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The sound source of a ship’s sonar system operates at a frequency of \(18.0 \mathrm{kHz}\). The speed of sound in water (assumed to be at a uniform \(20^{\circ} \mathrm{C}\) ) is \(1482 \mathrm{~m} / \mathrm{s}\). (a) What is the wavelength of the waves emitted by the source? (b) What is the difference in frequency between the directly radiated waves and the waves reflected from a whale traveling directly toward the ship at \(4.95 \mathrm{~m} / \mathrm{s} ?\) The ship is at rest in the water.

Short Answer

Expert verified
\[ \lambda = 0.0823 \, \text{m} , ~ \Delta f = 63 \, \text{Hz} \] The wavelength of the sonar wave is \( 0.0823 \, \text{m} \), and the difference in frequency due to the Doppler effect is \( 63 \, \text{Hz} \).

Step by step solution

01

Calculate the Wavelength of the Waves Emitted by the Sonar System

We know from the wave equation that the speed of wave (v) equals frequency (f) multiplied by wavelength (\(\lambda\)). We can rearrange the equation to solve for wavelength, giving us \(\lambda = \frac{v}{f}\). Substituting the given values, we have \(\lambda = \frac{1482 \, \text{m/s}}{18.0 \times 10^3 \, \text{Hz}}\). This will give us the wavelength of the waves emitted by the sonar system.
02

Calculate the Observed Frequency due to Doppler Effect

We will use the formula for observed frequency in the Doppler effect \(f_{\text{obs}} = f_{\text{source}} \frac{v + v_{\text{observer}}}{v - v_{\text{source}}}\) where \(v_{\text{observer}} = 0\) (since the ship is at rest) and \(v_{\text{source}} = -4.95 \, \text{m/s}\). Therefore the observed frequency, \(f_{\text{obs}} = 18.0 \times 10^3 \, \text{Hz} \frac{1482 \, \text{m/s}}{1482 \, \text{m/s} - (-4.95) \, \text{m/s}}\). This computation yield the observed frequency due to the Doppler effect.
03

Calculate the Difference in Frequency due to Doppler Effect

Finally, to find the difference in frequency, we subtract the source frequency from the observed frequency, i.e, \(\Delta f = f_{\text{obs}} - f_{\text{source}}\). This calculation gives us the difference in frequency between the directly emitted sound waves and the waves reflected back from the whale, due to the Doppler effect.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Doppler Effect in Sonar Systems
The Doppler effect is a phenomenon observed when there is relative motion between a sound source and an observer. It manifests as a change in frequency and pitch of the sound accordingly. In the context of sonar systems like the one on a ship used for detecting objects underwater, such as whales, the Doppler effect plays a crucial role. When the sonar's sound waves hit a moving object, the waves are reflected with a change in frequency dependent upon the relative speed and direction of the object. If the object is moving towards the source, the frequency increases, and when it moves away, the frequency decreases.

This phenomenon is not just a curiosity—it's essential for navigation and detection in marine contexts, giving information about the speed and direction of the object in relation to the ship. During the computation in the provided exercise, it is important to consider the sound source at rest relative to the water, ensuring that the observer's velocity in the Doppler effect formula is set to zero. The minus sign in the velocity of the source indicates that the whale is moving towards the ship, leading to an increase in the observed frequency.
Calculating Wavelength in Sonar Systems
Wavelength calculation is a fundamental aspect of physics that underlies the functioning of sonar systems. In the exercise, we apply the wave equation, which relates the speed of sound in a medium, the frequency of the wave, and its wavelength (denoted by \(\lambda\)). The formula \(\lambda = \frac{v}{f}\) allows us to calculate the distance between consecutive wave crests, which is essential for sonar operation since it determines the resolution and range of the sonar signal.

In our specific case, by dividing the speed of sound in water by the frequency at which the sonar system operates, we obtain the wavelength of the waves. The speed of sound in water is considerably different from in air, generally leading to longer wavelengths underwater. This impacts how well the sonar can detect and differentiate objects, making an accurate calculation of wavelength crucial for efficient sonar operation. In the exercise, you'll use the given constants, ensuring the resulting wavelength is in correct units, which is typically meters for such large-scale applications.
Speed of Sound in Water and its Significance
The speed of sound in water is an essential parameter for any calculation involving sonar systems. Unlike the speed of sound in air, which is about 343 meters per second (m/s) at room temperature, sound travels much faster in water, with an average speed of around 1482 m/s at \(20^\circ\mathrm{C}\). This speed can vary depending on various factors such as temperature, salinity, and depth of the water, which all affect how sonar systems are used and interpreted.

The speed of sound in water affects both the wavelength of the sonar waves and the interpretation of the Doppler effect. For instance, warmer water temperatures generally make sound waves travel faster. When solving physics problems involving sonar, it's crucial to use the correct speed value for accuracy. Notably, in the exercise provided, using the speed of sound in water allows us to calculate the wavelength and understand the effect of an object's velocity on the frequency perceived by the sonar system.

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Most popular questions from this chapter

An organ pipe has two successive harmonics with frequencies 1372 and \(1764 \mathrm{~Hz}\). (a) Is this an open or a stopped pipe? Explain. (b) What two harmonics are these? (c) What is the length of the pipe?

Standing sound waves are produced in a pipe that is \(1.20 \mathrm{~m}\) long. For the fundamental and first two overtones, determine the locations along the pipe (measured from the left end) of the displacement nodes and the pressure nodes if (a) the pipe is open at both ends and (b) the pipe is closed at the left end and open at the right end.

(a) By what factor must the sound intensity be increased to raise the sound intensity level by \(13.0 \mathrm{~dB} ?\) (b) Explain why you don't need to know the original sound intensity.

A police siren of frequency \(f_{\text {siren }}\) is attached to a vibrating platform. The platform and siren oscillate up and down in simple harmonic motion with amplitude \(A_{\mathrm{p}}\) and frequency \(f_{\mathrm{p}}\). (a) Find the maximum and minimum sound frequencies that you would hear at a position directly above the siren. (b) At what point in the motion of the platform is the maximum frequency heard? The minimum frequency? Explain.

A stationary source emits sound waves of frequency \(f_{\mathrm{s}}\). There is no wind blowing. A device for detecting sound waves and measuring their observed frequency moves toward the source with speed \(v_{\mathrm{L}}\) and the observed frequency of the sound waves is \(f_{\mathrm{L}}\). The measurement is repeated for different values of \(v_{\mathrm{L}}\). You plot the results as \(f_{\mathrm{L}}\) versus \(v_{\mathrm{L}}\) and find that your data lie close to a straight line that has slope \(1.75 \mathrm{~m}^{-1}\) and \(y\) -intercept \(600.0 \mathrm{~Hz}\). What are your experimental results for the speed of sound in the still air and for the frequency \(f_{\mathrm{s}}\) of the source?

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