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During an adiabatic expansion the temperature of \(0.450 \mathrm{~mol}\) of argon (Ar) drops from \(66.0^{\circ} \mathrm{C}\) to \(10.0^{\circ} \mathrm{C}\). The argon may be treated as an ideal gas. (a) Draw a \(p V\) -diagram for this process. (b) How much work does the gas do? (c) What is the change in internal energy of the gas?

Short Answer

Expert verified
(a) The \(pV\)-diagram of an adiabatic process will feature a steeper slope compared to an isothermal process. This is due to no heat exchange with the environment in an adiabatic process. (b) The work done by the gas can be computed from rearranged adiabatic equation into work done equation. After substituting the given values into this equation, the work done by the gas can be found. (c) The change in internal energy for an adiabatic process equals to the negative of work done by the gas. After substituting the calculated work number into this, the change in internal energy can be obtained.

Step by step solution

01

Determine Constants

First and foremost, establish all the given constants. These include the molar mass of argon \(M = 0.450 \, mol\), the beginning temperature of the argon \(T_1 = 66.0^{\circ} C = 339.15 \, K\) (converted to Kelvin), the final temperature \(T_2 = 10.0^{\circ} C = 283.15 \, K\), and the specific heat ratio for monatomic ideal gases, \(\gamma = \frac{C_p}{C_v} = 5/3\). Here, \(C_p\) and \(C_v\) are molar specific heats at constant pressure and volume respectively.
02

Adiabatic Expansion Process and Work Done

The general expression of work done in an adiabatic process by an ideal gas is given by: \(W = \frac{{P_1V_1 - P_2V_2}}{{\gamma - 1}}\). As the pressure and volume at both initial and final states are not given, apply the ideal gas equation \(PV = nRT\) to convert it into form of temperature: \(W = \frac{{nR(T_1 - T_2)}}{{\gamma - 1}}\). Substitute the given values to find the work done.
03

Change in Internal Energy

The internal energy change \(\Delta U\) in a process involving ideal gases relates to the first law of thermodynamics, according to which this change equals the work done by the system plus the heat transferred to the system. In adiabatic process no heat transfers to the system so the heat transferred \(Q = 0\), therefore: \(\Delta U = Q - W = -W\). The negative sign indicates that the work is done by the system, not on it, meaning the internal energy of the system decreases. By substituting the value of work calculated from step 2 into this formula, the result gives the change in internal energy.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ideal Gas Law
The ideal gas law is a fundamental equation in the study of thermodynamics that connects temperature, pressure, volume, and the amount of gas in a system. It is often represented by the equation \( PV = nRT \) where \( P \) is the pressure, \( V \) is the volume, \( n \) is the number of moles of gas, \( R \) is the ideal gas constant, and \( T \) is the absolute temperature in Kelvin. This equation allows us to describe the behavior of a so-called 'ideal gas', an imaginary gas that perfectly follows this mathematical relationship with no interactions between particles and no volume occupied by the particles themselves.

When dealing with adiabatic processes—an important scenario in thermodynamics—the ideal gas law plays a crucial role as it gives us insights into how the temperature and volume are related when the gas expands or compresses without heat exchange. In the case of the textbook exercise, the ideal gas law helps to assess the relationship between the initial and final states of argon gas during an adiabatic expansion.

By understanding how the properties of the gas change, one can solve for unknown variables, such as work done during a process, using the ideal gas law, as shown in the step-by-step solution provided.
Thermodynamics
Thermodynamics is the branch of physics that studies the interrelation of heat and other forms of energy. In particular, it deals with how energy changes within a system and how energy is transferred between systems. Within this context, an adiabatic process is one of the fundamental concepts in thermodynamics. Such a process occurs without any heat transfer between the system and its surroundings.

An adiabatic expansion—like the one experienced by argon in the textbook exercise—results in the system doing work on the surroundings, hence the internal energy of the gas decreases. To wrap our heads around this, we can invoke the first law of thermodynamics, which states that the change in internal energy of a system is equal to the heat added to the system plus the work done on the system. In an adiabatic process, the heat transfer \( Q \) is zero, thus simplifying the relationship.

In terms of practical application, understanding adiabatic processes is significant in areas such as meteorology, where they explain adiabatic cooling and heating in the atmosphere, and in engineering, particularly in designs involving heat engines and compressors.
Internal Energy of Gases
The internal energy of a gas refers to the total energy contained within the gas, which is the sum of the kinetic energies of all its particles. For an ideal gas, this internal energy is directly proportional to its temperature. Therefore, when an ideal gas expands adiabatically and does work on its surroundings, its temperature decreases, indicating a reduction in internal energy.

In the scenario of the textbook problem, argon is treated as an ideal gas undergoing adiabatic expansion, and its internal energy change is given by \( \Delta U = Q - W \) where \( Q \) is the heat transfer, nonexistent in an adiabatic process, and \( W \) is the work done by the gas. As the gas expands, it performs work, and with no heat added to compensate for this work, its internal energy must decrease, as reflected by the drop in temperature.

The concept of internal energy is paramount because it reflects the energy changes within a gas due to compressions and expansions. This understanding is essential not only in academic problem-solving but also in practical applications like the development of refrigeration cycles and understanding of atmospheric science.

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Most popular questions from this chapter

A cylinder contains 0.100 mol of an ideal monatomic gas. Initially the gas is at \(1.00 \times 10^{5} \mathrm{~Pa}\) and occupies a volume of \(2.50 \times 10^{-3} \mathrm{~m}^{3}\). (a) Find the initial temperature of the gas in kelvins. (b) If the gas is allowed to expand to twice the initial volume, find the final temperature (in kelvins) and pressure of the gas if the expansion is (i) isothermal; (ii) isobaric; (iii) adiabatic.

High-Altitude Research. A large research balloon containing \(2.00 \times 10^{3} \mathrm{~m}^{3}\) of helium gas at \(1.00 \mathrm{~atm}\) and a temperature of \(15.0^{\circ} \mathrm{C}\) rises rapidly from ground level to an altitude at which the atmospheric pressure is only 0.900 atm (Fig. \(\mathbf{P} 19.50\) ). Assume the helium behaves like an ideal gas and the balloon's ascent is too rapid to permit much heat exchange with the surrounding air. (a) Calculate the volume of the gas at the higher altitude. (b) Calculate the temperature of the gas at the higher altitude. (c) What is the change in internal energy of the helium as the balloon rises to the higher altitude?

\( \mathrm{A}\) gas in a cylinder expands from a volume of \(0.110 \mathrm{~m}^{3}\) to \(0.320 \mathrm{~m}^{3} .\) Heat flows into the gas just rapidly enough to keep the pres- sure constant at \(1.65 \times 10^{5} \mathrm{~Pa}\) during the expansion. The total heat added is \(1.15 \times 10^{5} \mathrm{~J}\). (a) Find the work done by the gas. (b) Find the change in internal energy of the gas. (c) Does it matter whether the gas is ideal? Why or why not?

Comparing Thermodynamic Processes. In a cylinder, \(1.20 \mathrm{~mol}\) of an ideal monatomic gas, initially at \(3.60 \times 10^{5} \mathrm{~Pa}\) and \(300 \mathrm{~K},\) expands until its volume triples. Compute the work done by the gas if the expansion is (a) isothermal; (b) adiabatic; (c) isobaric. (d) Show each process in a \(p V\) -diagram. In which case is the absolute value of the work done by the gas greatest? Least? (e) In which case is the absolute value of the heat transfer greatest? Least? (f) In which case is the absolute value of the change in internal energy of the gas greatest? Least?

A cylinder with a piston contains \(0.250 \mathrm{~mol}\) of oxygen at \(2.40 \times 10^{5} \mathrm{~Pa}\) and \(355 \mathrm{~K}\). The oxygen may be treated as an ideal gas. The gas first expands isobarically to twice its original volume. It is then compressed isothermally back to its original volume, and finally it is cooled isochorically to its original pressure. (a) Show the series of processes on a \(p V\) -diagram. Compute (b) the temperature during the isothermal compression; (c) the maximum pressure; (d) the total work done by the piston on the gas during the series of processes.

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