/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 53 You open a restaurant and hope t... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

You open a restaurant and hope to entice customers by hanging out a sign (Fig. \(\mathbf{P} 1 \mathbf{1 . 5 3}\) ). The uniform horizontal beam supporting the sign is \(1.50 \mathrm{~m}\) long, has a mass of \(16.0 \mathrm{~kg},\) and is hinged to the wall. The sign itself is uniform with a mass of \(28.0 \mathrm{~kg}\) and overall length of \(1.20 \mathrm{~m}\). The two wires supporting the sign are each \(32.0 \mathrm{~cm}\) long, are \(90.0 \mathrm{~cm}\) apart, and are equally spaced from the middle of the sign. The cable supporting the beam is \(2.00 \mathrm{~m}\) long. (a) What minimum tension must your cable be able to support without having your sign come crashing down? (b) What minimum vertical force must the hinge be able to support without pulling out of the wall?

Short Answer

Expert verified
The minimum tension in the cable for the sign not to fall should be 412.3N, and the minimum vertical force at the hinge should be 18.9N.

Step by step solution

01

Calculate the force of gravity on the beam and the sign

The force of gravity acting on an object is given by the product of its mass and the acceleration due to gravity. It acts downwards at the center of mass of the object. So, the force of gravity on the beam, \( F_{G_{beam}} \), is \( 16.0~kg * 9.8~m/s^2 = 156.8~N \) acting at a distance of 0.75m from the hinge. Similarly, the force of gravity on the sign, \( F_{G_{sign}} \), is \( 28.0~kg * 9.8~m/s^2 = 274.4~N \) acting at a distance of 1.50m + 0.60m = 2.10m from the hinge.
02

Write the equations of static equilibrium

The two conditions for static equilibrium are that the net force and the net torque acting on an object are zero. The net force equation is: \( \Sigma F_{vert} = 0 = F_{hinge} - F_{G_{beam}} - F_{G_{sign}} + F_{T}\), where \( F_{T} \) is the tension in the cable and \( F_{hinge} \) is the vertical force that the hinge must supply. The net torque equation (taking clockwise moments as positive) is: \( \Sigma \tau = 0 = F_{G_{beam}} * 0.75m + F_{G_{sign}} * 2.10m - F_{T} * 2.00m \). These equations will allow us to solve for the unknowns \( F_{T} \) and \( F_{hinge} \).
03

Solve the equations for \( F_{T} \) and \( F_{hinge} \)

Substitute the known values into the torque equation and solve it for the tension \( F_{T} \). That will result in: \( F_{T} = (156.8N * 0.75m + 274.4N * 2.10m) / 2.00m = 412.3N \). Then, substitute the value of \( F_{T} \) into the force equation and solve for \( F_{hinge} \). That gives us: \( F_{hinge} = 156.8N + 274.4N - 412.3N = 18.9N \). Notice that the sign of \( F_{hinge} \) is positive, which indicates that the hinge force acts upward.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Force of Gravity
Understanding the force of gravity is essential when analyzing static equilibrium scenarios. Gravity is a fundamental force of nature that pulls objects toward the center of the Earth. It acts on every mass, creating a downward force proportional to the object's mass.

In physics, this force is calculated as the product of the object's mass (m) and the acceleration due to gravity (g). The acceleration due to gravity on Earth's surface is approximately \( 9.8\text{ m/s}^2 \). Therefore, the gravitational force (often referred to as weight) is given by the formula: \[ F_g = m \times g \].

In static equilibrium problems involving objects supported by structures, like beams or signs, knowing the force of gravity acting at the center of mass helps establish the forces necessary for equilibrium. For example, to prevent a hanging sign from collapsing, the tension in the supporting cable and the force exerted by the hinge must counteract the gravitational pull on the sign and beam.
Net Torque
Net torque is a pivotal concept in understanding how forces lead to rotational motion and is crucial for analyzing systems in static equilibrium. Torque, sometimes called moment of force, measures the tendency of a force to rotate an object around an axis, fulcrum, or pivot.

Mathematically, torque (\( \tau \)) is the product of the force (F) and the perpendicular distance (d) from the axis of rotation to the line of action of the force: \[ \tau = F \times d \]. When examining the sign in the given problem, we consider the net torque about the hinge point. For an object to be in static equilibrium, the sum of all torques must be zero.

This principle allows us to write down equations that include all the forces acting on the system. In the case of the restaurant's sign, the gravitational forces on both the beam and the sign generate torques that must be countered by the torque due to the tension in the cable to achieve equilibrium.
Tension in Physics
Tension in physics refers to the force transmitted through a string, rope, cable, or any other similar medium that is pulled tight by forces acting at opposite ends. In equilibrium problems, tension must be carefully calculated to ensure structural integrity and safety.

Tension is a pulling force since ropes cannot push effectively. This force is always directed along the length of the medium and away from the object exerting the force. In the context of the restaurant sign, the cable must provide enough tension to support the weight of the beam and the sign, preventing them from falling under the influence of gravity.

The value of this tension can be obtained from the torque equation, as it plays a critical role in countering the rotational effect (torque) of the weights of the beam and the sign. In static equilibrium, the tension keeps the system balanced and steady, ensuring that no part of the sign or the structure holding it undergoes any acceleration.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The bulk modulus for bone is \(15 \mathrm{GPa}\). (a) If a diver-in-training is put into a pressurized suit, by how much would the pressure have to be raised (in atmospheres) above atmospheric pressure to compress her bones by \(0.10 \%\) of their original volume? (b) Given that the pressure in the ocean increases by \(1.0 \times 10^{4} \mathrm{~Pa}\) for every meter of depth below the surface, how deep would this diver have to go for her bones to compress by \(0.10 \%\) ? Does it seem that bone compression is a problem she needs to be concerned with when diving?

A specimen of oil having an initial volume of \(600 \mathrm{~cm}^{3}\) is subjected to a pressure increase of \(3.6 \times 10^{6} \mathrm{~Pa}\), and the volume is found to decrease by \(0.45 \mathrm{~cm}^{3} .\) What is the bulk modulus of the material? The compressibility?

An engineer is designing a conveyor system for loading hay bales into a wagon (Fig. \(\mathbf{P} 1 \mathbf{1} .79)\). Each bale is \(0.25 \mathrm{~m}\) wide, \(0.50 \mathrm{~m}\) high, and \(0.80 \mathrm{~m}\) long (the dimension perpendicular to the plane of the figure), with mass \(30.0 \mathrm{~kg}\). The center of gravity of each bale is at its geometrical center. The coefficient of static friction between a bale and the conveyor belt is \(0.60,\) and the belt moves with constant speed. (a) The angle \(\beta\) of the conveyor is slowly increased. At some critical angle a bale will tip (if it doesn't slip first), and at some different critical angle it will slip (if it doesn't tip first). Find the two critical angles and determine which happens at the smaller angle. (b) Would the outcome of part (a) be different if the coefficient of friction were \(0.40 ?\)

A metal rod that is \(4.00 \mathrm{~m}\) long and \(0.50 \mathrm{~cm}^{2}\) in crosssectional area is found to stretch \(0.20 \mathrm{~cm}\) under a tension of \(5000 \mathrm{~N}\). What is Young's modulus for this metal?

Two people carry a heavy electric motor by placing it on a light board \(2.00 \mathrm{~m}\) long. One person lifts at one end with a force of \(400 \mathrm{~N}\), and the other lifts the opposite end with a force of \(600 \mathrm{~N}\). (a) What is the weight of the motor, and where along the board is its center of gravity located? (b) Suppose the board is not light but weighs \(200 \mathrm{~N},\) with its center of gravity at its center, and the two people exert the same forces as before. What is the weight of the motor in this case, and where is its center of gravity located?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.