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What is the dc impedance of the electrode, assuming that it behaves as an ideal capacitor? (a) \(0 ;\) (b) infinite; (c) \(\sqrt{2} \times 10^{4} \Omega\) (d) \(\sqrt{2} \times 10^{6} \Omega\)

Short Answer

Expert verified
The DC impedance of the electrode, assuming that it behaves as an ideal capacitor, is infinite. So, the correct option is (b) infinite.

Step by step solution

01

Understand ideal capacitor properties

One key property of an ideal capacitor is that it has no electrical resistance, in other words, it does not dissipate electrical energy. Instead, it stores electrical energy in an electric field.
02

Understand impedance characteristics of an ideal capacitor

The impedance (Z) of a capacitor in an AC circuit is given by \(Z = 1/(2 \pi f C)\), where f is the frequency of the current and C is the capacitance. However, in a DC circuit, the frequency (f) is 0. So, if we substitute f=0 in the above formula, impedance is infinite since division by zero is undefined.
03

Conclude impedance of ideal capacitor in DC circuit

From the understanding of the capacitor's properties and the impedance equation, it is clear that at DC (where frequency is zero), the impedance of an ideal capacitor is infinite.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ideal Capacitor
An ideal capacitor is a fundamental component in electronic circuits. It is used to store electrical energy. Unlike a real-world capacitor, an ideal capacitor is considered perfect and without any imperfections. It does not lose energy and has no resistance. Instead, it stores energy entirely in the form of an electric field created between its plates.

In practical terms, this means:
  • There is no energy dissipation as heat.
  • It perfectly opposes changes in voltage across its plates.
  • Its only purpose is to store and release electrical energy effectively.
Its behavior is mainly explored with the help of the concept of impedance, which varies if the capacitor is in a Direct Current (DC) or Alternating Current (AC) circuit.
Electrical Resistance
Electrical resistance is a measure of the opposition to the flow of electric current in a conductor. It is an important concept in determining how easily electric current can pass through a material.

Resistance is often denoted by the symbol 'R' and is measured in units called ohms (Ω). Ohm's Law is a basic principle used to relate resistance with voltage and current, defined as: \[ V = I imes R \] where V is the voltage across a resistor, I is the current flowing through it, and R is the resistance of the resistor.
  • Materials with high resistance oppose electric current.
  • Materials with low resistance allow electric current to flow easily.
In the context of capacitors, an ideal capacitor exhibits zero resistance, hence no energy is dissipated as heat.
AC Circuit
Alternating Current (AC) circuits operate with a current that changes direction periodically. This distinguishing feature makes AC different from Direct Current (DC), where the flow of electric charge is in a single direction.

In an AC circuit, concepts such as impedance become crucial, particularly for components like capacitors and inductors, because these elements react differently to AC frequency changes. For capacitors in AC circuits, impedance is given by: \[ Z = \frac{1}{2 \pi f C} \]where \( Z \) is the impedance, \( f \) is the AC frequency, and \( C \) is the capacitance.
  • This equation shows that impedance decreases as frequency increases.
  • An ideal capacitor can easily store and release energy, depending on the frequency of the AC applied.
Unlike in a DC circuit, the continuous change in direction of current in AC circuits presents a dynamic interaction with capacitors.
Electric Field
An electric field is a region around a charged particle where electric forces act. For a capacitor, it is the field created between its plates when a voltage is applied. The strength of this field depends on the amount of voltage and the distance between the plates.

The electric field in a capacitor holds the energy stored in the capacitor. In an ideal capacitor:
  • Energy is stored without loss.
  • It is purely stored in the electric field between the plates.
The formula for electric field (E) between parallel plates in a capacitor is: \[ E = \frac{V}{d} \]where \( V \) is voltage and \( d \) is the separation between the plates.
This field is crucial for the functioning of the capacitor because it's responsible for storing energy, ready to be released when needed in the circuit.

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Most popular questions from this chapter

An inductor with \(L=9.50 \mathrm{mH}\) is connected across an ac source that has voltage amplitude \(45.0 \mathrm{~V}\). (a) What is the phase angle \(\phi\) for the source voltage relative to the current? Does the scurce voltage lag or lead the current? (b) What value for the frequency of the source results in a current amplitude of \(3.90 \mathrm{~A}\) ?31.3 an inductor with \(L=9.50 \mathrm{mH}\) is connected across an ac source that has voltage amplitude \(45.0 \mathrm{~V}\). (a) What is the phase angle \(\phi\) for the source voltage relative to the current? Does the scurce voltage lag or lead the current? (b) What value for the frequency of the source results in a current amplitude of \(3.90 \mathrm{~A}\) ?

A capacitance \(C\) and an inductance \(L\) are operated at the same angular frequency. (a) At what angular frequency will they have the same reactance? (b) If \(L=5.00 \mathrm{mH}\) and \(C=3.50 \mu \mathrm{F}\), what is the numerical value of the angular frequency in part (a), and what is the reactance of each element?

In an \(L-R-C\) series circuit, \(R=150 \Omega, L=0.750 \mathrm{H},\) and \(C=0.0180 \mu \mathrm{F}\). The source has voltage amplitude \(V=150 \mathrm{~V}\) and a frequency equal to the resonance frequency of the circuit. (a) What is the power factor? (b) What is the average power delivered by the source? (c) The capacitor is replaced by one with \(C=0.0360 \mu \mathrm{F}\) and the source frequency is adjusted to the new resonance value. Then what is the average power delivered by the source?

(a) Compute the reactance of a \(0.450 \mathrm{H}\) inductor at frequencies of \(60.0 \mathrm{~Hz}\) and \(600 \mathrm{~Hz}\). (b) Compute the reactance of a \(2.50 \mu \mathrm{F}\) capacitor at the same frequencies. (c) At what frequency is the reactance of a \(0.450 \mathrm{H}\) inductor equal to that of a \(2.50 \mu \mathrm{F}\) capacitor?

\(\operatorname{In}\) an \(L-R-C\) series circuit the source is operated at its resonant angular frequency. At this frequency, the reactance \(X_{C}\) of the capacitor is \(200 \Omega\) and the voltage amplitude across the capacitor is \(600 \mathrm{~V}\). The circuit has \(R=300 \Omega\). What is the voltage amplitude of the source?

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