/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q34E Jan first uses a Michelson inter... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 5: Q34E (page 1182)

Jan first uses a Michelson interferometer with the 606-nm light from a krypton-86 lamp. He displaces the movable mirror away from him, counting 818 fringes moving across a line in his field of view. Then Linda replaces the krypton lamp with filtered 502-nm light from a helium lamp and displaces the movable mirror toward her. She also counts 818 fringes, but they move across the line in her field of view opposite to the direction they moved for Jan. Assume that both Jan and Linda counted to 818 correctly. (a) What distance did each person move the mirror? (b) What is the resultant displacement of the mirror?

Short Answer

Expert verified

a) The Distance Jan has to move the mirror is 0.248mm.

The Distance Linda has to move the mirror is 0.205mm.

b) The resultant displacement of the mirror is 0.043mm.

Step by step solution

01

Michelson’s Interferometer and Jan’s Experiment.

We are givenm1=m2=818 and位1=606nm&位2=502nm .

We know that the distance by the mirror is given by

y=m位2

For the first experiment, Jan鈥檚 Experiment,

y1=m1位12

Substitute the given values

y1=818脳606脳10-92y1=2.48脳10-4

Hence, the Distance Jan has to move the mirror is 0.248mm.

02

Michelson’s Interferometer and Linda’s Experiment.

For the second experiment, Linda鈥檚 experiment,

y2=m2位22

Substitute the values,

y2=818脳502脳10-92y2=2.05脳10-4

Hence, the Distance Linda has to move the mirror is 0.205mm.

03

Displacement of mirror.

(b) Now we find resultant displacement of the mirror, which is given by

鈭�y=y1-y2鈭�y=2.48脳10-4-2.05脳10-4鈭�y=0.43脳10-4m

Hence the displacement of the mirror is 0.043mm.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Ordinary Glasses: Ordinary glasses are worn in front of the eye and usually 2.0 cm in front of the eyeball. Suppose that the person in previous exercise prefers ordinary glasses to contact lenses. What focal length lenses are needed to correct his vision, and what is their power in diopters?

Sometimes when looking at a window, you see two reflected images slightly displaced from each other. What causes this?

When a camera is focused, the lens is moved away from or toward the digital image sensor. If you take a picture of your friend, who is standing 3.90 m from the lens, using a camera with a lens with an 85-mm focal length, how far from the sensor is the lens? Will the whole image of your friend, who is 175 cm tall, fit on a sensor that is 24 mm * 36 mm?

The laws of optics also apply to electromagnetic waves invisible to the eye. A satellite TV dish is used to detect radio waves coming from orbiting satellites. Why is a curved reflecting surface (a 鈥渄ish鈥�) used? The dish is always concave, never convex; why? The actual radio receiver is placed on an arm and suspended in front of the dish. How far in front of the dish should it be placed?

The cornea behaves as a thin lens of focal length approximately1.8 cm, although this varies a bit. The material of which it is made has an index of refraction of 1.38 cm , and its front surface is convex, with a radius of curvature of 5.0 mm. (a) If this focal length is in air, what is the radius of curvature of the back side of the cornea? (b) The closest distance at which a typical person can focus on an object (called the near point) is about 25cm, although this varies considerably with age. Where would the cornea focus the image of an 8.00 mm -tall object at the near point? (c) What is the height of the image in part (b)? Is this image real or virtual? Is it erect or inverted? (Note:The results obtained here are not strictly accurate because, on one side, the cornea has a fluid with a refractive index different from that of air.)
See all solutions

Recommended explanations on Physics Textbooks

Classical Mechanics

Read Explanation

Modern Physics

Read Explanation

Magnetism

Read Explanation

Thermodynamics

Read Explanation

Electromagnetism

Read Explanation

Linear Momentum

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.