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A long. straight solenoid has 800 turns. When the current in the solenoid is \(2.90 \mathrm{~A}\), the average flux through each turn of the solenoid is \(3.25 \times 10^{-3} \mathrm{~Wb}\). What must be the magnitude of the rate of change of the current in order for the sclf-induced cmf to cqual \(6.20 \mathrm{mV} ?\)

Short Answer

Expert verified
The magnitude of the rate of change of the current should be \(2.38 \times 10^{-3} \mathrm{A/s}\)

Step by step solution

01

Calculate total magnetic flux

The total magnetic flux, \(\Phi\), in the solenoid is the product of the average flux through each turn of the solenoid and the total number of turns. The equation for total magnetic flux is \(\Phi = \text{number of turns} \times \text{flux per turn}\). Substituting given values, we get \(\Phi = 800 \times 3.25 \times 10^{-3} \mathrm{~Wb} = 2.6 \mathrm{~Wb}\).
02

Understanding Faraday's law of electromagnetic induction

By Faraday’s law of induction, the magnitude of the induced emf in a coil is equal to the rate of change of magnetic flux, or \(|\varDelta\Phi| = |emf|\cdot\Delta time\). Substituting gives \(|\varDelta\Phi| = |emf|\cdot\Delta time/(N \varDelta I)\).
03

Solve for rate of change of current

Rearrange the equation from step 2 to solve for the rate of change of the current: \(N \varDelta I = |emf|\cdot\Delta time/|\varDelta\Phi|\). Replacing the known values we get \(N \varDelta I = 6.20 \times 10^{-3} / 2.6 = 2.38 \times 10^{-3} \mathrm{A/s}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Faraday's Law of Induction
Imagine you have a loop of wire exposed to a magnetic field. As the magnetic field changes, whether by its strength or by the physical movement of the wire, an electric current is produced in the wire. This is the fundamental principle behind Faraday's law of induction. The law states that the induced electromotive force (emf) in any closed circuit is equal to the negative of the rate of change of the magnetic flux through the circuit. It can be mathematically represented as \( emf = -N\frac{d\Phi}{dt} \), where \( N \) is the number of turns in the coil, and \( \frac{d\Phi}{dt} \) is the rate of change of magnetic flux. Due to the negative sign, which stands for Lenz's Law, the induced emf always works to oppose the change in flux that produced it.
Magnetic Flux
Magnetic flux is a measure of the total magnetic field which passes through a given area. It's often compared to the flow of water; just as water flow measures the volume of water moving through an area per unit time, magnetic flux measures the strength and extent of magnetic fields. It is defined mathematically as \( \Phi = B \cdot A \cdot \cos(\theta) \), where \( B \) is the magnetic field strength, \( A \) is the area the field lines pass through, and \( \theta \) is the angle between the field lines and the normal (perpendicular) to the area. Measured in Webers (Wb), magnetic flux is a crucial component in understanding how electromotive forces are generated through Faraday's law.
Solenoid
A solenoid is essentially a coil of wire which, when electric current passes through it, creates a magnetic field. Think of it as a cylindrical roll of wire acting like a bar magnet with a north and south pole. This generated magnetic field has many practical applications, such as in electromagnets, inductors, and valves. In our example, the solenoid has multiple turns, and with each turn, the wire contributes to the total magnetic field inside the solenoid, making the inside field fairly uniform and very similar to that of a bar magnet. An important characteristic of a solenoid is that the magnetic field inside is directly proportional to the number of turns of the wire and the current passing through it.
Self-Induced Emf
When we talk about a self-induced emf, we're discussing an induced emf within the same circuit that caused it, often as a reaction to a change in current. This is a fundamental aspect of inductance, where a changing current in a coil produces a changing magnetic field, which in turn induces a voltage in the coil itself. This self-induced emf, according to Lenz's Law, will oppose the change in the current that caused it. In mathematical terms, it's given as \( emf = -L \frac{dI}{dt} \), where \( L \) is the inductance of the coil and \( \frac{dI}{dt} \) is the rate of change of current. In simpler terms, when the current through a solenoid changes, the solenoid generates an emf to resist that change.
Rate of Change of Current
The rate of change of current refers to how quickly the current is increasing or decreasing over time. It is a significant factor in electromagnetism and inductance, as it helps determine the magnitude of the induced emf in a circuit. As seen with our solenoid example, the rate at which the current changes directly affects the amount of emf that will be induced according to Faraday’s law. The quicker the change, the higher the induced emf. The mathematical representation for the rate of change of current is \( \frac{dI}{dt} \), which intuitively means 'the derivative of current with respect to time'. This rate plays a crucial role in the dynamics of circuits with inductors and is often a variable we want to control in electrical engineering to achieve the desired circuit behaviors.

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Most popular questions from this chapter

CP CALC A cylindrical solcnoid with radius \(1.00 \mathrm{~cm}\) and length \(10.0 \mathrm{~cm}\) consists of 300 windings of AWG 20 copper wirc, which has a resistance per length of \(0.0333 \Omega / \mathrm{m}\). This solenoid is connected in series with a \(10.0 \mu \mathrm{F}\) capacitor, which is initially uncharged. A magnetic ficld dirccted along the axis of the solcnoid with strength \(0.100 \mathrm{~T}\) is switched on abruptly. (a) The solenoid may be considered an inductor and a resistor in series. Use Faraday's law to determine the average emf across the solenoid during the brief switch-on interval, and determine the nct charge initially deposited on the capacitor. (Sec Excrcisc \(29.4 .)\) (b) At time \(t=0\) the capacitor is fully charged and there is no current. How much time does it take for the capacitor to fully discharge the first time? (c) What is the frequency with which the current oscillates? (d) IIow much energy is stored in the capacitor at \(t=0 ?\) (e) How long does it take for the total cnergy stored in the circuit to drop to \(10 \%\) of that value?

(a) What would have to be the self-inductance of a solenoid for it to store \(10.0 \mathrm{~J}\) of energy when a \(2.00 \mathrm{~A}\) current runs through it? (b) If this solenoid's cross-sectional diameter is \(4.00 \mathrm{~cm}\), and if you could wrap its coils to a density of 10 coils \(/ \mathrm{mm}\), how long would the solenoid be? (See Exercise \(30.11 .)\) Is this a realistic length for ordinary laboratory use?

Two coils have mutual inductance \(M=3.25 \times 10^{4}\) H. The current \(i_{1}\) in the first coil increases at a uniform rate of \(830 \mathrm{~A} / \mathrm{s}\). (a) What is the magnitude of the induced emf in the second coil? Is it constant? (b) Suppose that the current described is in the second coil rather than the first. What is the magnitude of the induced emf in the first coil?

An inductor with an inductance of \(2.50 \mathrm{II}\) and a resistance of \(8.00 \Omega\) is connected to the terminals of a battery with an emf of \(6.00 \mathrm{~V}\) and negligible internal resistance. Find (a) the initial rate of increase of current in the circuit; (b) the rate of increase of current at the instant when the current is \(0.500 \mathrm{~A}\) : (c) the current \(0.250 \mathrm{~s}\) after the circuit is closed; (d) the final steady-state current.

A solenoidal coil with 25 turns of wire is wound tightly around another coil with 300 turns (see Example 30.1 ). The inner solenoid is \(25.0 \mathrm{~cm}\) long and has a diameter of \(2.00 \mathrm{~cm}\). At a certain time, the current in the inner solenoid is \(0.120 \mathrm{~A}\) and is increasing at a rate of \(1.75 \times 10^{3} \mathrm{~A} / \mathrm{s}\). For this time, calculate: (a) the average magnetic flux through each turn of the inner solenoid; (b) the mutual inductance of the two solenoids; (c) the emf induced in the outer solenoid by the changing current in the inner solenoid.

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