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A liquid is irregularly stirred in a well-insulated container and thereby undergoes a rise in temperature. Regard the liquid as the system. Has heat been transferred? How can you tell? Has work been done? How can you tell? Why is it important that the stirring is irregular? What is the sign of ∆U? How can you tell?

Short Answer

Expert verified

The internal energy of the liquid is irregularly stirred in a well-insulated container increases and it corresponds to an increase in the temperature of the liquid.

∆U>0

Step by step solution

01

Step 1:

According to the first law of thermodynamics

∆U=O~-W

Since the container is well insulated, no heat has been transferred, and Q=0. Work has been done on the liquid, so W < 0. The force exerted during the stirring moves the liquid in the direction of force so positive work is done by string force. Irregular stirring increases the force applied to the liquid and thereby increases the work done on the liquid.

02

Step 2:

∆U=--Wand W<0

Hence, the internal energy increases and it corresponds to an increase in the temperature of the liquid

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