/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q27E Question:聽Visible light passes ... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 5: Q27E (page 1213)

Question:Visible light passes through a diffraction grating that has 900 slits / cm, and the interference pattern is observed on a screen that is2.50 mfrom the grating. (a) Is the angular position of the first-order spectrum small enough forsin胃鈮�胃to be a good approximation? (b) In the first-order spectrum, the maxima for two different wavelengths are separated on the screen by 3.00 mm. What is the difference in these wavelengths?

Short Answer

Expert verified
  1. Yes, the angular position of the first-order spectrum small enough.
  2. The difference in these wavelengths is 13.3 mm

Step by step solution

01

Determine if the angular position of the first-order spectrum is small enough

The angular position is given by

The first-order spectrum is for m = 1

So, the first-order angular position in radians is

Therefore, the angular position of the first-order spectrum is small enough for 胃鈮�胃to be a good approximation.

02

Determine the difference between the two wavelengths

The position of the bright fringes on the screen

So, the position of the first-order spectrum of the first and second wavelengths are

Now, we know that both the bright fringes for m = 1, thus subtract the positions of fringes

Substitute the values

Thus, the difference between the two wavelengths is 13.3 mm.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A pencil that is 9cm long is held perpendicular to the surface of a plane mirror with the tip of the pencil lead 12cm from the mirror surface and the end of the eraser 21cm from the mirror surface. What is the length of the image of the pencil that is formed by the mirror? Which end of the image is closer to the mirror surface: the tip of the lead or the end of the eraser?

For the situation shown in Fig. 34.3, is the image distance s鈥� positive or negative? Is the image real or virtual? Explain your answers

Huygens鈥檚 principle also applies to sound waves. During the day, the temperature of the atmosphere decreases with increasing altitude above the ground. But at night, when the ground cools, there is a layer of air just above the surface in which the temperature increaseswith altitude. Use this to explain why sound waves from distant sources can be heard more clearly at night than in the daytime. (Hint:The speed of sound increases with increasing temperature. Use the ideas displayed in Fig. 33.36 for light.)

You may have noticed a small convex mirror next to your bank鈥檚 ATM. Why is this mirror convex, as opposed to flat or concave? What considerations determine its radius of curvature?

34.16 A tank whose bottom is a mirror is filled with water to a depth of 20.0cm. A small fish floats motionless 7.0cm under the surface of the water. (a) What is the apparent depth of the fish when viewed at normal incidence? (b) What is the apparent depth of the image of the fish when viewed at normal incidence?
See all solutions

Recommended explanations on Physics Textbooks

Force

Read Explanation

Translational Dynamics

Read Explanation

Magnetism

Read Explanation

Astrophysics

Read Explanation

Further Mechanics and Thermal Physics

Read Explanation

Fields in Physics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.