/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 101 Compute the ratio of the rate of... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Compute the ratio of the rate of heat loss through a single-pane window with area \(0.15 \mathrm{~m}^{2}\) to that for a double-pane window with the same area. The glass of a single pane is \(4.2 \mathrm{~mm}\) thick, and the air space between the two panes of the double-pane window is \(7.0 \mathrm{~mm}\) thick. The glass has thermal conductivity \(0.80 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\). The air films on the room and outdoor surfaces of either window have a combined thermal resistance of \(0.15 \mathrm{~m}^{2} \cdot \mathrm{K} / \mathrm{W}\)

Short Answer

Expert verified
The ratio found as the result represents the rates of heat loss between the single-pane and the double-pane window. To find the exact ratio, input your calculated thermal resistances into the ratio formula.

Step by step solution

01

Determine the Thermal Resistance of the Single Pane Window

Utilize the thermal resistance formula, which is \( R = \frac{L}{KA} \). The thickness \( L = 4.2 \) mm, which is equivalent to \( 0.0042 \) m. The thermal conductivity \( K = 0.80 \) W/m.K, and the area \( A = 0.15 \) m². Inserting these values into the formula will give the thermal resistance for a single pane window.
02

Determine the Thermal Resistance of the Double Pane Window

Here, while calculating the thermal resistance for a double pane window, it is necessary to consider the trapped air between the panes. As the air resistance is given as \( 0.15 \) m².K/W, add this to the thermal resistance calculated for the single pane window.
03

Compute the Ratio of the Rates of Heat Loss

The ratio of the rates of heat loss can be obtained by taking the ratio of the thermal resistances. Important to note is that the rate of heat loss is inversely proportional to the thermal resistance, i.e., higher the resistance, lesser is the rate of heat loss.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Heat Transfer
Understanding heat transfer is fundamental to grasping how insulation works. Heat transfer is the movement of thermal energy from a region of higher temperature to one of lower temperature. This process can occur in three primary ways: conduction, convection, and radiation.

Conduction is the heat transfer through a solid material, like the glass in a window pane. Convection is the transfer of heat through fluids, which could be either gases or liquids. Radiation is the emission of heat in the form of infrared rays from hot to cold areas.

In the context of our window example, the heat primarily moves by conduction through the glass and the air, whereas the effect of convection occurs around the surfaces of the window and radiation can be neglected due to the relatively low temperature difference involved. A higher rate of heat loss indicates less effective insulation, while a lower rate is indicative of better insulative properties.
Thermal Conductivity
Thermal conductivity is a property of a material that indicates its ability to conduct heat. It is denoted by the symbol 'K' and is measured in watts per meter-kelvin \( \text{W/m}\cdot\text{K} \). Materials with high thermal conductivity, like metals, are good conductors of heat, while materials with low thermal conductivity, such as wood or fiberglass, are good insulators.

In our example with the window panes, the glass's thermal conductivity is given as \(0.80 \text{ W/m}\cdot\text{K} \), which means that for every meter thickness of the glass and for every degree of temperature difference across it, 0.80 watts of heat will be transferred per second. The concept of thermal resistance is intrinsically linked to conductivity, as materials with high thermal conductivity have lower thermal resistance and vice versa.
Double-Pane Window Insulation
Double-pane windows improve insulation by creating a pocket of air between two layers of glass. This design not only has the insulative benefits of two layers of material but also capitalizes on the low thermal conductivity of the trapped air, greatly reducing heat transfer by conduction.

The air space in double-pane windows acts as an additional layer of insulation. With reference to the exercise, the presence of an air gap of \(7.0 \text{ mm}\) thickness adds to the total thermal resistance. This added resistance is going to contribute significantly to the overall ratio of heat loss between the single and double-pane windows because air, being a gas with low thermal conductivity, imparts significant resistance to heat flow.

When optimal thickness and spacing are chosen for both the glass and the air gap, double-pane windows can significantly reduce the need for additional heating or cooling, leading to energy savings. This principle is an example of why understanding the relationship between thermal resistance and heat transfer is so crucial in practical applications like home insulation.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A steel wire has density \(7800 \mathrm{~kg} / \mathrm{m}^{3}\) and mass \(2.50 \mathrm{~g}\). It is stretched between two rigid supports separated by \(0.400 \mathrm{~m}\). (a) When the temperature of the wire is \(20.0^{\circ} \mathrm{C}\), the frequency of the fundamental standing wave for the wire is \(440 \mathrm{~Hz}\). What is the tension in the wire? (b) What is the temperature of the wire if its fundamental standing wave has frequency \(460 \mathrm{~Hz}\) ? For steel the coefficient of linear expansion is \(1.2 \times 10^{-5} \mathrm{~K}^{-1}\) and Young's modulus is \(20 \times 10^{10} \mathrm{~Pa}\)

Consider a poor lost soul walking at \(5 \mathrm{~km} / \mathrm{h}\) on a hot day in the desert, wearing only a bathing suit. This person's skin temperature tends to rise due to four mechanisms: (i) energy is generated by metabolic reactions in the body at a rate of \(280 \mathrm{~W},\) and almost all of this energy is converted to heat that flows to the skin; (ii) heat is delivered to the skin by convection from the outside air at a rate equal to \(k^{\prime} A_{\mathrm{skin}}\left(T_{\mathrm{air}}-T_{\mathrm{skin}}\right),\) where \(k^{\prime}\) is \(54 \mathrm{~J} / \mathrm{h} \cdot \mathrm{C}^{\circ} \cdot \mathrm{m}^{2},\) the exposed skin area \(A_{\text {skin }}\) is \(1.5 \mathrm{~m}^{2},\) the air temperature \(T_{\text {air }}\) is \(47^{\circ} \mathrm{C},\) and the skin temperature \(T_{\text {skin }}\) is \(36^{\circ} \mathrm{C} ;\) (iii) the skin absorbs radiant energy from the sun at a rate of \(1400 \mathrm{~W} / \mathrm{m}^{2} ;\) (iv) the skin absorbs radiant energy from the environment, which has temperature \(47^{\circ} \mathrm{C}\). (a) Calculate the net rate (in watts) at which the person's skin is heated by all four of these mechanisms. Assume that the emissivity of the skin is \(e=1\) and that the skin temperature is initially \(36^{\circ} \mathrm{C}\). Which mechanism is the most important? (b) At what rate (inL/h) must perspiration evaporate from this person's skin to maintain a constant skin temperature? (The heat of vaporization of water at \(36^{\circ} \mathrm{C}\) is \(2.42 \times 10^{6} \mathrm{~J} / \mathrm{kg} .\) ) (c) Suppose the person is protected by light-colored clothing \((e \approx 0)\) and only \(0.45 \mathrm{~m}^{2}\) of skin is exposed. What rate of perspiration is required now? Discuss the usefulness of the traditional clothing worn by desert peoples.

Derive an equation that gives \(T_{\mathrm{K}}\) as a function of \(T_{\mathrm{F}}\) to the nearest hundredth of a degree. Solve the equation and thereby obtain an equation for \(T_{\mathrm{F}}\) as a function of \(T_{\mathrm{K}}\).

The heat one feels when sitting near the fire in a fireplace or at a campfire is due almost entirely to thermal radiation. (a) Estimate the diameter and length of an average campfire log. (b) Compute the surface area of such a log. (c) Use the StefanBoltzmann law to determine the power emitted by thermal radiation by such a log when it burns at a typical temperature of \(700^{\circ} \mathrm{C}\) in a surrounding air temperature of \(20.0^{\circ} \mathrm{C}\). The emissivity of a burning log is close to unity.

What is the amount of heat input to your skin when it receives the heat released (a) by \(25.0 \mathrm{~g}\) of steam initially at \(100.0^{\circ} \mathrm{C},\) when it is cooled to skin temperature \(\left(34.0^{\circ} \mathrm{C}\right) ?\) (b) By \(25.0 \mathrm{~g}\) of water initially at \(100.0^{\circ} \mathrm{C},\) when it is cooled to \(34.0^{\circ} \mathrm{C}\) ? (c) What does this tell you about the relative severity of burns from steam versus burns from hot water?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.