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Physicists and engineers from around the world came together to build the largest accelerator in the world, the Large Hadron Collider (LHC) at the CERN Laboratory in Geneva, Switzerland. The machine accelerates protons to high kinetic energies in an underground ring \(27 \mathrm{~km}\) in circumference. (a) What is the speed \(v\) of a proton in the \(\mathrm{LHC}\) if the proton's kinetic energy is \(7.0 \mathrm{TeV} ?\) (Because \(v\) is very close to \(c,\) write \(v=(1-\Delta) c\) and give your answer in terms of \(\Delta .\) ) (b) Find the relativistic mass, \(m_{\text {rel }}\), of the accelerated proton in terms of its rest mass.

Short Answer

Expert verified
The results for the exercise are: \( \Delta \approx 8.065 * 10^{-9}\) and \( m_{rel} \approx 6,959 m_0\).

Step by step solution

01

Computing the Speed

Starting with the concept of kinetic energy \( K = \frac{1}{2} m v^2 \) (non-relativistic), since we deal with high energies where relativistic effects become noticeable, the form of the kinetic energy becomes \( K = (\gamma - 1) m_0 c^2 \), where \( \gamma = \frac{1}{\sqrt{1 - (v/c)^2}} \), \( m_0 \) is the proton's rest mass and \( c \) is the speed of light. Unfortunately, we cannot simply solve this equation for the speed \( v \), because it is contained inside the gamma function. So, we're asked to express \( v \) in terms of \( \Delta = c - v \) which turns our equation into a quadratic equation.
02

Solve the quadratic equation

The kinetic energy is given as \( 7.0 TeV = 7.0 * 10^{12} eV \). We express this energy in eV because the rest mass of a proton is given as \( m_0 = 938MeV/c^2 \). Rewriting the energy equation in terms of \( \Delta = 1 - \frac{v}{c}\), we get \(\frac{1}{2} m_0 c^2 (1 - \Delta)^2 = K\). Solving this quadratic equation results in \(\Delta = \frac{1}{2} ( - \sqrt{1 - \frac{8K}{m_0 c^2}} + 1).\)
03

Compute Relativistic Mass

The relativistic mass \(m_{rel}\) can be found using the equation \( m_{rel} = \gamma m_0 \) with \( \gamma = 1 / \sqrt{\Delta} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Energy of Protons
Understanding the kinetic energy of protons in high-energy physics is vital to comprehending experiments like those conducted at the Large Hadron Collider (LHC). At a basic level, kinetic energy represents the energy that an object possesses due to its motion. For objects moving at slow speeds, we can use the classical formula,

\( K = \frac{1}{2} mv^2 \),

where \( m \) is the mass of the object and \( v \) is its velocity. However, protons in the LHC are accelerated to near the speed of light, a regime where classical mechanics falls short. As a result, we must turn to Einstein's theory of special relativity, which introduces the concept of relativistic kinetic energy.
In the relativistic context, kinetic energy is given by:

\( K = (\gamma - 1)m_0c^2 \),

where \( \gamma \) is the Lorentz factor, \( m_0 \) is the rest mass of the proton, and \( c \) is the speed of light. Calculating the kinetic energy of a proton at these high speeds allows physicists to determine crucial properties of the particles, as well as to analyze the results of particle collisions with greater precision.
Relativistic Effects on Mass
One of the mind-bending predictions of Einstein’s Special Relativity is that an object's mass is not constant but rather depends on its speed. This relativistic effect on mass is particularly significant for particles traveling at speeds approaching the speed of light, such as protons in the LHC.
When protons are accelerated to high velocities, their relativistic mass, denoted as \( m_{rel} \), increases according to the Lorentz factor \( \gamma \). The relationship between the rest mass \( m_0 \), the relativistic mass, and the velocity \( v \) is given by:

\( m_{rel} = \gamma m_0 \).

Here, \( \gamma \) is the same factor from the kinetic energy equation and is defined as \( \gamma = \frac{1}{\sqrt{1 - (\frac{v}{c})^2}} \). As \( v \) approaches the speed of light \( c \), \( \gamma \) increases dramatically, resulting in a much larger relativistic mass compared to the rest mass. This significant increase in mass at high velocities plays a crucial role in the design and operation of accelerators like the LHC, as it affects the energy required to further accelerate the protons.
Computing Relativistic Speed
Computing the speed of protons in a high-energy physics setting involves relativistic equations due to their velocities being close to the speed of light. Since the kinetic energy equation includes the Lorentz factor \( \gamma \), solving directly for the speed \( v \) can be challenging. To address this, physicists rewrite the equation to define the speed in terms of a small difference \( \Delta \) from the speed of light.
By expressing \( v = (1 - \Delta)c \), where \( \Delta \) is a small number representing how much slower the proton is compared to the speed of light, we can form an equation that allows us to solve for \( \Delta \) given the kinetic energy of the proton. Once \( \Delta \) is known, the proton's speed can be easily calculated.
This approach is essential because directly measuring the speed at these magnitudes is not feasible with current technology. Instead, indirect methods such as computing \( \Delta \) leverage the established principles of relativity to infer the information needed to study particle interactions at a fundamental level. Understanding these methods is not just theoretical; it has practical implications in the control and analysis of experiments conducted at the forefront of particle physics.

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Most popular questions from this chapter

Two particles in a high-energy accelerator experiment approach each other head-on with a relative speed of \(0.890 c .\) Both particles travel at the same speed as measured in the laboratory. What is the speed of each particle, as measured in the laboratory?

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Two events are observed in a frame of reference \(S\) to occur at the same space point, the second occurring \(1.80 \mathrm{~s}\) after the first. In a frame \(S^{\prime}\) moving relative to \(S\), the second event is observed to occur \(2.15 \mathrm{~s}\) after the first. What is the difference between the positions of the two events as measured in \(S^{\prime} ?\)

What is the speed of a particle whose kinetic energy is equal to (a) its rest energy and (b) five times its rest energy?

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