/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 11 A circular loop of wire with rad... [FREE SOLUTION] | 91Ó°ÊÓ

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A circular loop of wire with radius \(2.00 \mathrm{~cm}\) and resistance \(0.600 \Omega\) is in a region of a spatially uniform magnetic field \(\vec{B}\) that is perpendicular to the plane of the loop. At \(t=0\) the magnetic field has magnitude \(B_{0}=3.00 \mathrm{~T}\). The magnetic field then decreases according to the equation \(B(t)=B_{0} e^{-t / \tau},\) where \(\tau=0.500 \mathrm{~s}\). (a) What is the maximum magnitude of the current \(I\) induced in the loop? (b) What is the induced current \(I\) when \(t=1.50 \mathrm{~s} ?\)

Short Answer

Expert verified
The maximum magnitude of the current induced in the loop is approximately 0.63 A, and the induced current when \(t = 1.50 s\) is approximately 0.023 A.

Step by step solution

01

Calculate the maximum rate of change of the magnetic field.

To find the maximum magnitude of the current, we first need to find the maximum rate of change of the magnetic field. The given equation for the magnetic field is \(B(t) = B_0 e^{-t / \tau}\). The rate of change of \(B(t)\) with respect to time is given by the derivative of this function: \(\frac{dB}{dt} = - \frac{B_0}{\tau} e^{-t / \tau}\). This function reaches its maximum when \(t = 0\). Plugging in this value, we find that the maximum rate of change of the field is \(- \frac{B_0}{\tau}\). Note the negative sign, which indicates that the field is decreasing.
02

Calculate the maximum induced current.

Faraday's law states that the emf (and hence the current) induced in a loop is equal to the rate of change of magnetic flux through the loop, with a minus sign due to Lenz's law. The magnetic flux \(\Phi\) through the loop is given by \(B \cdot A\), where \(A\) is the area of the loop. For a circular loop of radius \(r\), \(A = \pi r^2\). The change in flux is thus \(\Delta \Phi = B \cdot \Delta A = B \cdot \pi r^2\). Plugging in our values for \(r\) and \(\frac{dB}{dt}\), we find that \(\Delta \Phi = -B_0 \cdot \pi \cdot r^2 / \tau\). By Faraday's law, the emf is then \(|emf| = |\Delta \Phi / \Delta t| = B_0 \cdot \pi \cdot r^2 / \tau\). The current \(I\) is given by \(emf / R\), where \(R\) is the resistance of the loop. Plugging in our value for \(R\), we find that \(I = B_0 \cdot \pi \cdot r^2 / (R \cdot \tau)\). Note that the current is positive, indicating that it goes in the direction to oppose the decrease in magnetic field.
03

Calculate the current at a given moment.

To find the current at a given moment, we substitute that moment \(t\) into the equation for \(\frac{dB}{dt}\), which gives the rate of change of the field at that moment. We then substitute this into the formula for the current. At \(t = 1.50 s\), \(\frac{dB}{dt} = - \frac{B_0}{\tau} e^{-1.50 s / 0.500 s} = - \frac{B_0}{\tau} e^{-3}\) and the current at that moment is \(I(t) = - \frac{dB}{dt} \cdot \pi \cdot r^2 / R = B_0 \cdot \pi \cdot r^2 \cdot e^{-3} / (R \cdot \tau)\).
04

Substitute the known values.

Substitute the given values into the formulas from the previous steps: \(B_0 = 3.00 T\), \(r = 0.02 m\), \(R = 0.600 \Omega\), \(\tau = 0.500 s\). The maximum induced current is \(I_{max} = B_0 \cdot \pi \cdot r^2 / (R \cdot \tau)\) and the current at \(t = 1.50 s\) is \(I(t) = B_0 \cdot \pi \cdot r^2 \cdot e^{-3} / (R \cdot \tau)\). Calculate these to get the numerical answers.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Faraday's Law
Faraday's Law of Electromagnetic Induction is fascinating because it provides the basis for understanding how electric currents can be produced by changing magnetic fields. According to this law, an electromotive force (emf) is induced in a loop whenever there is a change in the magnetic flux through the loop. This can mean a change in the magnetic field strength, the area of the loop, or the angle between the magnetic field and the normal to the coil's surface.

In mathematical terms, Faraday's Law is expressed as:

\[ \text{emf} = - \frac{d\Phi}{dt} \]

where \( \Phi \) represents the magnetic flux, and the negative sign is accounted for by Lenz's Law; it signifies the direction of the induced emf relative to the change in flux. When tackling a problem like the one presented in the exercise, where a magnetic field varies with time, Faraday's Law helps us compute the emf by taking the time derivative of the flux. Consequently, knowing the emf allows calculation of the induced current, given the resistance of the loop. This beautifully showcases the dynamic connection between electricity and magnetism.
Lenz's Law
Lenz's Law is closely tied to Faraday's Law as it describes the direction of the induced current. Named after Emil Lenz, this law protects the conservation of energy principle. It states that the induced current will always flow in such a way as to counteract the change in magnetic flux that produced it.

In simpler terms:
  • If the magnetic field through a loop increases, the induced current will flow such that it creates a magnetic field opposing the increase.
  • If the magnetic field decreases, the induced current will flow in the opposite direction to counteract the decrease.

Lenz's Law can often be remembered by the rhyming directive "opposes the cause." It’s because of this law that the negative sign appears in Faraday's formula for induced emf (\( \text{emf} = - \frac{d\Phi}{dt} \)). It ensures the induced current doesn't enhance the cause of the original current but resists its alteration instead. This is crucial in the calculations presented in the exercise, determining that the induced current was positively oriented to counter the decreasing magnetic field.
Magnetic Flux
Magnetic flux is a measure of the quantity of magnetism, taking into account the strength and extent of a magnetic field. It is a vital concept that aids in understanding electromagnetic induction, particularly how and why changes in a magnetic field induce an electric current in nearby conductors.

Mathematically, magnetic flux \(\Phi\) through a surface is given by

\[ \Phi = B \cdot A \cdot \cos \theta \]

where:
  • \(B\) is the magnetic field strength,
  • \(A\) is the area of the loop,
  • and \(\theta\) is the angle between the magnetic field lines and the perpendicular (normal) to the surface.

In the circular loop example from the exercise, since the magnetic field is perpendicular to the loop (\(\theta = 0\)), the flux simplifies to \(\Phi = B \cdot A\). Changes in this quantity, as the magnetic field decreases, directly lead to the induction of a current in the loop. This interplay of flux change inevitably rolls into the practical calculations where flux derivatives are used to determine the induced emf and resulting current, aligning closely with Faraday's insights.

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Most popular questions from this chapter

A 5.00 A current runs through a 12 gauge copper wire (diameter \(2.05 \mathrm{~mm}\) ) and through a light bulb. Copper has \(8.5 \times 10^{28}\) free electrons per cubic meter. (a) How many electrons pass through the light bulb each second? (b) What is the current density in the wire? (c) At what speed does a typical electron pass by any given point in the wire? (d) If you were to use wire of twice the diameter, which of the above answers would change? Would they increase or decrease?

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The resistivity of a semiconductor can be modified by adding different amounts of impurities. A rod of semiconducting material of length \(L\) and cross- sectional area \(A\) lies along the \(x\) -axis between \(x=0\) and \(x=L\). The material obeys Ohm's law, and its resistivity varies along the rod according to \(\rho(x)=\rho_{0} \exp (-x / L) .\) The end of the rod at \(x=0\) is at a potential \(V_{0}\) greater than the end at \(x=L\). (a) Find the total resistance of the rod and the current in the rod. (b) Find the electric-field magnitude \(E(x)\) in the rod as a function of \(x\). (c) Find the electric potential \(V(x)\) in the rod as a function of \(x\). (d) Graph the functions \(\rho(x), E(x),\) and \(V(x)\) for values of \(x\) between \(x=0\) and \(x=L\)

BIO Spiderweb Conductivity. Some types of spiders build webs that consist of threads made of dry silk coated with a solution of a variety of compounds. This coating leaves the threads, which are used to capture prey, hygroscopic- that is, they attract water from the atmosphere. It has been hypothesized that this aqueous coating makes the threads good electrical conductors. To test the electrical properties of coated thread, researchers placed a \(5 \mathrm{~mm}\) length of thread between two electrical contacts. The researchers stretched the thread in \(1 \mathrm{~mm}\) increments to more than twice its original length, and then allowed it to return to its original length, again in \(1 \mathrm{~mm}\) increments. Some of the resistance measurements are shown in the table: $$ \begin{array}{l|lllllll} \hline \begin{array}{l} \text { Resistance of } \\ \text { thread }\left(10^{9} \Omega\right) \end{array} & 9 & 19 & 41 & 63 & 102 & 76 & 50 & 24 \\ \begin{array}{l} \text { Length of } \\ \text { thread }(\mathrm{mm}) \end{array} & 5 & 7 & 9 & 11 & 13 & 9 & 7 & 5 \\ \hline \end{array} $$ "Based on F. Vollrath and D. Edmonds, "Consequences of electrical conductivity in an orb spider's capture web," Naturwissenschaften (100:12, December \(2013,\) pp. \(1163-69)\) 25.79 What is the best explanation for the behavior exhibited in the data? (a) Longer threads can carry more current than shorter threads do and so make better electrical conductors. (b) The thread stops being a conductor when it is stretched to \(13 \mathrm{~mm},\) due to breaks that occur in the thin coating. (c) As the thread is stretched, the coating thins and its resistance increases; as the thread is relaxed, the coating returns nearly to its original state. (d) The resistance of the thread increases with distance from the end of the thread.

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