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Chapter 2: Q23E (page 498)

A horizontal wire is stretched with a tension of 94.0 N, and the speed of transverse waves for the wire is 406 m/s. What must the amplitude of a traveling wave of frequency 69.0 Hz be for the average power carried by the wave to be 0.365 W?

Short Answer

Expert verified

The amplitude of a traveling wave of frequency 69.0 Hz be for the average power carried by the wave to be 0.365 W should be 0.0041m.

Step by step solution

01

Determination of the formula of Mechanical Waves

The average power carried by the wave is:

P=12渭A2蝇2v

Also,

localid="1664344211351" v=T渭渭=Tv2w=2蟺f

Substitute the values of渭 and w in formula for power we get

P=TA24蟺2f22v

02

Application of the formula of Mechanical Waves

A=Pv2蟺2f2TA=0.365脳40619.72脳4761脳94A=0.0401m

Therefore, the amplitude of a traveling wave of frequency 69.0 Hz be for the average power carried by the wave to be 0.365 W should be 0.0041m.

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