(a) Through what potential difference does an electron have to be accelerated, starting from rest, to achieve a speed of \(0.980 c ?\) (b) What is the kinetic energy of the electron at this speed? Express your answer in joules and in electron volts.

Many of the stars in the sky are actually binary stars, in which two stars orbit about their common center of mass. If the orbital speeds of the stars are high enough, the motion of the stars can be detected by the Doppler shifts of the light they emit. Stars for which this is the case are called spectroscopic binary stars. Figure \(\mathbf{P 3 7 . 6 8}\) shows the simplest case of a spectroscopic binary star: two identical stars, each with mass \(m,\) orbiting their center of mass in a circle of radius \(R .\) The plane of the stars' orbits is edge-on to the line of sight of an observer on the earth. (a) The light produced by heated hydrogen gas in a laboratory on the earth has a frequency of \(4.568110 \times 10^{14} \mathrm{~Hz}\) In the light received from the stars by a telescope on the earth, hydrogen light is observed to vary in frequency between \(4.567710 \times 10^{14} \mathrm{~Hz}\) and \(4.568910 \times 10^{14} \mathrm{~Hz}\). Determine whether the binary star system as a whole is moving toward or away from the earth, the speed of this motion, and the orbital speeds of the stars. (Hint: The speeds involved are much less than \(c,\) so you may use the approximate result \(\Delta f / f=u / c\) given in Section \(37.6 .\) ) (b) The light from each star in the binary system varies from its maximum frequency to its minimum frequency and back again in 11.0 days. Determine the orbital radius \(R\) and the mass \(m\) of each star. Give your answer for \(m\) in kilograms and as a multiple of the mass of the sun, \(1.99 \times 10^{30} \mathrm{~kg} .\) Compare the value of \(R\) to the distance from the earth to the sun, \(1.50 \times 10^{11} \mathrm{~m}\). (This technique is actually used in astronomy to determine the masses of stars. In practice, the problem is more complicated because the two stars in a binary system are usually not identical, the orbits are usually not circular, and the plane of the orbits is usually tilted with respect to the line of sight from the earth.)

Einstein and Lorentz, avid tennis players, play a fast-paced game on a court where they stand \(20.0 \mathrm{~m}\) from each other. They play without a net. The tennis ball has mass \(0.0580 \mathrm{~kg} .\) Ignore gravity and assume that the ball travels parallel to the ground as it travels between the two players. Unless otherwise specified, all measurements are made by the two men. (a) Lorentz serves the ball at \(80.0 \mathrm{~m} / \mathrm{s}\). What is the ball's kinetic energy? (b) Einstein slams a return at \(1.80 \times 10^{8} \mathrm{~m} / \mathrm{s} .\) What is the ball's kinetic energy? (c) During Einstein's return of the ball in part (a), a white rabbit runs beside the court in the direction from Einstein to Lorentz. The rabbit has a speed of \(2.20 \times 10^{8} \mathrm{~m} / \mathrm{s}\) relative to the two men. What is the speed of the rabbit relative to the ball? (d) What does the rabbit measure as the distance from Einstein to Lorentz? (e) How much time does it take for the rabbit to run \(20.0 \mathrm{~m},\) according to the players? (f) The white rabbit uses his pocket watch to measure the time (as he sees it) for the distance from Einstein to Lorentz to pass by under him. What time does he measure?

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