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A metal ring \(4.50 \mathrm{~cm}\) in diameter is placed between the north and south poles of large magnets with the plane of its area perpendicular to the magnetic field. These magnets produce an initial uniform field of \(1.12 \mathrm{~T}\) between them but are gradually pulled apart, causing this field to remain uniform but decrease steadily at \(0.250 \mathrm{~T} / \mathrm{s}\). (a) What is the magnitude of the electric field induced in the ring? (b) In which direction (clockwise or counterclockwise) does the current flow as viewed by someone on the south pole of the magnet?

Short Answer

Expert verified
The magnitude of the electric field induced in the ring is \(E = 25.3 \mathrm{-mV/m}\), and the current in the ring flows counterclockwise as seen from the south pole of the magnet.

Step by step solution

01

Calculate the Area of the Ring

The ring is circular, and the area \(A\) of a circle with diameter \(D\) is calculated using the formula \(A = \pi (D/2)^2\). Given that the diameter \(D = 4.5 cm = 0.045 m\), you can substitute this into the formula to find the area of the ring.
02

Use Faraday's Law to Find the Magnitude of the Induced Electric Field

Faraday's Law of electromagnetic induction states that the emf (\Epsilon) around a closed path is equal to the negative rate of change of the magnetic flux (\ΦB) through the area enclosed by the path. First, compute the change in magnetic field (ΔB) per unit time (Δt): ΔB/Δt = -0.250 T/s (negative because the field is decreasing). Then, multiply this by the area of the ring to find the magnetic flux (-dΦB/dt). Now, remembering that the emf along the ring will equal the electric field strength (E) times the distance around the ring (the circumference), you can divide to find the electric field strength: \(E = |\Epsilon| / (2πr)\).
03

Determine the Direction of the Induced Current Using Lenz's Law

Lenz's Law states that the direction of the induced current is such that it opposes the change in the magnetic field that produced it. In this case, since the magnetic field is decreasing, the induced current will create its own magnetic field in the same direction as the original field to try and oppose the decrease. Therefore, if you use the right-hand rule (pointing thumb in the direction of magnetic field and curling fingers represents direction of current), you can figure out the direction of the current. Viewed from the south pole (where the magnetic field goes from outside to inside), the current will be flowing counterclockwise.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Faraday's Law
Faraday's Law of electromagnetic induction is a cornerstone of electromagnetism. It describes how a change in magnetic environment of a coil of wire will induce an electromotive force (emf) in the coil. The magnitude of this emf is directly proportional to the rate of change of the magnetic flux that passes through the coil's cross-section.
In mathematical terms, Faraday's Law is expressed as:\[\mathcal{E} = -\frac{d\Phi_B}{dt}\]where \(\mathcal{E}\) is the emf, and \(\Phi_B\) is the magnetic flux. The negative sign is significant—originating from Lenz's Law, it indicates the direction of the induced emf opposes the change in magnetic flux. This opposition is a crucial concept, ensuring that any induced current works against the change that creates it.
  • Faraday's principle is key in circuits such as transformers and generators.
  • Any change in the magnetic environment, whether by moving magnets or changing fields, can induce electricity.
Lenz's Law
Lenz's Law provides a rule to determine the direction of the current induced by a changing magnetic field. It states that the induced current will flow in such a way that its magnetic field opposes the initial change of flux through the loop.
This concept can be visualized using the right-hand rule: If you point your thumb in the direction of the magnetic field and wrap your fingers around the coil, your fingers will curl in the direction of the induced current. Thus, in our exercise, as the magnetic field decreases, the current will be counterclockwise when viewed from the south pole, trying to maintain the original field strength.
  • The negative sign in Faraday's Law comes from Lenz's Law.
  • It is a demonstration of the conservation of energy, as it prevents the creation of energy from nothing.
Magnetic Flux
Magnetic flux, denoted as \(\Phi_B\), quantifies the number of magnetic field lines passing through a given area. It is calculated using:\[\Phi_B = B \cdot A \cdot \cos(\theta)\]where \(B\) is the magnetic field, \(A\) is the area, and \(\theta\) is the angle between the magnetic field and the perpendicular to the surface.
In scenarios like the one described in our exercise, as the distance between magnets increases, the magnetic flux through the ring decreases. This decreasing flux induces an emf that acts in opposition to the change, as per Faraday's Law.
  • Magnetic flux is a scalar quantity and depends on both the magnetic field strength and the area it penetrates.
  • A uniform field with decreasing strength leads to a proportional decrease in magnetic flux through the area it envelops.
Induced Electric Field
An induced electric field arises when a magnetic field changes over time. This is a result of Faraday's Law, which links changing magnetic fields to the generation of electric fields.
In the context of our exercise, a steady decrease in the magnetic field at the rate of 0.250 T/s induces an electric field in the ring. This field can be calculated by first determining the rate of change of magnetic flux and then finding the magnitude of the induced electric field around the loop using:\[E = \frac{|\mathcal{E}|}{2\pi r}\]where \(|\mathcal{E}|\) is the magnitude of the induced emf and \(r\) is the radius of the ring.
  • Induced electric fields are a non-conservative electric field, different from those caused by stationary charges.
  • These fields can drive currents in closed loops, making them fundamental to electromagnetic applications.

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Most popular questions from this chapter

A single loop of wire with an area of \(0.0900 \mathrm{~m}^{2}\) is in a uniform magnetic field that has an initial value of \(3.80 \mathrm{~T},\) is perpendicular to the plane of the loop, and is decreasing at a constant rate of \(0.190 \mathrm{~T} / \mathrm{s}\)(a) What emf is induced in this loop? (b) If the loop has a resistance of \(0.600 \Omega,\) find the current induced in the loop.

A long, straight solenoid with a cross-sectional area of \(8.00 \mathrm{~cm}^{2}\) is wound with 90 turns of wire per centimeter, and the windings carry a current of 0.350 A. A second winding of 12 turns encircles the solenoid at its center. The current in the solenoid is turned off such that the magnetic field of the solenoid becomes zero in \(0.0400 \mathrm{~s}\). What is the average induced emf in the second winding?

A ductile metal wire has resistance \(R\). What will be the resistance of this wire in terms of \(R\) if it is stretched to three times its original length, assuming that the density and resistivity of the material do not change when the wire is stretched? (Hint: The amount of metal does not change, so stretching out the wire will affect its cross-sectional area.)

A metal wire has a circular cross section with radius \(0.800 \mathrm{~mm}\) You measure the resistivity of the wire in the following way: You connect one end of the wire to one terminal of a battery that has emf \(12.0 \mathrm{~V}\) and negligible internal resistance. To the other terminal of the battery you connect a point along the wire so that the length of wire between the battery terminals is \(d\). You measure the current in the wire as a function of \(d\). The currents are small, so the temperature change of the wire is very small. You plot your results as \(I\) versus \(1 / d\) and find that the data lie close to a straight line that has slope \(600 \mathrm{~A} \cdot \mathrm{m} .\) What is the resistivity of the material of which the wire is made?

A very long, straight solenoid with a cross-sectional area of \(2.00 \mathrm{~cm}^{2}\) is wound with 90.0 turns of wire per centimeter. Starting at \(t=0\) the current in the solenoid is increasing according to \(i(t)=\left(0.160 \mathrm{~A} / \mathrm{s}^{2}\right) t^{2}\). A secondary winding of 5 turns encircles the solenoid at its center, such that the secondary winding has the same cross-sectional area as the solenoid. What is the magnitude of the emf induced in the secondary winding at the instant that the current in the solenoid is \(3.20 \mathrm{~A}\) ?

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