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The positive muon \(\left(\mu^{+}\right),\) an unstable particle, lives on average \(2.20 \times 10^{-6} \mathrm{~s}\) (measured in its own frame of reference) before decaying. (a) If such a particle is moving, with respect to the laboratory, with a speed of \(0.900 c\), what average lifetime is measured in the laboratory? (b) What average distance, measured in the laboratory, does the particle move before decaying?

Short Answer

Expert verified
a) The average lifetime of the particle as measured in the laboratory is approximately \(7.33 \times 10^{-6} \, s\). b) The average distance the particle moves before decaying, as measured in the laboratory, is approximately \(1.96 \, km\).

Step by step solution

01

Apply Time Dilation

Time dilation is an actual difference of elapsed time between two events as measured by observers at different distances from a gravitational mass. The equation for time dilation is \(\Delta t = \frac{\Delta t_0}{\sqrt{1-v^2/c^2}}\) where \(\Delta t_0\) is the rest time, \(v\) is the relative speed, and \(c\) is speed of light. Here, \(\Delta t_0 = 2.20 \times 10^{-6}\,s\), \(v = 0.900c\), and \(c = 1\). Substitute known values into the equation, solve for \(\Delta t\).
02

Calculate Distance

Distance travelled is calculated by the simple relation \(d = vt\), where \(v\) is the velocity and \(t\) is the time. Using the calculated lab time from step 1 as \(t\) and \(v = 0.900c\) as desired velocity, substitute these values into this equation and solve for \(d\).
03

Evaluate the values

Calculation in both steps should lend reasonable values for lab time and distance travelled, fulfilling the goals of parts a and b of the exercise.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Muon decay
Muons are fascinating and short-lived particles observed in particle physics. They belong to the family of particles known as leptons, which also includes electrons. Muons are similar to electrons but are about 200 times heavier. Because of their heavy mass, muons are unstable and decay rapidly, mostly into electrons and neutrinos.

The specific muon discussed in this scenario is a positive muon (\(\mu^+\)), which has a very short average lifetime of 2.20 microseconds (\(2.20 \times 10^{-6} \mathrm{~s}\)), as measured in the muon's own reference frame. This time span represents the duration that the muon can exist before it begins to decay into other particles.
  • Muons decay via the weak nuclear force, a fundamental force in nature.
  • Despite their short lives, muons account for a significant number of cosmic ray particles that reach the Earth's surface.
Understanding the decay of muons is crucial for studying subatomic physics and cosmic radiation.
Relativity
Relativity is a theory in physics developed by Albert Einstein that dramatically altered our understanding of space and time. It introduces the idea that the laws of physics are the same for all observers, regardless of their relative motion.

This groundbreaking theory includes two types:
  • **Special Relativity**: Focuses on observers moving at constant speeds relative to each other. It introduces the famous equation \(E=mc^2\) and explains phenomena like time dilation and length contraction.
  • **General Relativity**: Extends the principles to include accelerated motion and gravity, describing how mass and energy cause the curvature of space-time.
In our specific case, we deal with Special Relativity. Through this concept, we can comprehend how time intervals and distances vary depending on the observer's relative motion. Relativity shows that time and space are interwoven as a space-time fabric, allowing us to understand the behavior of particles like muons when moving at high speeds relative to an observer in a laboratory.
Time dilation formula
Time dilation is one of the most intriguing predictions of Einstein's theory of relativity. It describes how the passage of time is affected by an object's velocity. As an object moves faster, time appears to slow down relative to an observer at rest. This effect becomes noticeable at speeds approaching the speed of light.

The time dilation formula is given by:\[\Delta t = \frac{\Delta t_0}{\sqrt{1-v^2/c^2}}\]
Where:
  • \(\Delta t\) is the time measured in the laboratory frame, also known as 'dilated time'.
  • \(\Delta t_0\) is the proper time measured in the moving object's rest frame.
  • \(v\) is the velocity of the moving object relative to the observer.
  • \(c\) is the speed of light in vacuum.
By applying this formula, we can determine how a muon moving at 90% the speed of light appears to the laboratory observer. This calculation reveals that the muon has a longer observed lifetime due to time dilation, explaining how muons created by cosmic rays high in the Earth's atmosphere can travel further across the surface before decaying.

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Most popular questions from this chapter

Many of the stars in the sky are actually binary stars, in which two stars orbit about their common center of mass. If the orbital speeds of the stars are high enough, the motion of the stars can be detected by the Doppler shifts of the light they emit. Stars for which this is the case are called spectroscopic binary stars. Figure \(\mathbf{P 3 7 . 6 8}\) shows the simplest case of a spectroscopic binary star: two identical stars, each with mass \(m,\) orbiting their center of mass in a circle of radius \(R .\) The plane of the stars' orbits is edge-on to the line of sight of an observer on the earth. (a) The light produced by heated hydrogen gas in a laboratory on the earth has a frequency of \(4.568110 \times 10^{14} \mathrm{~Hz}\) In the light received from the stars by a telescope on the earth, hydrogen light is observed to vary in frequency between \(4.567710 \times 10^{14} \mathrm{~Hz}\) and \(4.568910 \times 10^{14} \mathrm{~Hz}\). Determine whether the binary star system as a whole is moving toward or away from the earth, the speed of this motion, and the orbital speeds of the stars. (Hint: The speeds involved are much less than \(c,\) so you may use the approximate result \(\Delta f / f=u / c\) given in Section \(37.6 .\) ) (b) The light from each star in the binary system varies from its maximum frequency to its minimum frequency and back again in 11.0 days. Determine the orbital radius \(R\) and the mass \(m\) of each star. Give your answer for \(m\) in kilograms and as a multiple of the mass of the sun, \(1.99 \times 10^{30} \mathrm{~kg} .\) Compare the value of \(R\) to the distance from the earth to the sun, \(1.50 \times 10^{11} \mathrm{~m}\). (This technique is actually used in astronomy to determine the masses of stars. In practice, the problem is more complicated because the two stars in a binary system are usually not identical, the orbits are usually not circular, and the plane of the orbits is usually tilted with respect to the line of sight from the earth.)

\(\mathrm{A} \Sigma+\) particle has a mean lifetime of \(80.2 \mathrm{ps} .\) A physicist measures that mean lifetime to be 403 ps as the particle moves in his lab. The rest mass of the particle is \(2.12 \times 10^{-27} \mathrm{~kg} .\) (a) How fast is the particle moving? (b) How far does it travel, as measured in the lab frame, over one mean lifetime? (c) What are its rest, kinetic, and total energies in the lab frame of reference? (d) What are its rest, kinetic, and total energies in the particle's frame?

Muons are unstable subatomic particles that decay to electrons with a mean lifetime of \(2.2 \mu \mathrm{s}\) They are produced when cosmic rays bombard the upper atmosphere about \(10 \mathrm{~km}\) above the earth's surface, and they travel very close to the speed of light. The problem we want to address is why we see any of them at the earth's surface. (a) What is the greatest distance a muon could travel during its \(2.2 \mu\) s lifetime? (b) According to your answer in part (a), it would seem that muons could never make it to the ground. But the \(2.2 \mu \mathrm{s}\) lifetime is measured in the frame of the muon, and muons are moving very fast. At a speed of \(0.999 c,\) what is the mean lifetime of a muon as measured by an observer at rest on the earth? How far would the muon travel in this time? Does this result explain why we find muons in cosmic rays? (c) From the point of view of the muon, it still lives for only \(2.2 \mu \mathrm{s},\) so how does it make it to the ground? What is the thickness of the \(10 \mathrm{~km}\) of atmosphere through which the muon must travel, as measured by the muon? Is it now clear how the muon is able to reach the ground?

A nuclear bomb containing \(12.0 \mathrm{~kg}\) of plutonium explodes. The sum of the rest masses of the products of the explosion is less than the original rest mass by one part in \(10^{4}\). (a) How much energy is released in the explosion? (b) If the explosion takes place in \(4.00 \mu \mathrm{s}\) what is the average power developed by the bomb? (c) What mass of water could the released energy lift to a height of \(1.00 \mathrm{~km} ?\)

Spaceship \(A\) moves past the earth at \(0.80 c\) to the west. Spaceship \(B\) approaches \(A,\) moving to the east. Both spaceship crews measure their relative speed of approach to be \(0.98 c .\) What mass would the crews of both spaceships measure for the standard kilogram, kept at rest on the earth, (a) according to classical physics and (b) according to the special theory of relativity?

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