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Derive an equation that gives \(T_{\mathrm{K}}\) as a function of \(T_{\mathrm{F}}\) to the nearest hundredth of a degree. Solve the equation and thereby obtain an equation for \(T_{\mathrm{F}}\) as a function of \(T_{\mathrm{K}}\).

Short Answer

Expert verified
The equation that gives temperature in Kelvin (T_{\mathrm{K}}) as a function of temperature in Fahrenheit (T_{\mathrm{F}}) is T_{\mathrm{K}} = ((T_{\mathrm{F}} + 459.67) * 5/9). After rearranging this equation to express temperature in Fahrenheit (T_{\mathrm{F}}) as a function of temperature in Kelvin (T_{\mathrm{K}}), it becomes T_{\mathrm{F}} = (T_{\mathrm{K}} * 9/5) - 459.67.

Step by step solution

01

Derive equation for T_{\mathrm{K}} as a function of T_{\mathrm{F}}

We start with the known conversion formula from Fahrenheit to Kelvin, which is T_{\mathrm{K}} = (T_{\mathrm{F}} + 459.67) * (5/9). Here, 459.67 is the offset from Fahrenheit zero to absolute zero, and 5/9 is the rate of change between Fahrenheit and Kelvin (i.e. 1 degree Fahrenheit change is equal to 5/9 of a Kelvin). So, this formula allows to express temperature in Kelvin as function of temperature in Fahrenheit.
02

Round to the nearest hundredth

As our task is to present the T_{\mathrm{K}} as a function of T_{\mathrm{F}} to the nearest hundredth of a degree, we can simplify it as T_{\mathrm{K}} = ((T_{\mathrm{F}} + 459.67) * 5/9).toFixed(2). Here, the function toFixed(2) is used to round the result to the nearest hundredth.
03

Convert equation to make T_{\mathrm{F}} as a function of T_{\mathrm{K}}

To express temperature in Fahrenheit (T_{\mathrm{F}}) as a function of temperature in Kelvin (T_{\mathrm{K}}), we rearrange the formula from Step 1 to solve for T_{\mathrm{F}}. We multiply the T_{\mathrm{K}} by 9/5 to cancel out the multiplication done in original formula and then subtract 459.67.So, the equation becomes T_{\mathrm{F}} = (T_{\mathrm{K}} * 9/5) - 459.67. Now, we have an equation for T_{\mathrm{F}} as a function of T_{\mathrm{K}}.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kelvin to Fahrenheit Equation
Understanding how to convert temperatures between different scales is fundamental in science, particularly when moving between the Kelvin and Fahrenheit scales. The Kelvin scale is an absolute temperature scale, meaning it starts at absolute zero, the theoretical point where particles have minimum thermal motion.

The equation to convert from Kelvin (\(T_{\mathrm{K}}\)) to Fahrenheit (\(T_{\mathrm{F}}\)) is given by \[T_{\mathrm{F}} = (T_{\mathrm{K}} \times \frac{9}{5}) - 459.67\] This equation allows for the representation of temperature in the more commonly used Fahrenheit scale from the Kelvin scale, which is typically used in scientific contexts.

When using this equation, one should consider the precision required. For example, expressing temperature to the nearest hundredth of a degree implies a higher level of accuracy and can be depicted as \(T_{\mathrm{F}}.toFixed(2)\) in programming, where .toFixed(2) rounds the result to two decimal places.
Temperature Scale Conversion
Temperature scale conversion is essential in various fields including meteorology, cooking, and scientific research. It involves converting temperature measurements from one scale to another. The most common temperature scales are Celsius, Fahrenheit, and Kelvin.

  • The Celsius scale is used for everyday temperature measurements in most countries, except the United States.
  • The Fahrenheit scale is primarily used in the United States for weather forecasts, cooking, and other everyday measurements.
  • The Kelvin scale is used in the scientific community because it is an absolute scale starting at absolute zero, where theoretically there is no thermal energy in a substance.

Each temperature scale has its own uses and contexts for which it is best suited. Scientists and engineers often use the Kelvin and Celsius scales because they are based on the properties of water at sea level. Conversely, the Fahrenheit scale is commonly used for its finer resolution and its relevance to human-experienced temperatures.
Fahrenheit to Kelvin Equation
The counterpart to converting from Kelvin to Fahrenheit, the Fahrenheit to Kelvin equation is crucial for scientists who work with temperature data in the U.S. system but need to report or analyze the data in the internationally recognized metric system. The equation to convert from Fahrenheit to Kelvin is \[T_{\mathrm{K}} = (T_{\mathrm{F}} + 459.67) \times \frac{5}{9}\]

This formula incorporates the adjustment for the different starting points of the scales—the freezing point of water is 32 degrees Fahrenheit but 273.15 Kelvin—and the rate at which the scales increase. The factor of 5/9 represents the ratio of one Fahrenheit degree change to the corresponding Kelvin change.

For precise scientific work, rounding may be significant, such as to the nearest hundredth of a Kelvin. This level of precision is typically indicated in calculations by using rounding functions or significant digits.

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Most popular questions from this chapter

In an effort to stay awake for an all-night study session, a student makes a cup of coffee by first placing a \(200 \mathrm{~W}\) electric immersion heater in \(0.320 \mathrm{~kg}\) of water. (a) How much heat must be added to the water to raise its temperature from \(20.0^{\circ} \mathrm{C}\) to \(80.0^{\circ} \mathrm{C} ?\) (b) How much time is required? Assume that all of the heater's power goes into heating the water.

You put a bottle of soft drink in a refrigerator and leave it until its temperature has dropped \(10.0 \mathrm{~K}\). What is its temperature change in (a) \(\mathrm{F}^{\circ}\) and \((\mathrm{b}) \mathrm{C}^{\circ} ?\)

A plastic cup of negligible mass contains \(0.280 \mathrm{~kg}\) of an unknown liquid at a temperature of \(30.0^{\circ} \mathrm{C}\). A \(0.0270 \mathrm{~kg}\) mass of ice at a temperature of \(0.0^{\circ} \mathrm{C}\) is added to the liquid, and when thermal equilibrium is reached the temperature of the combined substances is \(14.0^{\circ} \mathrm{C}\). Assuming no heat is exchanged with the surroundings, what is the specific heat capacity of the unknown liquid?

A steel wire has density \(7800 \mathrm{~kg} / \mathrm{m}^{3}\) and mass \(2.50 \mathrm{~g}\). It is stretched between two rigid supports separated by \(0.400 \mathrm{~m}\). (a) When the temperature of the wire is \(20.0^{\circ} \mathrm{C}\), the frequency of the fundamental standing wave for the wire is \(440 \mathrm{~Hz}\). What is the tension in the wire? (b) What is the temperature of the wire if its fundamental standing wave has frequency \(460 \mathrm{~Hz}\) ? For steel the coefficient of linear expansion is \(1.2 \times 10^{-5} \mathrm{~K}^{-1}\) and Young's modulus is \(20 \times 10^{10} \mathrm{~Pa}\)

In very cold weather a significant mechanism for heat loss by the human body is energy expended in warming the air taken into the lungs with each breath. (a) On a cold winter day when the temperature is \(-20^{\circ} \mathrm{C},\) what amount of heat is needed to warm to body temperature \(\left(37^{\circ} \mathrm{C}\right)\) the \(0.50 \mathrm{~L}\) of air exchanged with each breath? Assume that the specific heat of air is \(1020 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\) and that \(1.0 \mathrm{~L}\) of air has mass \(1.3 \times 10^{-3} \mathrm{~kg} .\) (b) How much heat is lost per hour if the respiration rate is 20 breaths per minute?

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