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Chapter 3: Q73P (page 578)

You propose a new temperature scale with temperatures given in 掳M. You define 0.0掳M to be the normal melting point of mercury and 100.0掳M to be the normal boiling point of mercury. (a) What is the normal boiling point of water in 掳M? (b) A temperature change of 10.0 掳M corresponds to how many 掳C?

Short Answer

Expert verified

a) The normal boiling point of water on 掳Mscale is 35.1掳M.

b) The temperature change of 掳Min C is 39.6掳C.

Step by step solution

01

Concept/Significance of

The mercury scale operates on the idea that when the temperature changes, the mercury expands and contracts, and this temperature change is recorded. This scale runs from -37掳Cto356掳C. This scale is based on mercury's characteristics.

02

Determination of the normal boiling point of water in °M

The temperature on the 掳Mscale is given by,

TM=13.96Tc+39掳

Here, TCis the temperature in 掳C.

Substitute values for normal boiling point in the above equation.

TM=13.96100掳C+39掳=35.1掳M

Thus, the normal boiling point of water n掳Mscale is 35.1掳M.

03

Determination of A temperature change of 10.0 °M corresponds to C°

Temperature change in 掳Mcorresponds to 掳Cis given by,

localid="1664874234375" 100掳M=396掳C

Substitute values in the above for 10掳M,

10掳M=39.6掳C

Thus, the temperature change 10掳Min掳Cis39.6掳C.

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Most popular questions from this chapter

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