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When a resistor with resistance \(R\) is connected to a \(1.50 \mathrm{~V}\) flashlight battery, the resistor consumes \(0.0625 \mathrm{~W}\) of electrical power. (Throughout, assume that each battery has negligible internal resistance.) (a) What power does the resistor consume if it is connected to a \(12.6 \mathrm{~V}\) car battery? Assume that \(R\) remains constant when the power consumption changes. (b) The resistor is connected to a battery and consumes \(5.00 \mathrm{~W}\). What is the voltage of this battery?

Short Answer

Expert verified
The power consumed by the resistor when connected to a 12.6 V car battery is approximately 4.41 W. The voltage of a battery for which the power consumed is given as 5 W will be approximately 7.48 V.

Step by step solution

01

Determination of the resistance

From the first condition, we have \(P = \frac{V^2}{R}\). We rearrange it as \(R = \frac{V^2}{P}\) and put \(P = 0.0625 \mathrm{~W}\) and \(V = 1.5 \mathrm{~V}\), then we have \(R = \frac{1.5^2}{0.0625} = 36 \mathrm{~\Omega}\)
02

Calculation of the power when connected to a car battery

For a given voltage of 12.6 V and resistance of 36 \(\Omega\), we can substitute these values into the power formula \(P = \frac{V^2}{R}\). This gives \(P = \frac{12.6^2}{36} = 4.41 \mathrm{~W}\)
03

Calculation of the battery voltage when the power consumed is 5 W

From the equation \(P = \frac{V^2}{R}\), we can rearrange to get \(V = \sqrt{PR}\). Substituting \(P = 5 \mathrm{~W}\) and \R = 36 \mathrm{~\Omega}\) will give \(V = \sqrt{5 \times 36} = 7.48 \mathrm{~V}\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ohm's Law
Understanding Ohm's Law is critical when studying electrical circuits. It is the foundation for analyzing the relationship between voltage, current, and resistance. The law is usually represented by the equation \( V = IR \), where \( V \) stands for voltage in volts, \( I \) for current in amperes, and \( R \) for resistance in ohms. This implies that the current flowing through a conductor between two points is directly proportional to the voltage across the two points, and inversely proportional to the resistance between them.

In practical terms, if you increase the voltage and keep the resistance constant, the current will rise. Conversely, an increase in resistance with a constant voltage will cause the current to drop. Ohm's Law is foundational because it allows you to calculate one of the three parameters if you know the other two, which is a common task in both theoretical exercises and real-world electrical applications.
Resistors
Resistors are one of the most fundamental components in electronic circuits. Their primary function is to limit or regulate the flow of electrical current. The resistance of a resistor is measured in ohms \( (\Omega) \). They come in various forms and sizes, each designed for specific current and power ratings.

Resistors can be connected in series or parallel configurations within a circuit, which affects the overall resistance and behavior of the circuit. The total resistance in a series circuit is the sum of all resistances, while in a parallel circuit, the total resistance is found through the reciprocal formula. Understanding how resistors impact a circuit is crucial for controlling the flow of current and protecting delicate components from excessive current.
Power Consumption
Power consumption in an electrical circuit refers to the rate at which energy is used or converted into other forms, often expressed in watts \( (W) \). The power consumed by a component, such as a resistor, can be calculated using the formula \( P = VI \), where \( P \) is power, \( V \) is voltage, and \( I \) is current. Another common formula is \( P = V^2 / R \), which is particularly helpful when current is not directly known.

It is important to know the power consumption for sizing the power supplies and ensuring that components can handle the consumed power without failing. For example, if a resistor consumes too much power, it may overheat and fail, possibly damaging other parts of the circuit.
Voltage
Voltage is a measure of the electrical potential difference between two points in a circuit and is measured in volts \( (V) \). It is often referred to as 'electric pressure' that drives the flow of electrons through a conductor. When a voltage is applied to a circuit, it causes current to flow, provided there is a path with a given resistance.

For example, a higher voltage across a resistor of constant resistance will increase the current and the power consumption, as illustrated in the exercise where connecting a resistor to a car battery of higher voltage results in higher power usage. Voltage plays a significant role in determining the energy transfer and it's crucial to match voltage requirements in circuit design to ensure optimal performance.
Resistance
Resistance is the property of an electrical conductor to resist the flow of current. Measured in ohms \( (\Omega) \), it is a critical factor in determining how much current will flow for a given voltage. Factors affecting the resistance include the material's inherent resistivity, as well as the conductor's length and cross-sectional area.

Ohmic materials obey Ohm's Law, and their resistance remains constant over a wide range of voltages. This means that a resistor with a fixed resistance will have a predictable effect on current and power consumption in a circuit, which can be crucial for designing circuits with specific characteristics. The resistor in the exercise is assumed to have constant resistance, which allows for straightforward calculations of power changes when the voltage is altered.

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Most popular questions from this chapter

A circular loop of wire with a radius of \(12.0 \mathrm{~cm}\) and oriented in the horizontal \(x y\) -plane is located in a region of uniform magnetic field. A field of \(1.5 \mathrm{~T}\) is directed along the positive \(z\) -direction, which is upward. (a) If the loop is removed from the field region in a time interval of \(2.0 \mathrm{~ms}\), find the average emf that will be induced in the wire loop during the extraction process. (b) If the coil is viewed looking down on it from above, is the induced current in the loop clockwise or counterclockwise?

\(\mathrm{A} 1.50 \mathrm{~m}\) cylindrical rod of diameter \(0.500 \mathrm{~cm}\) is connected to a power supply that maintains a constant potential difference of \(15.0 \mathrm{~V}\) across its ends, while an ammeter measures the current through it. You observe that at room temperature \(\left(20.0^{\circ} \mathrm{C}\right)\) the ammeter reads \(18.5 \mathrm{~A}\), while at \(92.0^{\circ} \mathrm{C}\) it reads 17.2 A. You can ignore any thermal expansion of the rod. Find (a) the resistivity at \(20.0^{\circ} \mathrm{C}\) and (b) the temperature coefficient of resistivity at \(20^{\circ} \mathrm{C}\) for the material of the rod.

A resistor with resistance \(R\) is connected to a battery that has emf \(12.0 \mathrm{~V}\) and internal resistance \(r=0.40 \Omega .\) For what two values of \(R\) will the power dissipated in the resistor be \(80.0 \mathrm{~W} ?\)

The free-electron density in a copper wire is \(8.5 \times 10^{28}\) electrons \(/ \mathrm{m}^{3} .\) The electric field in the wire is \(0.0600 \mathrm{~N} / \mathrm{C}\) and the temperature of the wire is \(20.0^{\circ} \mathrm{C}\). (a) What is the drift speed \(v_{\mathrm{d}}\) of the electrons in the wire? (b) What is the potential difference between two points in the wire that are separated by \(20.0 \mathrm{~cm} ?\)

A material with resistivity \(\rho\) is formed into a cylinder of length \(L\) and outer radius \(r_{\text {outer }}\). A cylindrical core with radius \(r_{\text {inner }}\) is removed from the axis of this cylinder and filled with a conducting material, which is attached to a wire. The outer surface of the cylinder is coated with a conducting material and attached to another wire. (a) If the second wire has potential \(V\) greater than the first wire, in what direction does the local electric field point inside of the cylinder? (b) The magnitude of this electric field is \(c / r,\) where \(c\) is a constant and \(r\) is the distance from the axis of the cylinder. Use the relationship \(V=\int \overrightarrow{\boldsymbol{E}} \cdot d \overrightarrow{\boldsymbol{l}}\) to determine the constant \(c .(\mathrm{c})\) What is the resistance of this device? (d) A \(1.00-\mathrm{cm}\) -long hollow cylindrical resistor has an inner radius of \(1.50 \mathrm{~mm}\) and an outer radius of \(3.00 \mathrm{~mm} .\) The material is a blend of powdered carbon and ceramic whose resistivity \(\rho\) may be altered by changing the amount of carbon. If this device should have a resistance of \(6.80 \mathrm{k} \Omega,\) what value of \(\rho\) should be selected?

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