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Chapter 5: Q2DQ (page 1151)

For the situation shown in Fig. 34.3, is the image distance s鈥� positive or negative? Is the image real or virtual? Explain your answers

Short Answer

Expert verified

The image will be virtual and erect

Step by step solution

01

Images formed by the Plane mirror

Images formed by the plane mirror are virtual, upright, and left-right reversed, it is atthe same distance from the mirror as the object鈥檚 distance and the same size as that of the object.

02

Explanation of the answer

The image is on the side of the interface where the light comes from, hence the image is virtual and negative.

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Most popular questions from this chapter

According to the discussion in Section 34.2, light rays are reversible. Are the formulas in the table in this chapter鈥檚 Summary still valid if object and image are interchanged? What does reversibility imply with respect to the forms of the various formulas?

Monochromatic light is directed at normal incidence on a thin film. There is destructive interference for the reflected light, so the intensity of the reflected light is very low. What happened to the energy of the incident light?

The two sourcesS1andS2shown in Fig. 35.3 emit waves of the same wavelength 位and are in phase with each other. Suppose S1is a weaker source, so that the waves emitted by S1have half the amplitude of the waves emitted by S2. How would this affect the positions of the antipodallines and nodal lines? Would there be total reinforcement at points on the antipodal curves? Would there be total cancellation at points on the nodal curves? Explain your answers.

If we shine white light on an air wedge like that shown in Fig. 35.12, the colours that are weak in the light reflected from any point along the wedge are strong in the light transmitted through the wedge. Explain why this should be so.

Ordinary photographic film reverses black and white, in the sense that the most brightly illuminated areas become blackest upon development (hence the term negative). Suppose a hologram negative is viewed directly, without making a positive transparency. How will the resulting images differ from those obtained with the positive? Explain.
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