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Chapter 2: Q80PP (page 543)

In some applications of ultrasound, such as its use on cranial tissues, large reflections from the surrounding bones can produce standing waves. This is of concern because the large pressure amplitude in an antinode can damage tissues. For a frequency of 1.00鈥�MHz , what is the distance between antinodes in tissue?

Short Answer

Expert verified

The correct option is b.

Step by step solution

01

Given Data

The given frequency is 1.00鈥塎贬锄.

02

Relation between distance and wavelength

The distance between nodes is related to the wavelength as

d=苍位2=nv2f

03

Calculate the distance

Put the values of v, fand n=1to get d-

d=nv2f=1脳1540鈥尘/s2脳106鈥塇锄=0.77脳10鈭�3m=0.77鈥尘m

The result is d=0.77鈥尘m.

Hence, the distance between antinodes is approximately 0.75mm.

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