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Perfectly rigid containers each hold n moles of ideal gas, one is being hydrogen (H2) and the other being neon (Ne). If it takes 300 J of heat to increase the temperature of the hydrogen by 2.50°C, by how many degrees will the same amount of heat raise the temperature of the neon?

Short Answer

Expert verified

The temperature of Neraised by 4.17C° due to 300J of the heat, and same amount of heat 300J raised the temperature of H2 by 2.5C°

Step by step solution

01

Data, Assumption and Equation

Given data;

Heat of the hydrogen Q = 300 J

Temperature difference of hydrogen ∆T=2.5°C=2.5K

Gas constant R = 3.14J/mol K

Assumption;

The number of moles of hydrogen and neon are same

Equation;

Formula of heat for hydrogen

Q=n×52R∆T .......... (1)

Formula of heat for neon

Q=n×32R∆T .......... (2)

02

Find the number of moles

From equation (1)

n=Q52¸éΔ°Õ=300J52×8.314J/molK×2.5K=5.77mol

03

Find temperature of neon gas

From equation (2)

ΔT=Qn×32R=300J5.77mol×32×8.314J/molK=4.17K=4.17C∘

Hence, the temperature of Neraised by4.17C° due to 300J of the heat, and same amount of heat 300J raised the temperature of H2 by2.5C°

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