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Nitrogen gas in an expandable container is cooled from 50C to 10Cwith the pressure held constant at 3104Pa. The total heat liberated by the gas is 2.5104J. Assume that the gas may be treated as ideal. Find (a) the number of moles of gas; (b) the change in internal energy of the gas; (c) the work done by the gas. (d) How much heat would be liberated by the gas for the same temperature change if the volume were constant?

Short Answer

Expert verified

a) The number of moles, n=21.5moles

b) The change in internal energy, U=-17.9KJ

c) The amount of work done by the gas, W=-7.1kJ

d) The amount of heat, Q=-17.9kJ

Step by step solution

01

The specific heat at constant volume:

The change in internal energy with regard to temperature is what is meant by the definition of the heat capacity at constant volume.

Heat energy at constant volume is given by

Q=nCpT

Q=nCp(Tb-Ta) 鈥.. (1)

Here, Q is the amount of heat, n is the number of moles, CP is the heat capacity at constant pressure, Tis the change in temperature.

02

(a) Calculate the number of moles using heat energy

Consider the given data as below.

The amount heat, Q=-2.5104J

Temperature, T2=283K

Temperature, T1=323K

T The heat capacity at constant volume, CV=20.76J/kg.K

The heat capacity at constant pressure, CP=29.07J/mol.K

Rearrange equation (1) for the number of moles as below.

n=QCPT=QCPT2-T1=-2.510429.07283-323=21.5moles

Hence, the number of moles, n=21.5moles

03

Calculate the change in internal energy                  

The change in internal energy is given by

U=nCVT

Here, is the heat capacity at constant volume.

Therefore,

U=nCVT=21.520.76283-323=-17.9KJ

The internal energy decreases as change is negative.

04

Calculate work using first law of thermodynamics

According to the first law of thermodynamics,

W=Q-U

Here, is the amount of work done by the gas, Q is the amount of heat, and Uis the change in internal energy.

As given

The amount of heat, Q=2.5104J

The change in internal energy. U=-17.9KJ

Work done is given by

W=-2.5104--17.9103=-7.1KJ

Since, the work done is negative, work is done on the gas.

05

Calculate heat when volume is constant

Now, since the volume is constant, the work done would be zero. According to the first law of thermodynamics

Q=W+U=0+U=-17.9KJ

The heat liberated at constant volume is less than at constant pressure.

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