91影视

Formula is$\mathbf{I}\mathbf{=}\frac{{{\mathbf{vp}}^{\mathbf{2}}}_{\mathbf{max}}}{\mathbf{2}\mathbf{D}}$ isthe relation that describes the intensity of the sound wave in terms of the pressure amplitude

Substitute the values in the equation$\mathrm{I}=\frac{{{\mathrm{vp}}^2}_{\max }}{2\mathrm{D}}$we get,

$$\begin{gathered} \mathrm{I}=\frac{344脳{\left(6脳{10}^{-5}\right)}^2}{2脳1.42脳{10}^5} \\ =4.36脳{10}^{-12}\mathrm{W}/{\mathrm{m}}^2 \end{gathered}$$

The relation that describes the intensity level of a sound wave is$\mathrm{尾}=10\log \left(\frac{\mathrm{l}}{{\mathrm{l}}_0}\right)$ .Substitute the values in the above equation we get,

$$\begin{gathered} \mathrm{尾}=10\log \left(\frac{4.36脳{10}^{-12}\mathrm{W}/{\mathrm{m}}^2}{{10}^{-12}\mathrm{W}/{\mathrm{m}}^2}\right) \\ =6.4\mathrm{dB} \end{gathered}$$

Therefore, the intensity of the sound is 6.4dB

The equation is $\mathrm{A}=\frac{{\mathrm{P}}_{\max }}{\mathrm{kB}}$

We know that the Bulk modulus for the air is $\mathrm{B}=1.42脳{10}^5\mathrm{Pa}$and the pressure amplitude is $6脳{10}^{-5}\mathrm{Pa}$but in order to make use of equation (3) we need to determine k, where k can be represented as follows

$$\begin{gathered} \mathrm{k}=\frac{2\mathrm{蟺}}{\mathrm{位}} \\ \mathrm{位}=\frac{\mathrm{v}}{\mathrm{f}}=\frac{344}{400}=0.86\mathrm{m} \\ \mathrm{k}=\frac{2\mathrm{蟺}}{0.86\mathrm{m}}=7.3\mathrm{rad}/\mathrm{m} \\ \mathrm{A}=\frac{6脳{10}^{-5}\mathrm{Pa}}{7.3\mathrm{rad}/\mathrm{m}脳1.42脳{10}^5\mathrm{Pa}} \\ =5.8脳{10}^{-11}\mathrm{m} \end{gathered}$$

Therefore, the pressure amplitude is$5.8脳{10}^{-11}\mathrm{m}$