/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 33 Helium gas undergoes an adiabati... [FREE SOLUTION] | 91Ó°ÊÓ

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Helium gas undergoes an adiabatic process in which the Kelvin temperature doubles. By what factor does the pressure change?

Short Answer

Expert verified
The pressure changes by a factor of \( (2)^(5/3) \).

Step by step solution

01

Recall Adiabatic Equation.

To begin, you need to know the adiabatic equation that applies to this process. In adiabatic process with constant volume, where \( \gamma \) is the heat capacity ratio, the equation is \( P_1 T_2^\gamma = P_2 T_1^\gamma \).
02

Substitute Given Values.

Let's insert the given values into the formula. The temperature doubles, so \( T_2 = 2T_1 \). This allows us to write the equation as \( P_1 (2T_1)^\gamma = P_2 T_1^\gamma \). We're trying to find the factor \( X \) by which the pressure changes, where \( X = P_2/P_1 \). This lets us rewrite the equation as \( X = (2T_1)^\gamma/T_1^\gamma \).
03

Solve the Equation.

Next, you can simplify the equation \( X = (2)^\gamma \), since \( T_1 \) cancels out in the previous equation. Given that helium is a monatomic gas and \( \gamma = 5/3 \), \( X = (2)^(5/3) \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Thermodynamics
Thermodynamics is the branch of physics that deals with the relationships between heat and other forms of energy. In particular, it describes how thermal energy is converted to and from other forms of energy and how it affects matter. An adiabatic process, which is a key concept in thermodynamics, is a type of thermodynamic process where there is no exchange of heat with the surroundings. In an adiabatic process, all the work done on or by the system changes its internal energy, resulting in a temperature and pressure change. The behavior of gases under adiabatic conditions can be predicted by a set of equations derived from the laws of thermodynamics.
Heat Capacity Ratio
The heat capacity ratio, often denoted as \( \gamma \) (gamma), is a dimensionless quantity that is critical in characterizing the adiabatic process of a gas. It is the ratio of the specific heat at constant pressure \( (C_p) \) to the specific heat at constant volume \( (C_v) \). For ideal gases, this ratio is a constant and plays a pivotal role in determining the relationship between pressure and temperature during an adiabatic process. Monatomic gases like helium have a heat capacity ratio of \( \gamma = 5/3 \), while diatomic gases have different values. The value of \( \gamma \) reflects the degrees of freedom available to the particles in a gas and affects how the temperature of the gas changes in response to pressure changes.
Kelvin Temperature
Kelvin temperature is the base unit of thermodynamic temperature in the International System of Units (SI). Unlike Celsius and Fahrenheit, Kelvin is an absolute temperature scale starting at absolute zero, the theoretical point at which there is a total absence of heat energy and the particles are at rest. Kelvin temperatures are essential in thermodynamics and are used to ensure accuracy when describing temperature changes and relationships between thermodynamic quantities. In our exercise example, the Kelvin temperature doubling means that the energy per particle and, hence, the average kinetic energy of the gas particles has doubled.
Pressure Change
Pressure change in a gas is frequently related to changes in volume and temperature as described by the ideal gas law. For an adiabatic process, which is one without heat exchange, the relationship between pressure and temperature is given by the adiabatic equation \( P_1 T_2^\gamma = P_2 T_1^\gamma \). Since temperature and pressure are directly related in an adiabatic process, as one increases, so does the other, assuming volume is held constant. The factor by which pressure changes, as a result of temperature change in an adiabatic process, can be derived using the adiabatic equation. In the exercise, doubling the temperature of helium gas corresponds to a pressure change factor computed using the heat capacity ratio specific to helium.

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Most popular questions from this chapter

An ideal gas undergoes a process during which the pressure is kept directly proportional to the volume, so that \(p=\alpha V\) where \(\alpha\) is a positive constant. If the volume changes from \(V_{1}\) to \(V_{2}\), how much work is done by the gas? Express your answer in terms of \(V_{1}, V_{2},\) and \(\alpha\)

During an adiabatic expansion the temperature of \(0.450 \mathrm{~mol}\) of argon (Ar) drops from \(66.0^{\circ} \mathrm{C}\) to \(10.0^{\circ} \mathrm{C}\). The argon may be treated as an ideal gas. (a) Draw a \(p V\) -diagram for this process. (b) How much work does the gas do? (c) What is the change in internal energy of the gas?

\(\cdot\) Boiling Water at High Pressure. When water is boiled at a pressure of \(2.00 \mathrm{~atm},\) the heat of vaporization is \(2.20 \times 10^{6} \mathrm{~J} / \mathrm{kg}\) and the boiling point is \(120^{\circ} \mathrm{C}\). At this pressure, \(1.00 \mathrm{~kg}\) of water has a volume of \(1.00 \times 10^{-3} \mathrm{~m}^{3},\) and \(1.00 \mathrm{~kg}\) of steam has a volume of \(0.824 \mathrm{~m}^{3}\). (a) Compute the work done when \(1.00 \mathrm{~kg}\) of steam is formed at this temperature. (b) Compute the increase in internal energy of the water.

\( \cdot\) Heat \(Q\) flows into a monatomic ideal gas, and the volume increases while the pressure is kept constant. What fraction of the heat energy is used to do the expansion work of the gas?

A cylinder contains \(0.250 \mathrm{~mol}\) of carbon dioxide \(\left(\mathrm{CO}_{2}\right)\) gas at a temperature of \(27.0^{\circ} \mathrm{C}\). The cylinder is provided with a friction less piston, which maintains a constant pressure of 1.00 atm on the gas. The gas is heated until its temperature increases to \(127.0^{\circ} \mathrm{C}\). Assume that the \(\mathrm{CO}_{2}\) may be treated as an ideal gas. (a) Draw a \(p V\) -diagram for this process. (b) How much work is done by the gas in this process? (c) On what is this work done? (d) What is the change in internal energy of the gas? (e) How much heat was supplied to the gas? (f) How much work would have been done if the pressure had been 0.50 atm?

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