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A police siren of frequency \(f_{\text {siren }}\) is attached to a vibrating platform. The platform and siren oscillate up and down in simple harmonic motion with amplitude \(A_{\mathrm{p}}\) and frequency \(f_{\mathrm{p}}\). (a) Find the maximum and minimum sound frequencies that you would hear at a position directly above the siren. (b) At what point in the motion of the platform is the maximum frequency heard? The minimum frequency? Explain.

Short Answer

Expert verified
The maximum and minimum frequencies that can be heard directly above the siren are given by \(f_{obs-max} = f_{siren} \frac{v + ωA_{p}}{v}\) and \(f_{obs-min} = f_{siren} \frac{v - ωA_{p}}{v}\) respectively. The maximum frequency occurs when the platform starts moving upwards from the lowest point. In contrast, the minimum frequency occurs when the platform starts moving downward from the highest point.

Step by step solution

01

Understand the Situation

It's understood that the siren's frequency is changing due to the movement of the platform which is undergoing simple harmonic motion. So, we use a modified form of the frequency observed during Doppler effect. This is given by \(f_{obs} = f_{siren} \frac{v + v_{source}}{v}\), where \(v\) is speed of sound, \(v_{source}\) is speed of source.
02

Find Maximum and Minimum Frequencies

For maximum frequency, we consider the situation when platform move upwards or towards observer. Maximum speed of source is at mean position. So, \(v_{source} = ωA_{p}\), where \(ω = 2πf_{p}\). Substituting all values, we get \(f_{obs-max} = f_{siren} \frac{v + ωA_{p}}{v}\). Similarly, for minimum frequency when platform is moving downwards or away from the observer, we get \(f_{obs-min} = f_{siren} \frac{v - ωA_{p}}{v}\).
03

Determine Maximum And Minimum Frequency Points

The maximum observed frequency happens when the platform is moving upwards, starting its cycle from the lowest point. As for the minimum observed frequency, it happens when the platform starts moving downwards from the highest point.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Simple Harmonic Motion
Simple harmonic motion (SHM) is a type of periodic motion or oscillation where the restoring force is directly proportional to the displacement. This means that the force pulling or pushing the object back into its original position increases as it moves further away. This kind of motion is common in nature and man-made systems, and includes motions like the swinging of a pendulum or the oscillation of a spring.

Key characteristics of SHM include:
  • Amplitude ( A_p ): The maximum extent of the oscillation measured from the position of equilibrium.
  • Frequency ( f_p ): How many times the oscillation repeats itself in one second.
  • Angular frequency ( ω ): Related to the frequency, calculated as ω = 2Ï€f_p .
  • Phase: The specific point in the cycle of motion at a given time.
Understanding SHM is vital to solving problems like the one in the exercise because it describes the motion of both the siren and platform. It helps us calculate velocities and accelerations that affect how frequencies are observed.
Frequency Shift
The frequency shift in the observed sound from a moving source is often explained using the Doppler Effect. The Doppler Effect describes the change in frequency or wavelength of a wave in relation to an observer who is moving relative to the wave source. When the source of a sound wave, like a siren, is moving, its frequency appears different to an observer than if it were stationary.

In the scenario given in the exercise:
  • The siren's frequency heard by an observer changes as the platform moves.
  • When the platform moves upward, towards the observer, the sound waves compress resulting in a higher frequency, or a pitch that is perceived as higher ( f_{obs-max} ).
  • Conversely, as the platform moves downward, away from the observer, the sound waves stretch leading to a lower frequency ( f_{obs-min} ).
The extent of the frequency shift is influenced by the platform's movement speed and direction at any given point in its oscillation.
Sound Waves
Sound waves are mechanical waves that travel through a medium such as air, water, or solids. They are created by vibrating objects, and in the context of this exercise, by the vibrating police siren. As they move, sound waves create areas of compression and rarefaction.
  • Compression is where the air particles are closest together, increasing pressure.
  • Rarefaction is where particles are more spread out, decreasing pressure.
Understanding how sound waves interact with their environment can help us grasp the Doppler Effect described. The waves move through the medium at a speed v (always around 343m/s in air at room temperature).

For the observer, the frequency of these waves matters. When the waves are compressed due to the source moving towards the observer, the frequency increases. Alternatively, when the source moves away and waves are stretched out, the perceived frequency decreases. This knowledge is critical to solving for the right frequencies when dealing with moving sources of sound like in the given exercise.

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Most popular questions from this chapter

(a) In a liquid with density \(1300 \mathrm{~kg} / \mathrm{m}^{3},\) longitudinal waves with frequency \(400 \mathrm{~Hz}\) are found to have wavelength \(8.00 \mathrm{~m}\). Calculate the bulk modulus of the liquid. (b) A metal bar with a length of \(1.50 \mathrm{~m}\) has density \(6400 \mathrm{~kg} / \mathrm{m}^{3}\). Longitudinal sound waves take \(3.90 \times 10^{-4} \mathrm{~s}\) to travel from one end of the bar to the other. What is Young's modulus for this metal?

You have a stopped pipe of adjustable length close to a taut \(62.0 \mathrm{~cm}, 7.25 \mathrm{~g}\) wire under a tension of \(4110 \mathrm{~N}\). You want to adjust the length of the pipe so that, when it produces sound at its fundamental frequency, this sound causes the wire to vibrate in its second overtone with very large amplitude. How long should the pipe be?

Many professional singers have a range of \(2 \frac{1}{2}\) octaves or even greater. Suppose a soprano's range extends from A below middle C (frequency \(220 \mathrm{~Hz}\) ) up to E-flat above high \(\mathrm{C}\) (frequency \(1244 \mathrm{~Hz}\) ). Although the vocal tract is complicated, we can model it as a resonating air column, like an organ pipe, that is open at the top and closed at the bottom. The column extends from the mouth down to the diaphragm in the chest cavity. Assume that the lowest note is the fundamental. How long is this column of air if \(v=354 \mathrm{~m} / \mathrm{s} ?\) Does your result seem reasonable, on the basis of observations of your body?

A stationary police car emits a sound of frequency \(1200 \mathrm{~Hz}\) that bounces off a car on the highway and returns with a frequency of \(1250 \mathrm{~Hz}\). The police car is right next to the highway, so the moving car is traveling directly toward or away from it. (a) How fast was the moving car going? Was it moving toward or away from the police car? (b) What frequency would the police car have received if it had been traveling toward the other car at \(20.0 \mathrm{~m} / \mathrm{s} ?\)

At point \(A, 3.0 \mathrm{~m}\) from a small source of sound that is emitting uniformly in all directions, the sound intensity level is \(53 \mathrm{~dB}\). (a) What is the intensity of the sound at \(A ?\) (b) How far from the source must you go so that the intensity is one-fourth of what it was at \(A ?\) (c) How far must you go so that the sound intensity level is one-fourth of what it was at \(A ?\) (d) Does intensity obey the inverse-square law? What about sound intensity level?

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