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Chapter 3: Q38E (page 612)

Perfectly rigid containers each hold n moles of ideal gas, one is being hydrogen (H2) and the other being neon (Ne). If it takes 300 J of heat to increase the temperature of the hydrogen by 2.50掳C, by how many degrees will the same amount of heat raise the temperature of the neon?

Short Answer

Expert verified

The temperature of Neraised by 4.17C掳 due to 300J of the heat, and same amount of heat 300J raised the temperature of H2 by 2.5C掳

Step by step solution

01

Data, Assumption and Equation

Given data;

Heat of the hydrogen Q = 300 J

Temperature difference of hydrogen 鈭�T=2.5掳C=2.5K

Gas constant R = 3.14J/mol K

Assumption;

The number of moles of hydrogen and neon are same

Equation;

Formula of heat for hydrogen

Q=n脳52R鈭�T .......... (1)

Formula of heat for neon

Q=n脳32R鈭�T .......... (2)

02

Find the number of moles

From equation (1)

n=Q52搁螖罢=300J52脳8.314J/molK脳2.5K=5.77mol

03

Find temperature of neon gas

From equation (2)

螖T=Qn脳32R=300J5.77mol脳32脳8.314J/molK=4.17K=4.17C鈭�

Hence, the temperature of Neraised by4.17C掳 due to 300J of the heat, and same amount of heat 300J raised the temperature of H2 by2.5C掳

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