/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 78 An external resistor with resist... [FREE SOLUTION] | 91Ó°ÊÓ

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An external resistor with resistance \(R\) is connected to a battery that has emf \(\mathcal{E}\) and internal resistance \(r\). Let \(P\) be the electrical power output of the source. By conservation of energy, \(P\) is equal to the power consumed by \(R\). What is the value of \(P\) in the limit that \(R\) is (a) very small; (b) very large? (c) Show that the power output of the battery is a maximum when \(R=r .\) What is this maximum \(P\) in terms of \(\mathcal{E}\) and \(r ?\) (d) A battery has \(\mathcal{E}=64.0 \mathrm{~V}\) and \(r=4.00 \Omega .\) What is the power output of this battery when it is connected to a resistor \(R,\) for \(R=2.00 \Omega, R=4.00 \Omega,\) and \(R=6.00 \Omega ?\) Are your results consistent with the general result that you derived in part (b)?

Short Answer

Expert verified
The maximum power output of the battery is when \( R = r \), and the maximum value is \( P_{max} = \frac{\mathcal{E}^2}{4r} \). The power output for \( R = 2.00 \Omega \), \( R = 4.00 \Omega \), and \( R = 6.00 \Omega \) are 682.67 W, 512 W, and 341.33 W, respectively. This is consistent with the result that power output is maximized when \( R = r \).

Step by step solution

01

Calculating the Current in the Circuit

The current in the circuit can be found using the formula \(I = \frac{\mathcal{E}}{R + r}\). This is derived from Ohm's law, which states that the current is the voltage divided by the total resistance.
02

Calculating the Power Output

The power output can be found by substituting our value for current into the formula for power. This gives us \(P = \frac{\mathcal{E}^2 R}{(R + r)^2}\).
03

Finding the Limits as R Becomes Very Small and Very Large

As \(R\) becomes very small, \(P\) approaches 0. This is because the internal resistance becomes much greater than the external resistance, so the power is dissipated in the internal resistance. As \(R\) becomes very large, \(P\) also approaches 0. This is because the total resistance increases, so the overall current decreases.
04

Maximizing the Power Output

To maximize the power output, we take the derivative of \(P\) with respect to \(R\), set it equal to 0, and solve for \(R\). This gives us \(R = r\). Substituting this back into the formula for power, we get that the maximum power output is \(P_{max} = \frac{\mathcal{E}^2}{4r}\).
05

Evaluating the Power Output for Specific Resistances

Using the values \(\mathcal{E}=64.0 \mathrm{~V}\) and \(r=4.00 \Omega\), the power output can be calculated for \(R=2.00 \Omega, R=4.00 \Omega,\) and \(R=6.00 \Omega\) as \(P = \frac{(64.0 \mathrm{~V})^2 \cdot (2.00 \Omega)}{(2.00 \Omega + 4.00 \Omega)^2} = 682.67 W\), \(P = \frac{(64.0 \mathrm{~V})^2 \cdot (4.00 \Omega)}{(4.00 \Omega + 4.00 \Omega)^2} = 512 W\), and \(P = \frac{(64.0 \mathrm{~V})^2 \cdot (6.00 \Omega)}{(6.00 \Omega + 4.00 \Omega)^2} = 341.33 W\). These values are consistent with the result that power output is maximized when \(R = r\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ohm's Law
Ohm's Law is a fundamental concept in electrical engineering that describes the relationship between voltage, current, and resistance in a circuit. It is expressed by the equation:
\[ V = I \cdot R \]
where:
  • \( V \) is the voltage across the resistor.
  • \( I \) is the current flowing through the resistor.
  • \( R \) is the resistance of the resistor.
This equation shows that the current in a circuit is directly proportional to the voltage and inversely proportional to the resistance.
When calculating the current in a circuit with a voltage source and resistance, as described in the exercise, we utilize Ohm's Law in its derived form:
\[ I = \frac{\mathcal{E}}{R + r} \]
This version of Ohm’s Law accounts for both the internal resistance \( r \) of the battery and the external resistance \( R \) of the connected resistor. Understanding this relationship is crucial for analyzing circuits, especially when determining how different resistances in a circuit influence current flow.
Internal Resistance
The concept of internal resistance is vital when it comes to understanding real-world batteries and circuits.
Every battery or power source has some inherent resistance within itself, known as internal resistance, denoted by \( r \). This resistance causes some of the power generated by the battery to be dissipated within itself as heat.
Because of this internal resistance, the actual voltage available to an external circuit is less than the electromotive force (emf) \( \mathcal{E} \) of the battery.
Using Ohm's Law, the voltage across the load (external resistor) is given by:
\[ V = \mathcal{E} - I \cdot r \]
where \( I \) is the current as before. The power that can be delivered to an external load is thus affected by this internal resistance, reducing the efficiency especially when \( R \) is very small.
Understanding the internal resistance helps in analyzing why circuits behave differently at various load resistances and is crucial for practical applications, such as designing circuits for maximum efficiency.
Maximum Power Transfer Theorem
The Maximum Power Transfer Theorem is an important principle in electrical engineering. It states that for maximum power to be transferred from a source to a load, the load resistance \( R \) must equal the internal resistance \( r \) of the source. This can be derived by differentiating the power formula with respect to \( R \) and setting the derivative to zero, yielding \( R = r \).
At this condition, the power delivered to the load is maximized and calculated as:
\[ P_{max} = \frac{\mathcal{E}^2}{4r} \]
For practical examples, consider a battery with \( \mathcal{E} = 64.0 \, \mathrm{V} \) and \( r = 4.00 \, \Omega \). According to the theorem, if \( R \) is set to \( 4.00 \, \Omega \), the power output will be at its maximum, which in this case is \( 512 \, \mathrm{W} \).
  • If \( R \) is less than \( r \), more power is wasted internally.
  • If \( R \) is greater, the total resistance increases, reducing current and power.
This theorem is an essential tool for engineers aiming to design systems for optimal power efficiency, highlighting the balance needed between internal and external resistances.

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Most popular questions from this chapter

A coil \(4.00 \mathrm{~cm}\) in radius, containing 500 turns, is placed in a uniform magnetic field that varies with time according to \(B=(0.0120 \mathrm{~T} / \mathrm{s}) t+\left(3.00 \times 10^{-5} \mathrm{~T} / \mathrm{s}^{4}\right) t^{4} .\) The coil is connected to a \(600 \Omega\) resistor, and its plane is perpendicular to the magnetic field. You can ignore the resistance of the coil. (a) Find the magnitude of the induced emf in the coil as a function of time. (b) What is the current in the resistor at time \(t=5.00 \mathrm{~s} ?\)

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