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A specimen of oil having an initial volume of \(600 \mathrm{~cm}^{3}\) is subjected to a pressure increase of \(3.6 \times 10^{6} \mathrm{~Pa}\), and the volume is found to decrease by \(0.45 \mathrm{~cm}^{3} .\) What is the bulk modulus of the material? The compressibility?

Short Answer

Expert verified
The bulk modulus of the oil is \(4.8 x 10^{9} Pa\) and the compressibility is \(2.08 x 10^{-10} Pa^{-1}\).

Step by step solution

01

Calculate the fractional change in volume

First, the change in volume must be calculated to compute for bulk modulus. The initial volume (\(V\)) of the oil is given as \(600 cm^3\), and the volume decrease (\( \Delta V\)) is \(0.45 cm^3\). The fractional change in volume can be calculated using the formula \( \Delta V /V\), which gives \(0.45 cm^3 / 600 cm^3 = 7.5 x 10^{-4}\).
02

Calculate the bulk modulus

Second, the bulk modulus can now be determined using the formula \(B = - \Delta P / \Delta V/V\). The change in pressure (\(\Delta P\)) is given as \(3.6 x 10^{6} Pa\), and the fractional change in volume (\(\Delta V/V\)) was calculated in the previous step as \(7.5 x 10^{-4}\). Therefore, the bulk modulus is \((-1) * (3.6 x 10^{6} Pa) / (7.5 x 10^{-4}) = -4.8 x 10^{9} Pa\). The negative sign indicates a decrease in volume with an increase in pressure, which is expected for a compression scenario.
03

Calculate the compressibility

Lastly, the compressibility can be calculated. It is simply the inverse of bulk modulus, implying \( \beta = 1 / B\). Therefore, the compressibility of the oil is \(1 / -4.8 x 10^{9} Pa = -2.08 x 10^{-10} Pa^{-1}\). We ignore the negative sign since compressibility is always positive. Thus, the compressibility is \(2.08 x 10^{-10} Pa^{-1}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Compressibility
Compressibility is a key property of materials that depicts how much a material can reduce in volume under applied pressure. It's the ability of a substance to decrease its volume when subjected to an external force. Materials that are highly compressible can be squished into a smaller volume with relative ease while others will resist such changes.

Compressibility is mathematically defined as the inverse of the bulk modulus, denoted by the symbol \( \beta \). It indicates how much the material could be compressed per unit increase in applied pressure. In simple terms, compressibility helps us understand and predict how different materials will behave when they undergo pressure changes.
  • High compressibility: Large volume change with little pressure change
  • Low compressibility: Small volume change with high pressure change
It's a crucial parameter especially in fields like fluid dynamics and engineering where materials are often subjected to large loads and pressure conditions.
Pressure-Volume Relationship
The pressure-volume relationship is a fundamental aspect of physics and materials science, linking how a material's volume changes with applied pressure. This relationship is crucial when studying gases, liquids, and solids, as it helps predict how they will behave under different conditions.

In the context of bulk modulus, pressure and volume are inversely related, meaning when high pressure is applied, the volume tends to decrease. The formula for bulk modulus, \( B = - \frac{\Delta P}{\Delta V/V} \), encapsulates this inverse relationship:
  • \( \Delta P \) is the change in pressure
  • \( \Delta V/V \) is the fractional change in volume
The negative sign in the formula indicates that as pressure increases, volume decreases, a typical behavior in compressible materials. Understanding this pressure-volume relationship is crucial in designing systems that require precise control over volume changes, like hydraulic machinery and pressure vessels.
Fractional Change in Volume
The fractional change in volume describes the fraction of change in a material's volume compared to its original volume when it's compressed or expanded. It helps quantify the degree of compression or expansion a material undergoes due to applied pressure.

You calculate it using the formula \( \Delta V/V \), where \( \Delta V \) is the change in volume, and \( V \) is the initial volume. In this case, it would be the ratio of how much the volume changes to what the volume initially was.
  • \( V \) - Initial Volume
  • \( \Delta V \) - Change in Volume
  • Fractional Change = \( \Delta V/V \)
This quantity is key when evaluating the compressibility and bulk modulus of materials, as it provides a normalized measure of the volume change. By understanding fractional changes, scientists and engineers can assess material behavior more consistently, which informs design and safety considerations in applications like pressure vessels and mechanical structures.

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Most popular questions from this chapter

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