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\(\operatorname{In}\) an \(L-R-C\) series circuit the source is operated at its resonant angular frequency. At this frequency, the reactance \(X_{C}\) of the capacitor is \(200 \Omega\) and the voltage amplitude across the capacitor is \(600 \mathrm{~V}\). The circuit has \(R=300 \Omega\). What is the voltage amplitude of the source?

Short Answer

Expert verified
The voltage amplitude of the source is equal to the voltage across the resistor which was calculated in step 2.

Step by step solution

01

Calculate Current

Firstly, find the current (I) in the circuit using Ohm's law. At resonance, the voltage across the capacitor (V_C) is given, and since X_C and R are in series, they share the same current. Use the equation I = V_C/X_C, with V_C = 600 V and X_C = 200 Ohm.
02

Calculate Voltage Across the Resistor

Next, determine the voltage across the resistor (V_R) using Ohm's Law. Voltage V equals to the current multiplied by the resistance - V = I * R. We got the current from the previous step and the resistance is known (R = 300 Ohm).
03

Calculate Source Voltage

Lastly, at the resonance, the voltage of the source (V_S) is the same as the voltage across the resistor (since the voltage across the inductor and capacitor cancel each other out). Therefore, V_S = V_R.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

L-R-C Series Circuit
An L-R-C series circuit is a simple yet fascinating configuration that combines a resistor (R), an inductor (L), and a capacitor (C) all connected in a single loop with a power source. It's a classic arrangement used in many electronic applications.

At the heart of this circuit is the concept of resonance. At a specific frequency, known as the resonant frequency, the circuit responds with maximum voltage or current. Interestingly, at this frequency, the reactive effects of the inductor and capacitor cancel each other out. This phenomenon means that the only opposition to the current flow comes from the resistance within the circuit.

This balance of forces is crucial, as it not only maximizes circuit efficiency but also stabilizes the voltage and current flow, which can be desirable in many practical applications, such as tuning radio frequencies or in AC power systems.
Ohm's Law
Ohm's Law is a fundamental principle in the world of electronics that describes the relationship between voltage, current, and resistance in an electrical circuit. According to Ohm's Law, the current flowing through a conductor between two points is directly proportional to the voltage across the two points. The formula is given by \( V = I \times R \).

Ohm's Law is incredibly useful because it allows us to calculate one electrical quantity if we know the values of the other two. For students and practitioners alike, understanding and applying Ohm's Law is essential for troubleshooting and designing electrical circuits. For instance, determining the current that a resistor will allow to flow in a circuit helps in predicting the behavior of the circuit under different voltages.
Reactance
Reactance is an important concept in AC circuits that represents the opposition to the change in current by an inductor or a capacitor. Unlike resistance, which opposes current equally at all times, reactance varies with frequency.

There are two types of reactance: inductive reactance (\(X_L\)) and capacitive reactance (\(X_C\)). Inductive reactance arises from inductors storing energy in a magnetic field, and it increases with higher frequency. Conversely, capacitive reactance comes from capacitors storing energy in an electric field, and it decreases with higher frequency. These properties cause inductors and capacitors to behave differently from resistors in an AC circuit.

The total reactance in a circuit influences how it responds to AC signals and is key to understanding phenomena like resonance in an L-R-C series circuit. At resonance, the reactances of the inductor and capacitor become equal and opposite, effectively canceling each other out and minimizing the overall impedance.
Voltage Amplitude
Voltage amplitude refers to the maximum absolute value of an electrical potential difference in a periodic waveform, typically in an AC circuit. It is an essential aspect because it represents the peak power capability of the source before any voltage drop occurs due to the resistance or reactance within the circuit.

In the context of an L-R-C circuit at its resonant frequency, knowing the voltage amplitude across any component can be very telling. For instance, the voltage amplitude across the capacitor not only reflects its energy storage capability but also indirectly indicates the overall energy that is flowing through the entire circuit at resonance. Moreover, by using the voltage amplitude in conjunction with Ohm's Law and knowledge of reactance, the calculation of other electrical quantities within the circuit becomes straightforward.

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Most popular questions from this chapter

A \( 200 \Omega\) resistor, \(0.900 \mathrm{H}\) inductor, and \(6.00 \mu \mathrm{F}\) capacitor are connected in series across a voltage source that has voltage amplitude \(30.0 \mathrm{~V}\) and an angular frequency of \(250 \mathrm{rad} / \mathrm{s}\). (a) What are \(v, v_{R}\), \(v_{L},\) and \(v_{C}\) at \(t=20.0 \mathrm{~ms} ?\) Compare \(v_{R}+v_{L}+v_{C}\) to \(v\) at this instant. (b) What are \(V_{R}, V_{L},\) and \(V_{C} ?\) Compare \(V\) to \(V_{R}+V_{L}+V_{C} .\) Explain why these two quantities are not equal.

You plan to take your hair dryer to Europe, where the electrical outlets put out \(240 \mathrm{~V}\) instead of the \(120 \mathrm{~V}\) seen in the United States. The dryer puts out \(1600 \mathrm{~W}\) at \(120 \mathrm{~V}\). (a) What could you do to operate your dryer via the \(240 \mathrm{~V}\) line in Europe? (b) What current will your dryer draw from a European outlet? (c) What resistance will your dryer appear to have when operated at \(240 \mathrm{~V}\) ?

A series circuit has an impedance of \(60.0 \Omega\) and a power factor of 0.720 at \(50.0 \mathrm{~Hz}\). The source voltage lags the current. (a) What circuit element, an inductor or a capacitor, should be placed in series with the circuit to raise its power factor? (b) What size element will raise the power factor to unity?

A toroidal solenoid has 2900 closely wound turns, cross-sectional area \(0.450 \mathrm{~cm}^{2},\) mean radius \(9.00 \mathrm{~cm},\) and resistance \(R=2.80 \Omega .\) Ignore the variation of the magnetic field across the cross section of the solenoid. What is the amplitude of the current in the solenoid if it is connected to an ac source that has voltage amplitude \(24.0 \mathrm{~V}\) and frequency \(495 \mathrm{~Hz} ?\)

Cell phones that use \(4 \mathrm{G}\) technology receive signals broadcast between \(2 \mathrm{GHz}\) and \(8 \mathrm{GHz}\) (a) If you want to create a simple \(L-R-C\) series circuit to detect a \(4.0 \mathrm{GHz}\) cell phone signal, what is the relevant value of the product \(L C,\) where \(L\) is the inductance and \(C\) is the capacitance? (b) If you choose a capacitor that has \(C=1.0 \times 10^{-15} \mathrm{~F}\), what inductance do you need? (c) Suppose you want to wind your own toroidal inductor and fit it inside a box as thin as your cell phone. Based on the size of your phone, estimate the largest cross- sectional area possible for this. (d) Assume the largest allowable radius of the toroid is \(1.0 \mathrm{~cm}\) and estimate the lowest number of windings needed to create your inductor, assuming the material inside has a relative permeability of 1 .

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