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A blacksmith cools a 1.20 kg chunk of iron, initially at 650C,by trickling 15Cwater over it. All of the water boils away, and the iron ends up at 120C. How much water did the blacksmith trickle over the iron?

Short Answer

Expert verified

The 0.114 kg water did the blacksmith trickle over the iron.

Step by step solution

01

Definition of heat

The term heat may be defined as the energy transfer from one body to another body as a result change in temperature.

02

Determine the amount of water

Consider the given data as below.

Mass of iron, m1=1.20kg

The heat capacity, Cl=0.47103J/kgC

Initial temperature, T1=650C

Water temperature, T'=15C

Boiling temperature, T'=100C

Final temperature, T2=120C

Heat capacity of water, Cw=4190J/kgC

Heat capacity of iron, localid="1664337917208" Cl=0.47103J/kgC

Due to change in system QW=-QironmwCwTw+mwLv=-mlclTl

mw=-mlClTlCwTw+Lw=-mlClT2-T1CwT'-T+Lw

Substitute known values in the above equation.

mw=1.20.47103120-650C4.19103100-15C+2256103=0.114kg

Hence, the 0.114kg water did the blacksmith trickle over the iron.

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