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The magnetic flux through a coil is given by \(\Phi_{B}=\alpha t-\beta t^{3}\) where \(\alpha\) and \(\beta\) are constants. (a) What are the units of \(\alpha\) and \(\beta ?\) (b) If the induced emf is zero at \(t=0.500 \mathrm{~s},\) how is \(\alpha\) related to \(\beta ?\) (c) If the emf at \(t=0\) is \(-1.60 \mathrm{~V},\) what is the \(\mathrm{emf}\) at \(t=0.250 \mathrm{~s} ?\)

Short Answer

Expert verified
The units of \( \alpha \) and \( \beta \) are \( Wb \cdot s^{-1} \) and \( Wb \cdot s^{-3} \) respectively. The relationship between \( \alpha \) and \( \beta \) is \( \alpha = 0.75 \beta \). The emf at \( t = 0.250 \, s \) can be calculated using these values.

Step by step solution

01

Determining the units of \( \alpha \) and \( \beta \)

Magnetic flux \( \Phi_{B} \) is measured in Weber (Wb) in SI units, and \( t \) time is measured in seconds (s). From the equation \( \Phi_{B} = \alpha t - \beta t^3 \), it can be inferred that the units of \( \alpha \) must be \( Wb \cdot s^{-1} \) and the unit of \( \beta \) must be \( Wb \cdot s^{-3} \) to ensure the units are consistent on both sides of the equation.
02

Finding the relationship between \( \alpha \) and \( \beta \)

Faraday's law states that the induced emf equals the rate of change of flux events. Mathematically, emf = \( -\frac{d \Phi_{B}}{dt} \). Substituting the given \( \Phi_{B} \) into the emf formula gives \( -\frac{d (\alpha t - \beta t^3 )}{dt} = -\alpha + 3\beta t^2 \). Set the induced emf to zero and \( t = 0.500 \) into the equation, we get \( 0 = -\alpha + 3\beta (0.500)^2 \), rearranging the terms, we can find how \( \alpha \) is related to \( \beta \), that is \( \alpha = 0.75 \beta \).
03

Calculating emf at \( t = 0.250 \, s \)

The induced emf equals the negative rate of change of flux events and equals \( -\alpha + 3\beta t^2 \). The given initial emf at \( t = 0 \) is \( -1.60 \, V \), can be written as \( -1.60 = -\alpha + 3\beta (0)^2 \) which simplifies to \( \alpha = -1.60 \). Using the relationship between \( \alpha \) and \( \beta \) from step 2, we can find \( \beta \) = \( \alpha / 0.75 = -1.60 / 0.75 \). Substituting these values in the emf equation for \( t = 0.250 \, s \), we get the emf at \( t = 0.250 \, s \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Faraday's Law
Faraday's Law is a fundamental principle in electromagnetism. It describes how an electric field is induced in any closed circuit when the magnetic flux through the circuit changes over time. Simply put, when the amount of magnetic field (flux) passing through a loop changes, it generates an electromotive force (EMF) around that loop. This change in magnetic flux can be due to:
  • Moving a magnet towards or away from a coil
  • Changing the area of the loop exposed to the magnetic field
  • Varying the intensity of the magnetic field itself
Mathematically, Faraday's Law is expressed as:\[emf = -\frac{d \Phi_{B}}{dt}\]The negative sign in the equation is consistent with Lenz's Law, indicating that the induced EMF opposes the change in flux causing it. In practical terms, this explains how transformers, electric generators, and inductors work by converting mechanical energy to electrical energy or vice versa. It's essential to understand that the rate at which the magnetic flux changes is what contributes to the generation of EMF.
Induced EMF
Induced EMF is the voltage generated inside a circuit due to the change in magnetic flux. It's what powers devices when a generator is turned or makes a transformer operate. As derived from Faraday's Law, the induced EMF in a circuit is calculated using:\[emf = -\frac{d \Phi_{B}}{dt}\]In the context of our problem:
  • The magnetic flux \( \Phi_{B} \) is given by \( \alpha t - \beta t^3 \)
  • Therefore, the rate of change of this flux yields the induced EMF \( -\alpha + 3\beta t^2 \)
This formula indicates that the induced EMF depends not only on the rate of change of magnetic flux but also on time \( t \). At specific moments, such as \( t=0.500 \mathrm{~s} \), it's crucial to solve these equations to find the relationship among constants \( \alpha \) and \( \beta \) or calculate the EMF at another instance, such as \( t=0.250 \mathrm{~s} \). Such calculations help in determining how setups like electric motors and dynamos efficiently convert physical changes into electrical signals.
Rate of Change of Flux
The rate of change of flux is a key factor in determining how much induced EMF is generated in a coil. In simpler terms, it's how quickly the magnetic field going through a coil changes. The faster the change, the greater the EMF and the more potential electricity can be produced. This concept is central to Faraday's Law, as this rate directly contributes to the magnitude of the induced EMF.In mathematical terms, given a magnetic flux \( \Phi_{B} = \alpha t - \beta t^3 \), the rate of change is determined by differentiating this expression with respect to time \( t \):\[\frac{d \Phi_{B}}{dt} = \alpha - 3\beta t^2\]From this differentiation:
  • \( \alpha \) represents a linear change in flux, contributing steadily to EMF
  • \(-3\beta t^2\) signifies how the rate grows with increasing \( t \), showing more complex dynamics
Understanding and calculating this rate is essential for various real-world applications. For instance, by knowing the rate at which flux changes, engineers can design generators to optimize their efficiency and output. Additionally, this knowledge aids in solving problems where specific conditions, such as when the induced EMF equals zero at a given time, are imposed, revealing relationships between constants involved.

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Most popular questions from this chapter

A ductile metal wire has resistance \(R\). What will be the resistance of this wire in terms of \(R\) if it is stretched to three times its original length, assuming that the density and resistivity of the material do not change when the wire is stretched? (Hint: The amount of metal does not change, so stretching out the wire will affect its cross-sectional area.)

The current in a wire varies with time according to the relationship \(I=55 \mathrm{~A}-\left(0.65 \mathrm{~A} / \mathrm{s}^{2}\right) t^{2} .\) (a) How many coulombs of charge pass a cross section of the wire in the time interval between \(t=0\) and \(t=8.0 \mathrm{~s} ?(\mathrm{~b}) \mathrm{What}\) constant current would transport the same charge in the same time interval?

BIO Treatment of Heart Failure. A heart defibrillator is used to enable the heart to start beating if it has stopped. This is done by passing a large current of 12 A through the body at \(25 \mathrm{~V}\) for a very short time, usually about \(3.0 \mathrm{~ms}\). (a) What power does the defibrillator deliver to the body, and (b) how much energy is transferred?

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On your first day at work as an electrical technician, you are asked to determine the resistance per meter of a long piece of wire. The company you work for is poorly equipped. You find a battery, a voltmeter, and an ammeter, but no meter for directly measuring resistance (an ohmmeter). You put the leads from the voltmeter across the terminals of the battery, and the meter reads \(12.6 \mathrm{~V}\). You cut off a \(20.0 \mathrm{~m}\) length of wire and connect it to the battery, with an ammeter in series with it to measure the current in the wire. The ammeter reads 7.00 A. You then cut off a \(40.0 \mathrm{~m}\) length of wire and connect it to the battery, again with the ammeter in series to measure the current. The ammeter reads 4.20 A. Even though the equipment you have available to you is limited, your boss assure you of its high quality: The ammeter has very small resistance, and the voltmeter has very large resistance. What is the resistance of 1 meter of wire?

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