91Ó°ÊÓ

The given data can be listed below as,

• The length of the string is, \(L = 63.5\;{\rm{cm}} = 63.5 \times {10^{ - 2}}\;{\rm{m}}\).
• The fundamental frequency is, \({f_1} = 245\;{\rm{Hz}}\).

A wave's velocity is its rate of movement. By using the formula wave speed is equal to the product of frequency and wavelength, wave speed is correlated with wavelength, frequency, and period. Visible light, an electromagnetic wave, travels at a speed that is most frequently employed.

The relation between fundamental frequency, velocity and length of string is expressed as,

\({f_1} = \frac{v}{{2L}}\) …(1)

Here \({f_1}\) is the fundamental frequency, \(v\) is the velocity and \(L\) is the length of string.

Substitute \(245\;{\rm{Hz}}\) for \({f_1}\) and \(63.5 \times {10^{ - 2}}\;{\rm{m}}\) for \(L\) in the equation (1).

\(\begin{array}{c}245\;{\rm{Hz}} = \frac{v}{{2 \times 63.5 \times {{10}^{ - 2}}\;{\rm{m}}}}\\v = \left( {245\;{\rm{Hz}}} \right) \times \left( {2 \times 63.5 \times {{10}^{ - 2}}\;{\rm{m}}} \right)\\v = 311.15\;{{\rm{m}} \mathord{\left/ {\vphantom {{\rm{m}} {\rm{s}}}} \right. \\}{\rm{s}}}\end{array}\)

Hence the speed of transverse waves is, \(311.15\;{{\rm{m}} \mathord{\left/ {\vphantom {{\rm{m}} {\rm{s}}}} \right. \\} {\rm{s}}}\).