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Two coils have mutual inductance \(M=3.25 \times 10^{4}\) H. The current \(i_{1}\) in the first coil increases at a uniform rate of \(830 \mathrm{~A} / \mathrm{s}\). (a) What is the magnitude of the induced emf in the second coil? Is it constant? (b) Suppose that the current described is in the second coil rather than the first. What is the magnitude of the induced emf in the first coil?

Short Answer

Expert verified
The magnitude of the induced emf is 26950 kV and it is constant. The same value applies if the current is in the second coil.

Step by step solution

01

From Given Variables to Faraday's Law

By definition, the induced emf is \(-M \cdot di/dt\). The mutual inductance \(M = 3.25 \times 10^{4}\) H and the rate of change of the current \(di/dt = 830 A/s\). Substitute these values into Faraday's law to find the magnitude of the induced emf.
02

Calculate The Induced EMF

Performing the multiplication, the magnitude of the induced emf is \(-3.25 \times 10^{4} \times 830 = -2695 \times 10^4 V\).
03

Determine If The EMF Is Constant

Since we are told that the current in the first coil is increasing at a uniform rate, \(di/dt\), is constant. Therefore, the induced emf will also be constant, as it is directly proportional to \(di/dt\).
04

Calculate The Induced EMF For The Reversed Case

It doesn't matter whether the current is in the first or second coil. This is because the second part of the question does not change the rate of current, nor the mutual inductance, thus, the induced EMF remains the same \(2695 \times 10^4 V\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mutual Inductance
Mutual inductance is a fundamental concept in electromagnetism that describes how the change in current in one coil can induce an electromotive force (emf) in another nearby coil. It is denoted by the symbol \( M \) and measured in henries (H). In our given exercise, the mutual inductance between two coils is \( M = 3.25 \times 10^{4} \) H. This indicates a strong coupling between the coils.

The concept of mutual inductance is crucial in understanding how transformers, induction coils, and many electrical devices operate. It allows for the transmission of electric energy between circuits without a physical connection.
  • When the current in the first coil changes, the magnetic field created by this current also changes.
  • This changing magnetic field then induces an emf in the second coil according to the same mutual inductance \( M \).
  • Thus, mutual inductance is a measure of how efficiently these coils are influencing each other.
Faraday's Law
Faraday's Law of electromagnetic induction is the principle that quantifies the induced emf in a coil due to the change in magnetic flux. According to Faraday's Law, the induced emf in a coil is proportional to the rate of change of current in a neighboring coil. The expression is given by:

\[\text{Induced emf} = -M \cdot \frac{di}{dt}\]
Here, the negative sign indicates the direction of the induced emf, following Lenz's law, which tries to oppose the change in current. In our example, we calculate the induced emf using the given mutual inductance \( M = 3.25 \times 10^{4} \) H and the rate of change of current \( \frac{di}{dt} = 830 \mathrm{~A/s} \).

These calculations are straightforward:
  • Calculate the product of mutual inductance \( M \) and the rate of change of current.
  • Apply the formula to find the magnitude of the induced emf.
  • Notably, if the current changes uniformly, the rate \( \frac{di}{dt} \) is constant, resulting in a constant induced emf.
Uniform Rate of Current Increase
A uniform rate of current increase means that the rate at which the current changes is consistent over time. In our exercise, the current in one of the coils increases uniformly at a rate of \( 830 \mathrm{~A/s} \). This consistency in the rate is crucial because:
  • It ensures that the induced emf remains constant over time, as obtained from Faraday's Law.
  • When an emf is induced due to a uniform change, it implies that the magnetic flux is changing at a constant rate, leading to a steady induced emf.
  • This helps in simplifying the analysis and calculations related to electromagnetic induction, making these scenarios easier to handle in practical applications.
In practical situations, maintaining a uniform rate of change can be challenging, but it simplifies many real-world applications and analyses, such as in designing circuits and coils. These properties are leveraged in devices like transformers where a consistent change is crucial for reliable performance.

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Most popular questions from this chapter

\(\operatorname{An} L-C\) circuit containing an \(80.0 \mathrm{ml}\) inductor and a \(1.25 \mathrm{nF}\) capacitor oscillates with a maximum current of 0.750 A. Calculate: (a) the maximum charge on the capacitor and (b) the oscillation frequency of the circuit. (c) Assuming the capacitor had its maximum charge at time \(t=0,\) calculate the energy stored in the inductor after \(2.50 \mathrm{~ms}\) of oscillation.

CP CALC A cylindrical solcnoid with radius \(1.00 \mathrm{~cm}\) and length \(10.0 \mathrm{~cm}\) consists of 300 windings of AWG 20 copper wirc, which has a resistance per length of \(0.0333 \Omega / \mathrm{m}\). This solenoid is connected in series with a \(10.0 \mu \mathrm{F}\) capacitor, which is initially uncharged. A magnetic ficld dirccted along the axis of the solcnoid with strength \(0.100 \mathrm{~T}\) is switched on abruptly. (a) The solenoid may be considered an inductor and a resistor in series. Use Faraday's law to determine the average emf across the solenoid during the brief switch-on interval, and determine the nct charge initially deposited on the capacitor. (Sec Excrcisc \(29.4 .)\) (b) At time \(t=0\) the capacitor is fully charged and there is no current. How much time does it take for the capacitor to fully discharge the first time? (c) What is the frequency with which the current oscillates? (d) IIow much energy is stored in the capacitor at \(t=0 ?\) (e) How long does it take for the total cnergy stored in the circuit to drop to \(10 \%\) of that value?

{A} 6.40 \mathrm{nF} \text { capacitor is charged to } 24.0 \mathrm{~V} \text { and then discon- } nected from the battery in the circuit and connected in series with a coil that has \(L=0.0660 \mathrm{H}\) and negligible resistance. After the circuit has been completed, there are current oscillations. (a) At an instant when the charge of the capacitor is \(0.0800 \mu \mathrm{C}\), how much cnergy is stored in the capacitor and in the inductor, and what is the current in the inductor? (b) At the instant when the charge on the capacitor is \(0.0800 \mu \mathrm{C},\) what are the voltages across the capacitor and across the inductor, and what is the rate at which current in the inductor is changing?

When the currcnt in a toroidal solcnoid is changing at a rate of \(0.0260 \mathrm{~A} / \mathrm{s},\) the magnitude of the induced \(\mathrm{cmf}\) is \(12.6 \mathrm{mV}\). When the current equals \(1.40 \mathrm{~A},\) the average flux through each turn of the solenoid is 0.00285 Wb. Ilow many turns does the solenoid have?

At the instant when the current in an inductor is increasing at a rate of \(0.0640 \mathrm{~A} / \mathrm{s},\) the magnitude of the sclf-induced \(\mathrm{cmf}\) is \(0.0160 \mathrm{~V}\). (a) What is the inductance of the inductor? (b) If the inductor is a solenoid with 400 turns, what is the average magnetic flux through each turn when the current is \(0.720 \mathrm{~A}\) ?

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